在SQL中分类查询并且重新编号

Question

在SQL中如何才能查出类似这样的结果，谢谢
OneClass
No. Name Status
1 Officials Non-statutory
2 Development Non-statutory
TwoClass
No. Name Status
1 Board Statutory
2 Committee Non-statutory
3 Honours Non-statutory
4 ICAC Complaints Committee Non-statutory
ThreeClass
No. Name Status
1 ICAC Non-statutory
2 Citizens Non-statutory
3 Corruption statutory

Answer 1

partition by ... order by ...
不过格式和你这个有区别，你这个格式太扯

Answer 2

3個表用 union all --連接

Answer 3

--1.
select row_number()over(order by name desc) as [No.],name,status from tb
--2.
select row_number()over(order by name) as [No.],name,status from tb
--3.
select row_number()over(order by status) as [No.],name,status from tb

Answer 4

舉個例子，猜一下use Tempdb
go
--> --> 
 
if not object_id(N'Tempdb..#T1') is null
drop table #T1
Go
Create table #T1([No] int,[Name] nvarchar(11),[Status] nvarchar(13))
Insert #T1
select 1,N'Officials',N'Non-statutory' union all
select 2,N'Development',N'Non-statutory'
Goif not object_id(N'Tempdb..#T2') is null
drop table #T2
Go
Create table #T2([No] int,[Name] nvarchar(38),[Status] nvarchar(13))
Insert #T2
select 1,N'Board',N'Statutory' union all
select 2,N'Committee',N'Non-statutory' union all
select 3,N'Honours',N'Non-statutory' union all
select 4,N'ICAC ComplaintsCommittee','Non-statutory'
Go
use Tempdb
go
--> --> 
 
if not object_id(N'Tempdb..#T3') is null
drop table #T3
Go
Create table #T3([No] int,[Name] nvarchar(10),[Status] nvarchar(13))
Insert #T3
select 1,N'ICAC',N'Non-statutory' union all
select 2,N'Citizens',N'Non-statutory' union all
select 3,N'Corruption',N'statutor'
Go
;WITH a
AS
(
Select *,ParentID=0 from #T1
UNION ALL
Select *,ParentID=1 from #T2
UNION ALL
Select *,ParentID=2 from #T3
),a2
AS
(
SELECT *,ord=CAST(RIGHT(100+[No],2) AS NVARCHAR(200)) FROM a WHERE ParentID=0
UNION ALL
SELECT a.*,ord=CAST(b.ord+RIGHT(100+a.[No],2) AS NVARCHAR(200)) FROM a2 AS b INNER JOIN a ON b.[No]=a.ParentID AND b.ParentID=0
)
SELECT NO=ROW_NUMBER()OVER(ORDER BY ord),[Name],[Status],ParentID
FROM a2 
OPTION(MAXRECURSION 0)
/*
NO Name Status ParentID
1 Officials Non-statutory 0
2 Board Statutory 1
3 Committee Non-statutory 1
4 Honours Non-statutory 1
5 ICAC ComplaintsCommittee Non-statutory 1
6 Development Non-statutory 0
7 ICAC Non-statutory 2
8 Citizens Non-statutory 2
9 Corruption statutor 2
*/

Answer 5

Table中有这几个字段：Class  Name  Status

Answer 6

Table中有这几个字段：Class Name Status，现在是就是想要根据class去分类显示为以下结构：
OneClass
No. Name  Status
1 Officials Non-statutory
2 Development Non-statutory
TwoClass
No. Name  Status
1 Board  Statutory
2 Committee Non-statutory
3 Honours  Non-statutory
4 ICAC Complaints Committee Non-statutory
ThreeClass
No. Name  Status
1 ICAC  Non-statutory
2 Citizens Non-statutory
3 Corruption statutory

Answer 7

?排序規則是;WITH a
AS
(
Select *,ParentID=0 from #T1
UNION ALL
Select *,ParentID=1 from #T2
UNION ALL
Select *,ParentID=2 from #T3
),a2
AS
(
SELECT *,ord=CAST(RIGHT(100+[No],2) AS NVARCHAR(200)) FROM a WHERE ParentID=0
UNION ALL
SELECT a.*,ord=CAST(b.ord+RIGHT(100+a.[No],2) AS NVARCHAR(200)) FROM a2 AS b INNER JOIN a ON b.[No]=a.ParentID AND b.ParentID=0
)
SELECT NO=ROW_NUMBER()OVER(ORDER BY ParentID,ord),[Name],[Status],ParentID
FROM a2 
OPTION(MAXRECURSION 0)
/*NO Name Status ParentID
1 Officials Non-statutory 0
2 Development Non-statutory 0
3 Board Statutory 1
4 Committee Non-statutory 1
5 Honours Non-statutory 1
6 ICAC ComplaintsCommittee Non-statutory 1
7 ICAC Non-statutory 2
8 Citizens Non-statutory 2
9 Corruption statutor 2
*/