Login.Userno User.Userno
F3221604,f3213469,f3205811,8324 F3221604
f1628604,f3213469,f3205811,8324 f3213469
f3205811........左边的这个字段如何变成右边的字段呢,就是把以前以逗号隔开的数据分成多个数据付给另一个表。哪位大大帮帮忙呀
F3221604,f3213469,f3205811,8324 F3221604
f1628604,f3213469,f3205811,8324 f3213469
f3205811........左边的这个字段如何变成右边的字段呢,就是把以前以逗号隔开的数据分成多个数据付给另一个表。哪位大大帮帮忙呀
CREATE FUNCTION [dbo].[fn_splitSTR](
@s varchar(8000), --待分拆的字符串
@split varchar(10) --数据分隔符
)RETURNS @re TABLE(col varchar(100))
AS
BEGIN
DECLARE @splitlen int
SET @splitlen=LEN(@split+'a')-2
WHILE CHARINDEX(@split,@s)>0
BEGIN
INSERT @re VALUES(LEFT(@s,CHARINDEX(@split,@s)-1))
SET @s=STUFF(@s,1,CHARINDEX(@split,@s)+@splitlen,'')
END
INSERT @re VALUES(@s)
RETURN
ENDGO
以下是效果:
declare @tb table(id int,Userno varchar(100))
insert @tb
select 1,'F3221604,f3213469,f3205811,8324'
union all select 2,'f1628604,f3213469,f3205811,8324'declare @tb2 table(Userno varchar(10))insert into @tb2
select col
from @tb
cross apply dbo.fn_splitSTR(Userno,',')select * from @tb2--结果:
Userno
F3221604
f3213469
f3205811
8324
f1628604
f3213469
f3205811
8324
select distinct col
from @tb
cross apply dbo.fn_splitSTR(Userno,',')select * from @tb2
就是把F3221604,f3213469,f3205811,8324
变成
F3221604
f3213469
f3205811
8324
付给第二个表
drop function [dbo].[f_splitSTR]
GO--3.2.1 循环截取法
CREATE FUNCTION f_splitSTR(
@s varchar(8000), --待分拆的字符串
@split varchar(10) --数据分隔符
)RETURNS @re TABLE(col varchar(100))
AS
BEGIN
DECLARE @splitlen int
SET @splitlen=LEN(@split+'a')-2
WHILE CHARINDEX(@split,@s)>0
BEGIN
INSERT @re VALUES(LEFT(@s,CHARINDEX(@split,@s)-1))
SET @s=STUFF(@s,1,CHARINDEX(@split,@s)+@splitlen,'')
END
INSERT @re VALUES(@s)
RETURN
END
GO
/*==============================================*/if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[f_splitSTR]') and xtype in (N'FN', N'IF', N'TF'))
drop function [dbo].[f_splitSTR]
GO--3.2.3.1 使用临时性分拆辅助表法
CREATE FUNCTION f_splitSTR(
@s varchar(8000), --待分拆的字符串
@split varchar(10) --数据分隔符
)RETURNS @re TABLE(col varchar(100))
AS
BEGIN
--创建分拆处理的辅助表(用户定义函数中只能操作表变量)
DECLARE @t TABLE(ID int IDENTITY,b bit)
INSERT @t(b) SELECT TOP 8000 0 FROM syscolumns a,syscolumns b INSERT @re SELECT SUBSTRING(@s,ID,CHARINDEX(@split,@s+@split,ID)-ID)
FROM @t
WHERE ID<=LEN(@s+'a')
AND CHARINDEX(@split,@split+@s,ID)=ID
RETURN
END
GO/*==============================================*/if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[f_splitSTR]') and xtype in (N'FN', N'IF', N'TF'))
drop function [dbo].[f_splitSTR]
GOif exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[tb_splitSTR]') and objectproperty(id,N'IsUserTable')=1)
drop table [dbo].[tb_splitSTR]
GO--3.2.3.2 使用永久性分拆辅助表法
--字符串分拆辅助表
SELECT TOP 8000 ID=IDENTITY(int,1,1) INTO dbo.tb_splitSTR
FROM syscolumns a,syscolumns b
GO--字符串分拆处理函数
CREATE FUNCTION f_splitSTR(
@s varchar(8000), --待分拆的字符串
@split varchar(10) --数据分隔符
)RETURNS TABLE
AS
RETURN(
SELECT col=CAST(SUBSTRING(@s,ID,CHARINDEX(@split,@s+@split,ID)-ID) as varchar(100))
FROM tb_splitSTR
WHERE ID<=LEN(@s+'a')
AND CHARINDEX(@split,@split+@s,ID)=ID)
GO
/*==============================================*/if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[f_splitSTR]') and xtype in (N'FN', N'IF', N'TF'))
drop function [dbo].[f_splitSTR]
GO--3.2.5 将数据项按数字与非数字再次拆份
CREATE FUNCTION f_splitSTR(
@s varchar(8000), --待分拆的字符串
@split varchar(10) --数据分隔符
)RETURNS @re TABLE(No varchar(100),Value varchar(20))
AS
BEGIN
--创建分拆处理的辅助表(用户定义函数中只能操作表变量)
DECLARE @t TABLE(ID int IDENTITY,b bit)
INSERT @t(b) SELECT TOP 8000 0 FROM syscolumns a,syscolumns b INSERT @re
SELECT No=REVERSE(STUFF(col,1,PATINDEX('%[^-^.^0-9]%',col+'a')-1,'')),
Value=REVERSE(LEFT(col,PATINDEX('%[^-^.^0-9]%',col+'a')-1))
FROM(
SELECT col=REVERSE(SUBSTRING(@s,ID,CHARINDEX(@split,@s+@split,ID)-ID))
FROM @t
WHERE ID<=LEN(@s+'a')
AND CHARINDEX(@split,@split+@s,ID)=ID)a
RETURN
END
GO
/*==============================================*/if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[f_splitSTR]') and xtype in (N'FN', N'IF', N'TF'))
drop function [dbo].[f_splitSTR]
GO--3.2.6 分拆短信数据
CREATE FUNCTION f_splitSTR(@s varchar(8000))
RETURNS @re TABLE(split varchar(10),value varchar(100))
AS
BEGIN
DECLARE @splits TABLE(split varchar(10),splitlen as LEN(split))
INSERT @splits(split)
SELECT 'AC' UNION ALL
SELECT 'BC' UNION ALL
SELECT 'CC' UNION ALL
SELECT 'DC'
DECLARE @pos1 int,@pos2 int,@split varchar(10),@splitlen int
SELECT TOP 1
@pos1=1,@split=split,@splitlen=splitlen
FROM @splits
WHERE @s LIKE split+'%'
WHILE @pos1>0
BEGIN
SELECT TOP 1
@pos2=CHARINDEX(split,@s,@splitlen+1)
FROM @splits
WHERE CHARINDEX(split,@s,@splitlen+1)>0
ORDER BY CHARINDEX(split,@s,@splitlen+1)
IF @@ROWCOUNT=0
BEGIN
INSERT @re VALUES(@split,STUFF(@s,1,@splitlen,''))
RETURN
END
ELSE
BEGIN
INSERT @re VALUES(@split,SUBSTRING(@s,@splitlen+1,@pos2-@splitlen-1))
SELECT TOP 1
@pos1=1,@split=split,@splitlen=splitlen,@s=STUFF(@s,1,@pos2-1,'')
FROM @splits
WHERE STUFF(@s,1,@pos2-1,'') LIKE split+'%'
END
END
RETURN
END
GO
--> 测试数据: #T
if object_id('tempdb.dbo.#T') is not null drop table #T
create table #T (id int,name varchar(8))
insert into #T
select 1,'jame,job' union all
select 2,'paul,mc' union all
select 3,'carl';--> 1. CTE 递归找分隔字符位置法:速度极快
with T (id,P1,P2) as
(
select id,charindex(',',','+name),charindex(',',name+',')+1 from #T
union all
select a.id,b.P2,charindex(',',name+',',b.P2)+1 from #T a join T b on a.id=b.id where charindex(',',name+',',b.P2)>0
)
select a.id,name=substring(a.name+',',b.P1,b.P2 - b.P1 - 1) from #T a join T b on a.id=b.id order by 1
/*
id name
----------- ---------
1 jame
1 job
2 mc
2 paul
3 carl
*/
--> 测试数据: #T
if object_id('tempdb.dbo.#T') is not null drop table #T
create table #T (id int,name varchar(8))
insert into #T
select 1,'jame,job' union all
select 2,'paul,mc' union all
select 3,'carl';--> 2. 临时表法:速度比CTE方法相差无几
if object_id('tempdb.dbo.#') is not null drop table #
select top 8000 id=identity(int,1,1) into # from syscolumns,sysobjects --> select max(len(name)) from #T=11
select a.id,name=substring(a.name+',',b.id,charindex(',',a.name+',',b.id+1)-b.id) from #T a inner join # b on substring(','+a.name,b.id,1)=','
/*
id name
----------- ---------
1 jame
1 job
2 mc
2 paul
3 carl
*/3. XML法:速度较慢
select
a.id,b.name
from
(select id,name=convert(xml,'<root><v>'+replace(name,',','</v><v>')+'</v></root>') from #T ) a
outer apply
(select name=N.v.value('.','varchar(100)') from a.name.nodes('/root/v') N(v)) b
/*
id name
----------- ---------
1 jame
1 job
2 mc
2 paul
3 carl
*/