我用sql2005,表(table1)如下id zhuti riqi
1 大家好 2012-1-3
2 大 2012-1-5
3 家 2012-1-5
4 好 2012-1-10
5 欢迎 2012-1-10
6 光临 2012-1-10我想要实现的功能是,一段sql语句实现下列输出:2012-1-10
光临
欢迎
好
2012-1-5
家
大
2012-1-3
大家好如何实现?请教大家了,谢谢!
1 大家好 2012-1-3
2 大 2012-1-5
3 家 2012-1-5
4 好 2012-1-10
5 欢迎 2012-1-10
6 光临 2012-1-10我想要实现的功能是,一段sql语句实现下列输出:2012-1-10
光临
欢迎
好
2012-1-5
家
大
2012-1-3
大家好如何实现?请教大家了,谢谢!
select max(id) id,riqi from table1 group by riqi
),t2 as (
select id,zhuti from table1
),t3 as (
select id,riqi as a,1 id2 from t1
union all
select id,zhuti,2 id2 from t2
)
select a from t3 order by id desc,id2
(id int not null,
zhuti varchar(10),
riqi datetime)insert into tb#(id, zhuti ,riqi)
select 1, '大家好','2012-1-3'
union all select 2,'大',' 2012-1-5'
union all select 3 , '家 ','2012-1-5'
union all select 4 , '好 ','2012-1-10'
union all select 5 , '欢迎','2012-1-10'
union all select 6 , '光临 ','2012-1-10'select * from tb#select zhuti
from(
select distinct cast(year(riqi) as varchar(4))+' - '+ cast(month(riqi) as varchar(2))+' - '+ cast(day(riqi) as varchar(2)) as zhuti,riqi from tb#
union all
select zhuti,riqi from tb# ) as a
order by riqi desc,zhuti--结果
/*
2012 - 1 - 10
光临
好
欢迎
2012 - 1 - 5
大
家
2012 - 1 - 3
大家好
*/