SQL 如下
表 Tb 两列 ID Name
1 A
1 B
1 C
1 D
1 E
2 F
2 G
2 H
2 I
3 J
3 K
3 L
4 M
5 N
5 O需要排列的结果是
表 TC ID Name1 Name2 Name3
1 A B C
1 D E null
2 F G H
2 I null null
3 J K L
4 M null null
5 N O null
其中ID中的行数是不固定的,有高手支个招么?非常谢谢!
表 Tb 两列 ID Name
1 A
1 B
1 C
1 D
1 E
2 F
2 G
2 H
2 I
3 J
3 K
3 L
4 M
5 N
5 O需要排列的结果是
表 TC ID Name1 Name2 Name3
1 A B C
1 D E null
2 F G H
2 I null null
3 J K L
4 M null null
5 N O null
其中ID中的行数是不固定的,有高手支个招么?非常谢谢!
/*
标题:普通行列转换(version 2.0)
作者:爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开)
时间:2008-03-09
地点:广东深圳
说明:普通行列转换(version 1.0)仅针对sql server 2000提供静态和动态写法,version 2.0增加sql server 2005的有关写法。问题:假设有张学生成绩表(tb)如下:
姓名 课程 分数
张三 语文 74
张三 数学 83
张三 物理 93
李四 语文 74
李四 数学 84
李四 物理 94
想变成(得到如下结果):
姓名 语文 数学 物理
---- ---- ---- ----
李四 74 84 94
张三 74 83 93
-------------------
*/create table tb(姓名 varchar(10) , 课程 varchar(10) , 分数 int)
insert into tb values('张三' , '语文' , 74)
insert into tb values('张三' , '数学' , 83)
insert into tb values('张三' , '物理' , 93)
insert into tb values('李四' , '语文' , 74)
insert into tb values('李四' , '数学' , 84)
insert into tb values('李四' , '物理' , 94)
go--SQL SERVER 2000 静态SQL,指课程只有语文、数学、物理这三门课程。(以下同)
select 姓名 as 姓名 ,
max(case 课程 when '语文' then 分数 else 0 end) 语文,
max(case 课程 when '数学' then 分数 else 0 end) 数学,
max(case 课程 when '物理' then 分数 else 0 end) 物理
from tb
group by 姓名--SQL SERVER 2000 动态SQL,指课程不止语文、数学、物理这三门课程。(以下同)
declare @sql varchar(8000)
set @sql = 'select 姓名 '
select @sql = @sql + ' , max(case 课程 when ''' + 课程 + ''' then 分数 else 0 end) [' + 课程 + ']'
from (select distinct 课程 from tb) as a
set @sql = @sql + ' from tb group by 姓名'
exec(@sql) --SQL SERVER 2005 静态SQL。
select * from (select * from tb) a pivot (max(分数) for 课程 in (语文,数学,物理)) b--SQL SERVER 2005 动态SQL。
declare @sql varchar(8000)
select @sql = isnull(@sql + '],[' , '') + 课程 from tb group by 课程
set @sql = '[' + @sql + ']'
exec ('select * from (select * from tb) a pivot (max(分数) for 课程 in (' + @sql + ')) b')---------------------------------
需要根据ID来每3个分一组,不够3个的用null补足,根据组ID来做行列转换条件。
create table #TB
(
id int,
[name] varchar(50)
)
insert into #TB
select 1,'A' union all
select 1,'B' union all
select 1,'C' union all
select 1,'D' union all
select 1,'E' union all
select 2,'F' union all
select 2,'G' union all
select 2,'H' union all
select 2,'I' union all
select 3,'J' union all
select 3,'K' union all
select 3,'L' union all
select 4,'M' union all
select 5,'N' union all
select 5,'O'
create table #TC
(
GroupID int,
ID int,
[name] varchar(50)
) declare @i int
declare @ID int
set @i=0
Declare iCursor Cursor For
Select Distinct ID from #TB
Open iCursor
Fetch next from iCursor into @ID
While @@Fetch_Status=0
Begin
Insert Into #TC
select ((row-1)/3)+@i,ID,[Name] from (select row_number() over (partition by ID order by id) as row,* from #TB) B
where ID=@ID
select @i=max(GroupID)+1 from #TC
Print @i
Fetch Next from iCursor into @ID
End
Close iCursor
Deallocate iCursorselect GroupID,id,
max(case row%3 when 1 then [name] else null end) as name1,
max(case row%3 when 2 then [name] else null end) as name2,
max(case row%3 when 0 then [name] else null end) as name3
from (select row_number() over (partition by ID order by id) as row,* from #TC) b
group by GroupID,id
GroupID id name1 name2 name3
0 1 A B C
1 1 D E NULL
2 2 F G H
3 2 I NULL NULL
4 3 J K L
5 4 M NULL NULL
6 5 N O NULL
证明是正确的很可惜呵呵,我们数据库是SQL2000,不识别row_number()
我在用这个函数的替代算法
select row_number() over (partition by ID order by id) as row,* from #TC
INSERT @TB
SELECT 1, 'A' UNION ALL
SELECT 1, 'B' UNION ALL
SELECT 1, 'C' UNION ALL
SELECT 1, 'D' UNION ALL
SELECT 1, 'E' UNION ALL
SELECT 2, 'F' UNION ALL
SELECT 2, 'G' UNION ALL
SELECT 2, 'H' UNION ALL
SELECT 2, 'I' UNION ALL
SELECT 3, 'J' UNION ALL
SELECT 3, 'K' UNION ALL
SELECT 3, 'L' UNION ALL
SELECT 4, 'M' UNION ALL
SELECT 5, 'N' UNION ALL
SELECT 5, 'O'SELECT *,SEQ=IDENTITY(int,1,1) INTO # FROM @TB SELECT ID,
MAX(CASE WHEN (SEQ-1)%3=0 THEN NAME END) AS NAME1,
MAX(CASE WHEN (SEQ-1)%3=1 THEN NAME END) AS NAME2,
MAX(CASE WHEN (SEQ-1)%3=2 THEN NAME END) AS NAME3
FROM (SELECT ID,NAME,SEQ=SEQ-(SELECT COUNT(*) FROM # WHERE ID<TA.ID) FROM # TA) TB
GROUP BY ID,(SEQ-1)/3
ORDER BY IDDROP TABLE #
/*
ID NAME1 NAME2 NAME3
----------- ----- ----- -----
1 A B C
1 D E NULL
2 F G H
2 I NULL NULL
3 J K L
4 M NULL NULL
5 N O NULL
*/
----------- ----- ----- -----
1 D E C
2 I G H
3 J K L
4 M NULL NULL
5 N O NULL
厉害。
是对你说的,看错人了。
DECLARE @TB TABLE([ID] INT, [Name] VARCHAR(1))
INSERT @TB
SELECT 1, 'A' UNION ALL
SELECT 1, 'B' UNION ALL
SELECT 1, 'C' UNION ALL
SELECT 1, 'D' UNION ALL
SELECT 1, 'E' UNION ALL
SELECT 2, 'F' UNION ALL
SELECT 2, 'G' UNION ALL
SELECT 2, 'H' UNION ALL
SELECT 2, 'I' UNION ALL
SELECT 3, 'J' UNION ALL
SELECT 3, 'K' UNION ALL
SELECT 3, 'L' UNION ALL
SELECT 4, 'M' UNION ALL
SELECT 5, 'N' UNION ALL
SELECT 5, 'O'SELECT *,sign=(c-1)/3,sign1=(c-1)%3
INTO #
FROM(SELECT *,C=(SELECT COUNT(1) FROM @TB WHERE A.ID=ID AND NAME<=A.NAME) FROM @TB A)ADECLARE @s VARCHAR(1000)
SELECT @S='SELECT ID,sign'
SELECT @s=@s+',MAX(CASE WHEN LTRIM(sign1)='''+LTRIM(sign1)+''' THEN name ELSE null END)AS ''NAME'+ltrim(sign1+1)+''' '
FROM # GROUP BY sign1
SET @S=@s+' FROM # GROUP BY ID,sign '
SET @s='SELECT ID,NAME1,NAME2,NAME3 FROM ('+@S+')A ORDER BY id'
EXEC(@S)/*
ID NAME1 NAME2 NAME3
----------- ----- ----- -----
1 A B C
1 D E NULL
2 F G H
2 I NULL NULL
3 J K L
4 M NULL NULL
5 N O NULL警告: 聚合或其它 SET 操作消除了空值。
*/
create table #TB
(
id int,
[name] varchar(50)
)
insert into #TB
select 1,'A' union all
select 1,'B' union all
select 1,'C' union all
select 1,'D' union all
select 1,'E' union all
select 2,'F' union all
select 2,'G' union all
select 2,'H' union all
select 2,'I' union all
select 3,'J' union all
select 3,'K' union all
select 3,'L' union all
select 4,'M' union all
select 5,'N' union all
select 5,'O'
create table #TC
(
GroupID int,
ID int,
[name] varchar(50)
) declare @i int
declare @ID int
set @i=0
Declare iCursor Cursor For
Select Distinct ID from #TB
Open iCursor
Fetch next from iCursor into @ID
While @@Fetch_Status=0
Begin
Insert Into #TC
select ((row-1)/3)+@i,ID,[Name] from (select row_number() over (partition by ID order by id) as row,* from #TB) B
where ID=@ID
select @i=max(GroupID)+1 from #TC
Print @i
Fetch Next from iCursor into @ID
End
Close iCursor
Deallocate iCursorselect GroupID,id,
max(case row%3 when 1 then [name] else null end) as name1,
max(case row%3 when 2 then [name] else null end) as name2,
max(case row%3 when 0 then [name] else null end) as name3
from (select row_number() over (partition by ID order by id) as row,* from #TC) b
group by GroupID,id
GroupID id name1 name2 name3
0 1 A B C
1 1 D E NULL
2 2 F G H
3 2 I NULL NULL
4 3 J K L
5 4 M NULL NULL
6 5 N O NULL
非常謝謝!順利解決了問題
順便結貼!SQL裡面看來自己很多東西還是需要多多學習的。