当前数据库表A内容如下
ID code name cur amout
-------------------------------------------------------------------------
1 asa JJ RMB 10
1 asa JJ EUR 20
1 asa JJ HKD 28
2 ba ss RMB 10
2 ba ss HKD 10
3 dd qq RMB 50
4 zxz pp RMB 60
4 zxz pp EUR 14
4 zxz pp HKD 28现想通过查询得到如下内容
ID code name curamout
-------------------------------------------------------------------------
1 asa JJ RMB10,EUR20,HKD28
2 ba ss RMB10,HKD10
3 dd qq RMB50
4 zxz pp RMB60,EUR14,HKD28 请问此sql语句如何写
ID code name cur amout
-------------------------------------------------------------------------
1 asa JJ RMB 10
1 asa JJ EUR 20
1 asa JJ HKD 28
2 ba ss RMB 10
2 ba ss HKD 10
3 dd qq RMB 50
4 zxz pp RMB 60
4 zxz pp EUR 14
4 zxz pp HKD 28现想通过查询得到如下内容
ID code name curamout
-------------------------------------------------------------------------
1 asa JJ RMB10,EUR20,HKD28
2 ba ss RMB10,HKD10
3 dd qq RMB50
4 zxz pp RMB60,EUR14,HKD28 请问此sql语句如何写
curamount=stuff((select ','+cur+ltrim(amount) from a where id=t.id for xml path('')),1,1,'')
from a t
-- Author :fredrickhu(小F,向高手学习)
-- Date :2010-06-02 20:55:35
-- Version:
-- Microsoft SQL Server 2005 - 9.00.4035.00 (Intel X86)
-- Nov 24 2008 13:01:59
-- Copyright (c) 1988-2005 Microsoft Corporation
-- Developer Edition on Windows NT 5.1 (Build 2600: Service Pack 3)
--
----------------------------------------------------------------
--> 测试数据:[tb]
if object_id('[tb]') is not null drop table [tb]
go
create table [tb]([ID] int,[code] varchar(3),[name] varchar(2),[cur] varchar(3),[amout] int)
insert [tb]
select 1,'asa','JJ','RMB',10 union all
select 1,'asa','JJ','EUR',20 union all
select 1,'asa','JJ','HKD',28 union all
select 2,'ba','ss','RMB',10 union all
select 2,'ba','ss','HKD',10 union all
select 3,'dd','qq','RMB',50 union all
select 4,'zxz','pp','RMB',60 union all
select 4,'zxz','pp','EUR',14 union all
select 4,'zxz','pp','HKD',28
--------------开始查询--------------------------
select
id,[code],[name],
[cur]=stuff((select ','+[cur] from tb t where id=tb.id for xml path('')), 1, 1, '')
from
tb
group by
id,[code],[name]
----------------结果----------------------------
/* id code name cur
----------- ---- ---- ----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
1 asa JJ RMB,EUR,HKD
2 ba ss RMB,HKD
3 dd qq RMB
4 zxz pp RMB,EUR,HKD(4 行受影响)
*/
--*******************************************************************************************
表结构,数据如下:
id value
----- ------
1 aa
1 bb
2 aaa
2 bbb
2 ccc 需要得到结果:
id values
------ -----------
1 aa,bb
2 aaa,bbb,ccc
即:group by id, 求 value 的和(字符串相加) 1. 旧的解决方法(在sql server 2000中只能用函数解决。)
--=============================================================================
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
--1. 创建处理函数
CREATE FUNCTION dbo.f_strUnite(@id int)
RETURNS varchar(8000)
AS
BEGIN
DECLARE @str varchar(8000)
SET @str = ''
SELECT @str = @str + ',' + value FROM tb WHERE id=@id
RETURN STUFF(@str, 1, 1, '')
END
GO
-- 调用函数
SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id
drop table tb
drop function dbo.f_strUnite
go
/*
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
(所影响的行数为 2 行)
*/
--===================================================================================
2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。)
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
-- 查询处理
SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY(
SELECT [values]= STUFF(REPLACE(REPLACE(
(
SELECT value FROM tb N
WHERE id = A.id
FOR XML AUTO
), ' <N value="', ','), '"/>', ''), 1, 1, '')
)N
drop table tb /*
id values
----------- -----------
1 aa,bb
2 aaa,bbb,ccc (2 行受影响)
*/ --SQL2005中的方法2
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '')
from tb
group by id /*
id values
----------- --------------------
1 aa,bb
2 aaa,bbb,ccc (2 row(s) affected) */ drop table tb
IF OBJECT_ID('[a]') IS NOT NULL
DROP TABLE [a]
GO
CREATE TABLE [a] ([ID] [int],[code] [nvarchar](10),[name] [nvarchar](10),[cur] [nvarchar](10),[amount] [int])
INSERT INTO [a]
SELECT '1','asa','JJ','RMB','10' UNION ALL
SELECT '1','asa','JJ','EUR','20' UNION ALL
SELECT '1','asa','JJ','HKD','28' UNION ALL
SELECT '2','ba','ss','RMB','10' UNION ALL
SELECT '2','ba','ss','HKD','10' UNION ALL
SELECT '3','dd','qq','RMB','50' UNION ALL
SELECT '4','zxz','pp','RMB','60' UNION ALL
SELECT '4','zxz','pp','EUR','14' UNION ALL
SELECT '4','zxz','pp','HKD','28'--SELECT * FROM [a]-->SQL查询如下:
SELECT DISTINCT id, code, name, curamount = STUFF(
(
SELECT ','+cur+LTRIM(amount)
FROM a
WHERE id = t.id FOR XML PATH('')
), 1, 1, ''
)
FROM a t
/*
id code name curamount
----------- ---------- ---------- ----------------------------
1 asa JJ RMB10,EUR20,HKD28
2 ba ss RMB10,HKD10
3 dd qq RMB50
4 zxz pp RMB60,EUR14,HKD28(4 行受影响)*/
-- Author :fredrickhu(小F,向高手学习)
-- Date :2010-06-02 20:55:35
-- Version:
-- Microsoft SQL Server 2005 - 9.00.4035.00 (Intel X86)
-- Nov 24 2008 13:01:59
-- Copyright (c) 1988-2005 Microsoft Corporation
-- Developer Edition on Windows NT 5.1 (Build 2600: Service Pack 3)
--
----------------------------------------------------------------
--> 测试数据:[tb]
if object_id('[tb]') is not null drop table [tb]
go
create table [tb]([ID] int,[code] varchar(3),[name] varchar(2),[cur] varchar(3),[amout] int)
insert [tb]
select 1,'asa','JJ','RMB',10 union all
select 1,'asa','JJ','EUR',20 union all
select 1,'asa','JJ','HKD',28 union all
select 2,'ba','ss','RMB',10 union all
select 2,'ba','ss','HKD',10 union all
select 3,'dd','qq','RMB',50 union all
select 4,'zxz','pp','RMB',60 union all
select 4,'zxz','pp','EUR',14 union all
select 4,'zxz','pp','HKD',28
--------------开始查询--------------------------
select
id,code,name,
curamount=stuff((select ','+cur+ltrim([amout]) from tb where id=t.id for xml path('')),1,1,'')
from
tb t
group by
id,[code],[name]
----------------结果----------------------------
/*id code name curamount
----------- ---- ---- ----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
1 asa JJ RMB10,EUR20,HKD28
2 ba ss RMB10,HKD10
3 dd qq RMB50
4 zxz pp RMB60,EUR14,HKD28(4 行受影响)
*/
IF OBJECT_ID('[a]') IS NOT NULL
DROP TABLE [a]
GO
CREATE TABLE [a] ([ID] [int],[code] [nvarchar](10),[name] [nvarchar](10),[cur] [nvarchar](10),[amount] [int])
INSERT INTO [a]
SELECT '1','asa','JJ','RMB','10' UNION ALL
SELECT '1','asa','JJ','EUR','20' UNION ALL
SELECT '1','asa','JJ','HKD','28' UNION ALL
SELECT '2','ba','ss','RMB','10' UNION ALL
SELECT '2','ba','ss','HKD','10' UNION ALL
SELECT '3','dd','qq','RMB','50' UNION ALL
SELECT '4','zxz','pp','RMB','60' UNION ALL
SELECT '4','zxz','pp','EUR','14' UNION ALL
SELECT '4','zxz','pp','HKD','28'--SELECT * FROM [a]-->SQL2000查询如下:
IF OBJECT_ID('[fn_test]') IS NOT NULL
DROP FUNCTION [fn_test]
GO
CREATE FUNCTION [fn_test]
(@id int)
RETURNS varchar(100)
AS
BEGIN
DECLARE @s varchar(100)
SELECT @s = isnull(@s + ',' ,'')+ [cur]+LTRIM(amount)
FROM a
WHERE id=@id
RETURN @s
END
GO SELECT distinct id,code,name,dbo.fn_test(id) curamount
FROM a
/*
id code name curamount
----------- ---------- ---------- ----------------------------
1 asa JJ RMB10,EUR20,HKD28
2 ba ss RMB10,HKD10
3 dd qq RMB50
4 zxz pp RMB60,EUR14,HKD28(4 行受影响)*/
这是什么意思吗