update 疑问 UPDATE ASET A JOIN INNER BON A.ID = B.IDSET A.column1 = B.column1,A.column2 = B.column2WHERE B.AGE>40A:id,age,column1,column2 B:id,age,column1,column2 A.id 与 B.id关联。 将B中age>40的column1,column2更新到A的相应记录中 解决方案 » 免费领取超大流量手机卡,每月29元包185G流量+100分钟通话, 中国电信官方发货 UPDATE ASET A.column1 = B.column1,A.column2 = B.column2and B.AGE>40FROM A JOIN INNER BON A.ID = B.ID UPDATE A JOIN INNER BON A.ID = B.IDSET A.column1 = B.column1,A.column2 = B.column2WHERE B.AGE>40这样不可以呢 UPDATE ASET A.column1 = B.column1,A.column2 = B.column2FROM A JOIN INNER BON A.ID = B.ID and B.AGE>40 消息 156,级别 15,状态 1,第 3 行关键字 'and' 附近有语法错误。 UPDATE ASET A.column1 = B.column1,A.column2 = B.column2A JOIN INNER B ON A.ID = B.IDWHERE B.AGE>40 UPDATE ASET A.column1 = B.column1,A.column2 = B.column2from A JOIN INNER B ON A.ID = B.IDWHERE B.AGE>40 2表create table A ( id varchar(10), column1 varchar(10), column2 varchar(10) ) create table B ( id varchar(10), column1 varchar(10), column2 varchar(10), age int ) 这个为准啊!UPDATE ASET A.column1 = B.column1,A.column2 = B.column2FROM A JOIN INNER BON A.ID = B.ID and B.AGE>40 update ASET A.column1=B.column1,A.column2=B.column2from A inner join B on A.id=B.idwhere b.age>40 消息 156,级别 15,状态 1,第 3 行关键字 'INNER' 附近有语法错误。 咋回事呢 UPDATE ASET A.column1 = B.column1,A.column2 = B.column2from A JOIN INNER B ON A.ID = B.IDWHERE B.AGE>40 UPDATE ASET A.column1 = B.column1,A.column2 = B.column2from A INNER JOIN B ON A.ID = B.IDWHERE B.AGE>40 UPDATE ASET column1 = B.column1,column2 = B.column2A JOIN INNER B ON A.ID = B.IDWHERE B.AGE>40 UPDATE ASET A.column1 = B.column1,A.column2 = B.column2FROM A INNER JOIN BON A.ID = B.ID and B.AGE>40 --inner 和 JOIN的位置不对UPDATE ASET column1 = B.column1,column2 = B.column2A INNER JOIN B ON A.ID = B.IDWHERE B.AGE>40 UPDATE ASET A.column1 = B.column1,A.column2 = B.column2from A,B WHERE A.ID = B.ID and B.AGE>40怎么都写成join inner 不是inner join么? insert into Aselect * from B WHERE A.ID = B.IDAND B.AGE>40 insert into a select * from b where age>40 消息 4104,级别 16,状态 1,第 2 行无法绑定由多个部分组成的标识符 "A.ID"。消息 213,级别 16,状态 1,第 1 行列名或所提供值的数目与表定义不匹配。 insert into Aselect * from B WHERE B.AGE>40 insert into Aselect * from B WHERE B.AGE>40 and B.id not in (select id from A) 这个问题怎么处理,大家进来看看 以下查询语句如何实现呢?要求主表中的某个字段值只出现一次 用了identify标识的字段是如何工作的? 求一句SQL,100分问题!!!!!!!!!!!!!!!!!!!!!!!!! 每天晚上自动对所有用户数据库清日志有必要吗? 重新生成索引后碎片百分比没变化问题 有没有哪位大侠有超长数据库字段的操作方法实例啊? sql? 求一复杂函数 比较难的sql语句只给一分,为财而来的就对不起了 问个SQL 排序的问题,问个几个群都未果。 存储过程中使用临时表查询的奇怪问题
UPDATE A
SET A.column1 = B.column1,A.column2 = B.column2
and B.AGE>40
FROM A JOIN INNER B
ON A.ID = B.ID
ON A.ID = B.ID
SET A.column1 = B.column1,A.column2 = B.column2
WHERE B.AGE>40
这样不可以呢
UPDATE A
SET A.column1 = B.column1,A.column2 = B.column2
FROM A JOIN INNER B
ON A.ID = B.ID and B.AGE>40
关键字 'and' 附近有语法错误。
SET A.column1 = B.column1,A.column2 = B.column2
A JOIN INNER B ON A.ID = B.ID
WHERE B.AGE>40
SET A.column1 = B.column1,A.column2 = B.column2
from A JOIN INNER B ON A.ID = B.ID
WHERE B.AGE>40
create table A (
id varchar(10),
column1 varchar(10),
column2 varchar(10)
)
create table B (
id varchar(10),
column1 varchar(10),
column2 varchar(10),
age int
)
UPDATE A
SET A.column1 = B.column1,A.column2 = B.column2
FROM A JOIN INNER B
ON A.ID = B.ID and B.AGE>40
SET A.column1=B.column1,A.column2=B.column2
from A
inner join B
on A.id=B.id
where b.age>40
消息 156,级别 15,状态 1,第 3 行
关键字 'INNER' 附近有语法错误。
咋回事呢
SET A.column1 = B.column1,A.column2 = B.column2
from A JOIN INNER B ON A.ID = B.ID
WHERE B.AGE>40
SET A.column1 = B.column1,A.column2 = B.column2
from A INNER JOIN B ON A.ID = B.ID
WHERE B.AGE>40
SET column1 = B.column1,column2 = B.column2
A JOIN INNER B ON A.ID = B.ID
WHERE B.AGE>40
SET A.column1 = B.column1,A.column2 = B.column2
FROM A INNER JOIN B
ON A.ID = B.ID and B.AGE>40
UPDATE A
SET column1 = B.column1,column2 = B.column2
A INNER JOIN B ON A.ID = B.ID
WHERE B.AGE>40
UPDATE A
SET A.column1 = B.column1,A.column2 = B.column2
from A,B
WHERE A.ID = B.ID and B.AGE>40怎么都写成join inner 不是inner join么?
select * from B WHERE A.ID = B.ID
AND B.AGE>40
insert into a select * from b where age>40
无法绑定由多个部分组成的标识符 "A.ID"。
消息 213,级别 16,状态 1,第 1 行
列名或所提供值的数目与表定义不匹配。
select * from B WHERE B.AGE>40
select * from B WHERE B.AGE>40 and B.id not in (select id from A)