TRANSFORM Count(ccc.num)
SELECT ccc.name,address, Count(ccc.num) AS 合计
FROM ccc
GROUP BY ccc.name,address
PIVOT ccc.class;这里面好像 TRANSFORM,PIVOT,sql都不认,是不是有其他语句可以替代?
谢谢!
SELECT ccc.name,address, Count(ccc.num) AS 合计
FROM ccc
GROUP BY ccc.name,address
PIVOT ccc.class;这里面好像 TRANSFORM,PIVOT,sql都不认,是不是有其他语句可以替代?
谢谢!
以下为实例代码
declare @sql varchar(8000)set @sql = 'select name,' select @sql = @sql + 'sum(case subject when '''+subject+''' then source else 0 end) as '''+subject+''',' from (select distinct subject from test) as a select @sql = left(@sql,len(@sql)-1) + ' from test group by name'exec(@sql)
我还想在前面加一列合计,就是该学生的成绩合计,怎样实现?
最好可以把列排序!怎样实现?
谢谢
[Source] [numeric](18, 0) NULL
) ON [PRIMARY]
GO
INSERT INTO [test] ([name],[subject],[Source]) values (N'张三',N'语文',60)
INSERT INTO [test] ([name],[subject],[Source]) values (N'李四',N'数学',70)
INSERT INTO [test] ([name],[subject],[Source]) values (N'王五',N'英语',80)
INSERT INTO [test] ([name],[subject],[Source]) values (N'王五',N'数学',75)
INSERT INTO [test] ([name],[subject],[Source]) values (N'王五',N'语文',57)
INSERT INTO [test] ([name],[subject],[Source]) values (N'李四',N'语文',80)
INSERT INTO [test] ([name],[subject],[Source]) values (N'张三',N'英语',100)
Go--用于:交叉表的列数是确定的select name,sum(case subject when '数学' then source else 0 end) as '数学', sum(case subject when '英语' then source else 0 end) as '英语', sum(case subject when '语文' then source else 0 end) as '语文' from test group by name --用于:交叉表的列数是不确定的declare @sql varchar(8000)set @sql = 'select name,' select @sql = @sql + 'sum(case subject when ''+subject+'' then source else 0 end) as ''+subject+'',' from (select distinct subject from test) as a select @sql = left(@sql,len(@sql)-1) + ' from test group by name'exec(@sql)
set @sql = 'select name, sum(source) as 总分'select @sql = @sql + 'sum(case subject when ''+subject+''
then source else 0 end) as ''+subject+'','
from (select distinct subject from test) as aselect @sql = left(@sql,len(@sql)-1) + ' from test group by name'exec(@sql)