必如有一个表pactinfo结构如下:
ID pactname
1 正常
2 中国
3 做饭
4 加发
我现在在想要查询pactname的第一个字母是 Z 的,就可以把“正常”“中国”“做饭”查询出来,sql怎么写?
谢谢!!!
ID pactname
1 正常
2 中国
3 做饭
4 加发
我现在在想要查询pactname的第一个字母是 Z 的,就可以把“正常”“中国”“做饭”查询出来,sql怎么写?
谢谢!!!
if object_id('[pactinfo]') is not null drop table [pactinfo]
go
create table [pactinfo]([ID] int,[pactname] varchar(4))
insert [pactinfo]
select 1,'正常' union all
select 2,'中国' union all
select 3,'做饭' union all
select 4,'加发'
---引用前辈们的一个函数---
create function f_GetPy(@str nvarchar(4000))
returns nvarchar(4000)
as
begin
declare @strlen int,@re nvarchar(4000)
declare @t table(chr nchar(1) collate Chinese_PRC_CI_AS,letter nchar(1))
insert into @t(chr,letter)
select '吖 ', 'A ' union all select '八 ', 'B ' union all
select '嚓 ', 'C ' union all select '咑 ', 'D ' union all
select '妸 ', 'E ' union all select '发 ', 'F ' union all
select '旮 ', 'G ' union all select '铪 ', 'H ' union all
select '丌 ', 'J ' union all select '咔 ', 'K ' union all
select '垃 ', 'L ' union all select '嘸 ', 'M ' union all
select '拏 ', 'N ' union all select '噢 ', 'O ' union all
select '妑 ', 'P ' union all select '七 ', 'Q ' union all
select '呥 ', 'R ' union all select '仨 ', 'S ' union all
select '他 ', 'T ' union all select '屲 ', 'W ' union all
select '夕 ', 'X ' union all select '丫 ', 'Y ' union all
select '帀 ', 'Z '
select @strlen=len(@str),@re= ' '
while @strlen> 0
begin
select top 1 @re=letter+@re,@strlen=@strlen-1
from @t a where chr <=substring(@str,@strlen,1)
order by chr desc
if @@rowcount=0
select @re=substring(@str,@strlen,1)+@re,@strlen=@strlen-1
end
return(@re)
end
---查询---
select
*
from
[pactinfo]
where
left(dbo.f_GetPy(pactname),1)='Z'---结果---
ID pactname
----------- --------
1 正常
2 中国
3 做饭(所影响的行数为 3 行)
--1. 按拼音排序
DECLARE @t TABLE(col varchar(2))
INSERT @t SELECT '中'
UNION ALL SELECT '国'
UNION ALL SELECT '人'SELECT * FROM @t ORDER BY col COLLATE Chinese_PRC_CS_AS_KS_WS
/*--结果
col
----
国
人
中
--*/
GO
/*==========================================*/
--2. 汉字首字母查询处理用户定义函数
CREATE FUNCTION f_GetPY(@str nvarchar(4000))
RETURNS nvarchar(4000)
AS
BEGIN
DECLARE @py TABLE(
ch char(1),
hz1 nchar(1) COLLATE Chinese_PRC_CS_AS_KS_WS,
hz2 nchar(1) COLLATE Chinese_PRC_CS_AS_KS_WS)
INSERT @py SELECT 'A',N'吖',N'鏊'
UNION ALL SELECT 'B',N'八',N'簿'
UNION ALL SELECT 'C',N'嚓',N'错'
UNION ALL SELECT 'D',N'哒',N'跺'
UNION ALL SELECT 'E',N'屙',N'贰'
UNION ALL SELECT 'F',N'发',N'馥'
UNION ALL SELECT 'G',N'旮',N'过'
UNION ALL SELECT 'H',N'铪',N'蠖'
UNION ALL SELECT 'J',N'丌',N'竣'
UNION ALL SELECT 'K',N'咔',N'廓'
UNION ALL SELECT 'L',N'垃',N'雒'
UNION ALL SELECT 'M',N'妈',N'穆'
UNION ALL SELECT 'N',N'拿',N'糯'
UNION ALL SELECT 'O',N'噢',N'沤'
UNION ALL SELECT 'P',N'趴',N'曝'
UNION ALL SELECT 'Q',N'七',N'群'
UNION ALL SELECT 'R',N'蚺',N'箬'
UNION ALL SELECT 'S',N'仨',N'锁'
UNION ALL SELECT 'T',N'他',N'箨'
UNION ALL SELECT 'W',N'哇',N'鋈'
UNION ALL SELECT 'X',N'夕',N'蕈'
UNION ALL SELECT 'Y',N'丫',N'蕴'
UNION ALL SELECT 'Z',N'匝',N'做'
DECLARE @i int
SET @i=PATINDEX('%[吖-做]%' COLLATE Chinese_PRC_CS_AS_KS_WS,@str)
WHILE @i>0
SELECT @str=REPLACE(@str,SUBSTRING(@str,@i,1),ch)
,@i=PATINDEX('%[吖-做]%' COLLATE Chinese_PRC_CS_AS_KS_WS,@str)
FROM @py
WHERE SUBSTRING(@str,@i,1) BETWEEN hz1 AND hz2
RETURN(@str)
END
GO
查询时对应拼音编码查询
编码
if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[fGetPy]') and xtype in (N'FN', N'IF', N'TF'))
drop function [dbo].[fGetPy]
GO
--创建取拼音函数
create function fGetPy(@Str varchar(500)='')
returns varchar(500)
as
begin
declare @strlen int,@return varchar(500),@ii int
declare @n int,@c char(1),@chn nchar(1)
select @strlen=len(@str),@return='',@ii=0
set @ii=0
while @ii<@strlen
begin
select @ii=@ii+1,@n=63,@chn=substring(@str,@ii,1)
if @chn>'z'
select @n = @n +1
,@c = case chn when @chn then char(@n) else @c end
from(
select top 27 * from (
select chn = '吖'
union all select '八'
union all select '嚓'
union all select '咑'
union all select '妸'
union all select '发'
union all select '旮'
union all select '铪'
union all select '丌' --because have no 'i'
union all select '丌'
union all select '咔'
union all select '垃'
union all select '嘸'
union all select '拏'
union all select '噢'
union all select '妑'
union all select '七'
union all select '呥'
union all select '仨'
union all select '他'
union all select '屲' --no 'u'
union all select '屲' --no 'v'
union all select '屲'
union all select '夕'
union all select '丫'
union all select '帀'
union all select @chn) as a
order by chn COLLATE Chinese_PRC_CI_AS
) as b
else set @c='a'
set @return=@return+@c
end
return(@return)
end
go
--测试
select dbo.fgetpy('东莞市') as 东莞市,dbo.fgetpy('ab中c国人') as 中国人
--删除拼音函数
drop function fgetpy