select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) 服务器: 消息 170,级别 15,状态 1,行 2
第 2 行: ',' 附近有语法错误。这条语句不能执行,大概是我的where语句不能用两个字段。
我想知道应该怎样实现这条语句,该语句的意思是 “删除表中重复的行”?
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) 服务器: 消息 170,级别 15,状态 1,行 2
第 2 行: ',' 附近有语法错误。这条语句不能执行,大概是我的where语句不能用两个字段。
我想知道应该怎样实现这条语句,该语句的意思是 “删除表中重复的行”?
convert(varchar(10),a.peopleID)+convert(varchar(10),a.seq)
in (select convert(varchar(10),a.peopleID)+convert(varchar(10),a.seq)
from vitae group by convert(varchar(10),a.peopleID)+convert(varchar(10),a.seq)
having count(*) > 1) )
这条语句就可以把重复的去掉,只留一条信息
a b c d
1 2 3 4
1 5 3 5
1 2 7 9
以a、b为唯一字段,第一条和第三条的a、b完全相同,所以,需要删除第一条记录1 2 3 4 或者第三条记录1 2 7 9
即如下结果:
a b c d
1 2 3 4
1 5 3 5
或
a b c d
1 5 3 5
1 2 7 9请问各位大侠这种sql语句怎么写
CREATE TABLE Tb1(id int, [a] varchar(255), [b] varchar(255), [c] varchar(255), [d] varchar(255))
INSERT Tb1(id, [a], [b], [c], [d])
SELECT 1, '1','2','3','4'
UNION ALL SELECT 2, '1','5','3','5'
UNION ALL SELECT 3, '1','2','7','9'
UNION ALL SELECT 4, '1','4','7','6'delete Tb1 where [id] not in (select max([id]) from Tb1 group by a,b )
select * from tb1
drop table tb1如果要同时删除第一和第三行
即如下结果:
a b c d
1 5 3 5语句如下:delete m from tb t
inner join
(
select a ,b
from tb
group by a , b
having count(*)>1
)n
on m.a = n.a and m.b = n.b
或
delete * from tb as m,
(
select a ,b
from tb
group by a , b
having count(*)>1
)n
where m.a = n.a and m.b = n.b
1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断
select * from people
where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录
delete from people
where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)
and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)3、查找表中多余的重复记录(多个字段)
select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录
delete from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录
select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)比方说在A表中存在一个字段“name”,而且不同记录之间的“name”值有可能会相同,
现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;
Select Name,Count(*) From A Group By Name Having Count(*) > 1
我看过你发的那个内容,不知道你运行过没有,1、2都可以运行但是3、4、5都通不过我想问的就是这个问题:
1、为什么where后面带两个字段的sql语句会出错?
2、我应当怎样解决?
为什么有convert(varchar(10),a.peopleID)+convert(varchar(10),a.seq)?是什么意思?
当然如果你的peopleID和seq存在着
peopleID seq
1001 1
100 11
这样的情况,那还是会有错误的,不过可以类似用'$'之类的比较特殊的符号夹中间
convert(varchar(10),a.peopleID)+'$'+convert(varchar(10),a.seq)