合并列值 --******************************************************************************************* 表结构,数据如下: id value ----- ------ 1 aa 1 bb 2 aaa 2 bbb 2 ccc 需要得到结果: id values ------ ----------- 1 aa,bb 2 aaa,bbb,ccc 即:group by id, 求 value 的和(字符串相加) 1. 旧的解决方法(在sql server 2000中只能用函数解决。) --============================================================================= create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go --1. 创建处理函数 CREATE FUNCTION dbo.f_strUnite(@id int) RETURNS varchar(8000) AS BEGIN DECLARE @str varchar(8000) SET @str = '' SELECT @str = @str + ',' + value FROM tb WHERE id=@id RETURN STUFF(@str, 1, 1, '') END GO -- 调用函数 SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id drop table tb drop function dbo.f_strUnite go /* id value ----------- ----------- 1 aa,bb 2 aaa,bbb,ccc (所影响的行数为 2 行) */ --=================================================================================== 2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。) create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go -- 查询处理 SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY( SELECT [values]= STUFF(REPLACE(REPLACE( ( SELECT value FROM tb N WHERE id = A.id FOR XML AUTO ), ' <N value="', ','), '"/>', ''), 1, 1, '') )N drop table tb /* id values ----------- ----------- 1 aa,bb 2 aaa,bbb,ccc (2 行受影响) */ --SQL2005中的方法2 create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '') from tb group by id /* id values ----------- -------------------- 1 aa,bb 2 aaa,bbb,ccc (2 row(s) affected) */ drop table tb /* 标题:分拆列值1 作者:爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开) 时间:2008-11-20 地点:广东深圳 描述有表tb, 如下: id value ----------- ----------- 1 aa,bb 2 aaa,bbb,ccc 欲按id,分拆value列, 分拆后结果如下: id value ----------- -------- 1 aa 1 bb 2 aaa 2 bbb 2 ccc */--1. 旧的解决方法(sql server 2000) SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b SELECT A.id, value = SUBSTRING(A.[value], B.id, CHARINDEX(',', A.[value] + ',', B.id) - B.id) FROM tb A, # B WHERE SUBSTRING(',' + A.[value], B.id, 1) = ','DROP TABLE #--2. 新的解决方法(sql server 2005) create table tb(id int,value varchar(30)) insert into tb values(1,'aa,bb') insert into tb values(2,'aaa,bbb,ccc') go SELECT A.id, B.value FROM( SELECT id, [value] = CONVERT(xml,'<root><v>' + REPLACE([value], ',', '</v><v>') + '</v></root>') FROM tb )A OUTER APPLY( SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v) )BDROP TABLE tb/* id value ----------- ------------------------------ 1 aa 1 bb 2 aaa 2 bbb 2 ccc(5 行受影响) */
select a.so_no,a.sta_dd,b.end_dd,a.amt,b.fin_amt,b.salme from ta a, (select so_no,max(end_dd) end_dd,sum9fin_amt) as fin_amt,salm = (select ''+salm from tb where so_no = b.so_no for xml path('')) from tb b ) c where a.so_no = c.so_no
create table A ( SO_no nvarchar(50), sta_dd datetime, amt int ) insert into A select 'so001','2009-1-1',100 insert into A select 'so002','2009-5-1',800 insert into A select 'so003','2009-1-1',500 insert into A select 'so004','2009-3-10',1000create table B1 ( SO_no nvarchar(50), end_dd datetime, fin_amt int, salm nvarchar(20) ) insert into B1 select 'so001','2009-2-1',100,'aaa' insert into B1 select 'so002','2009-6-1',200,'bbb' insert into B1 select 'so002','2009-6-5',300,'ccc' insert into B1 select 'so002','2009-6-20',300,'ddd' insert into B1 select 'so003','2009-2-1',200,'eee' insert into B1 select 'so003','2009-2-10',200,'fff'drop function dbo.f_str CREATE FUNCTION dbo.f_str(@SO_no nvarchar(20)) RETURNS varchar(8000) AS BEGIN DECLARE @str varchar(8000) SET @str = '' SELECT @str = @str + ',' + salm FROM B1 WHERE SO_no=@SO_no RETURN STUFF(@str, 1, 1, '') END GO select A.*,B.end_dd,B.salm from A left join ( select SO_no,max(end_dd) end_dd,sum(fin_amt) fin_amt,dbo.f_str(SO_no) salm from B1 group by SO_no,dbo.f_str(SO_no) ) B on A.SO_no=B.SO_noSO_no sta_dd amt end_dd salm -------------------------------------------------- ----------------------- ----------- ----------------------- ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- so001 2009-01-01 00:00:00.000 100 2009-02-01 00:00:00.000 aaa so002 2009-05-01 00:00:00.000 800 2009-06-20 00:00:00.000 bbb,ccc,ddd so003 2009-01-01 00:00:00.000 500 2009-02-10 00:00:00.000 eee,fff so004 2009-03-10 00:00:00.000 1000 NULL NULL(4 行受影响)
create table A ( SO_no nvarchar(50), sta_dd datetime, amt int ) insert into A select 'so001','2009-1-1',100 insert into A select 'so002','2009-5-1',800 insert into A select 'so003','2009-1-1',500 insert into A select 'so004','2009-3-10',1000create table B1 ( SO_no nvarchar(50), end_dd datetime, fin_amt int, salm nvarchar(20) ) insert into B1 select 'so001','2009-2-1',100,'aaa' insert into B1 select 'so002','2009-6-1',200,'bbb' insert into B1 select 'so002','2009-6-5',300,'ccc' insert into B1 select 'so002','2009-6-20',300,'ddd' insert into B1 select 'so003','2009-2-1',200,'eee' insert into B1 select 'so003','2009-2-10',200,'fff'drop function dbo.f_str CREATE FUNCTION dbo.f_str(@SO_no nvarchar(20)) RETURNS varchar(8000) AS BEGIN DECLARE @str varchar(8000) SET @str = '' SELECT @str = @str + ',' + salm FROM B1 WHERE SO_no=@SO_no RETURN STUFF(@str, 1, 1, '') END GO select A.*,B.end_dd,B.salm,B.fin_amt from A left join ( select SO_no,max(end_dd) end_dd,sum(fin_amt) fin_amt,dbo.f_str(SO_no) salm from B1 group by SO_no,dbo.f_str(SO_no) ) B on A.SO_no=B.SO_noSO_no sta_dd amt end_dd salm fin_amt -------------------------------------------------- ----------------------- ----------- ----------------------- ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- ----------- so001 2009-01-01 00:00:00.000 100 2009-02-01 00:00:00.000 aaa 100 so002 2009-05-01 00:00:00.000 800 2009-06-20 00:00:00.000 bbb,ccc,ddd 800 so003 2009-01-01 00:00:00.000 500 2009-02-10 00:00:00.000 eee,fff 400 so004 2009-03-10 00:00:00.000 1000 NULL NULL NULL(4 行受影响)
CREATE FUNCTION dbo.f(@SO_no int) RETURNS varchar(8000) AS BEGIN DECLARE @str varchar(8000) SET @str = '' SELECT @str = @str + ',' + salm FROM 表A WHERE @SO_no=@SO_no --把 [ 表A ] 换成你的表 RETURN STUFF(@str, 1, 1, '') END GO select a.SO_no,a.sta_dd,b.end_dd,a.amt,isnull(fin_amt,0),salm from 表A a left (select SO_no,max(end_dd) end_dd,sum(fin_amt) fin_amt,salm=dbo.f(SO_no) from 表B group by SO_no,convert(char(7),end_dd,21)) b on a.SO_no = b.SO_no
[code=create table A ( SO_no nvarchar(50), sta_dd datetime, amt int ) insert into A select 'so001','2009-1-1',100 insert into A select 'so002','2009-5-1',800 insert into A select 'so003','2009-1-1',500 insert into A select 'so004','2009-3-10',1000][/code]
create table A ( SO_no nvarchar(50), sta_dd datetime, amt int ) insert into A select 'so001','2009-1-1',100 insert into A select 'so002','2009-5-1',800 insert into A select 'so003','2009-1-1',500 insert into A select 'so004','2009-3-10',1000
--*******************************************************************************************
表结构,数据如下:
id value
----- ------
1 aa
1 bb
2 aaa
2 bbb
2 ccc 需要得到结果:
id values
------ -----------
1 aa,bb
2 aaa,bbb,ccc
即:group by id, 求 value 的和(字符串相加) 1. 旧的解决方法(在sql server 2000中只能用函数解决。)
--=============================================================================
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
--1. 创建处理函数
CREATE FUNCTION dbo.f_strUnite(@id int)
RETURNS varchar(8000)
AS
BEGIN
DECLARE @str varchar(8000)
SET @str = ''
SELECT @str = @str + ',' + value FROM tb WHERE id=@id
RETURN STUFF(@str, 1, 1, '')
END
GO
-- 调用函数
SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id
drop table tb
drop function dbo.f_strUnite
go
/*
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
(所影响的行数为 2 行)
*/
--===================================================================================
2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。)
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
-- 查询处理
SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY(
SELECT [values]= STUFF(REPLACE(REPLACE(
(
SELECT value FROM tb N
WHERE id = A.id
FOR XML AUTO
), ' <N value="', ','), '"/>', ''), 1, 1, '')
)N
drop table tb /*
id values
----------- -----------
1 aa,bb
2 aaa,bbb,ccc (2 行受影响)
*/ --SQL2005中的方法2
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '')
from tb
group by id /*
id values
----------- --------------------
1 aa,bb
2 aaa,bbb,ccc (2 row(s) affected) */ drop table tb /*
标题:分拆列值1
作者:爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开)
时间:2008-11-20
地点:广东深圳
描述有表tb, 如下:
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
欲按id,分拆value列, 分拆后结果如下:
id value
----------- --------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
*/--1. 旧的解决方法(sql server 2000)
SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b SELECT A.id, value = SUBSTRING(A.[value], B.id, CHARINDEX(',', A.[value] + ',', B.id) - B.id)
FROM tb A, # B
WHERE SUBSTRING(',' + A.[value], B.id, 1) = ','DROP TABLE #--2. 新的解决方法(sql server 2005)
create table tb(id int,value varchar(30))
insert into tb values(1,'aa,bb')
insert into tb values(2,'aaa,bbb,ccc')
go
SELECT A.id, B.value
FROM(
SELECT id, [value] = CONVERT(xml,'<root><v>' + REPLACE([value], ',', '</v><v>') + '</v></root>') FROM tb
)A
OUTER APPLY(
SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v)
)BDROP TABLE tb/*
id value
----------- ------------------------------
1 aa
1 bb
2 aaa
2 bbb
2 ccc(5 行受影响)
*/
from ta a,
(select so_no,max(end_dd) end_dd,sum9fin_amt) as fin_amt,salm = (select ''+salm from tb where so_no = b.so_no for xml path(''))
from tb b ) c
where a.so_no = c.so_no
(
SO_no nvarchar(50),
sta_dd datetime,
amt int
)
insert into A select 'so001','2009-1-1',100
insert into A select 'so002','2009-5-1',800
insert into A select 'so003','2009-1-1',500
insert into A select 'so004','2009-3-10',1000create table B1
(
SO_no nvarchar(50),
end_dd datetime,
fin_amt int,
salm nvarchar(20)
)
insert into B1 select 'so001','2009-2-1',100,'aaa'
insert into B1 select 'so002','2009-6-1',200,'bbb'
insert into B1 select 'so002','2009-6-5',300,'ccc'
insert into B1 select 'so002','2009-6-20',300,'ddd'
insert into B1 select 'so003','2009-2-1',200,'eee'
insert into B1 select 'so003','2009-2-10',200,'fff'drop function dbo.f_str
CREATE FUNCTION dbo.f_str(@SO_no nvarchar(20))
RETURNS varchar(8000)
AS
BEGIN
DECLARE @str varchar(8000)
SET @str = ''
SELECT @str = @str + ',' + salm FROM B1 WHERE SO_no=@SO_no
RETURN STUFF(@str, 1, 1, '')
END
GO select A.*,B.end_dd,B.salm from A
left join
(
select SO_no,max(end_dd) end_dd,sum(fin_amt) fin_amt,dbo.f_str(SO_no) salm from B1
group by SO_no,dbo.f_str(SO_no)
) B
on A.SO_no=B.SO_noSO_no sta_dd amt end_dd salm
-------------------------------------------------- ----------------------- ----------- ----------------------- ----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
so001 2009-01-01 00:00:00.000 100 2009-02-01 00:00:00.000 aaa
so002 2009-05-01 00:00:00.000 800 2009-06-20 00:00:00.000 bbb,ccc,ddd
so003 2009-01-01 00:00:00.000 500 2009-02-10 00:00:00.000 eee,fff
so004 2009-03-10 00:00:00.000 1000 NULL NULL(4 行受影响)
create table A
(
SO_no nvarchar(50),
sta_dd datetime,
amt int
)
insert into A select 'so001','2009-1-1',100
insert into A select 'so002','2009-5-1',800
insert into A select 'so003','2009-1-1',500
insert into A select 'so004','2009-3-10',1000create table B1
(
SO_no nvarchar(50),
end_dd datetime,
fin_amt int,
salm nvarchar(20)
)
insert into B1 select 'so001','2009-2-1',100,'aaa'
insert into B1 select 'so002','2009-6-1',200,'bbb'
insert into B1 select 'so002','2009-6-5',300,'ccc'
insert into B1 select 'so002','2009-6-20',300,'ddd'
insert into B1 select 'so003','2009-2-1',200,'eee'
insert into B1 select 'so003','2009-2-10',200,'fff'drop function dbo.f_str
CREATE FUNCTION dbo.f_str(@SO_no nvarchar(20))
RETURNS varchar(8000)
AS
BEGIN
DECLARE @str varchar(8000)
SET @str = ''
SELECT @str = @str + ',' + salm FROM B1 WHERE SO_no=@SO_no
RETURN STUFF(@str, 1, 1, '')
END
GO select A.*,B.end_dd,B.salm,B.fin_amt from A
left join
(
select SO_no,max(end_dd) end_dd,sum(fin_amt) fin_amt,dbo.f_str(SO_no) salm from B1
group by SO_no,dbo.f_str(SO_no)
) B
on A.SO_no=B.SO_noSO_no sta_dd amt end_dd salm fin_amt
-------------------------------------------------- ----------------------- ----------- ----------------------- ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- -----------
so001 2009-01-01 00:00:00.000 100 2009-02-01 00:00:00.000 aaa 100
so002 2009-05-01 00:00:00.000 800 2009-06-20 00:00:00.000 bbb,ccc,ddd 800
so003 2009-01-01 00:00:00.000 500 2009-02-10 00:00:00.000 eee,fff 400
so004 2009-03-10 00:00:00.000 1000 NULL NULL NULL(4 行受影响)
RETURNS varchar(8000)
AS
BEGIN
DECLARE @str varchar(8000)
SET @str = ''
SELECT @str = @str + ',' + salm FROM 表A WHERE @SO_no=@SO_no --把 [ 表A ] 换成你的表
RETURN STUFF(@str, 1, 1, '')
END
GO
select a.SO_no,a.sta_dd,b.end_dd,a.amt,isnull(fin_amt,0),salm
from 表A a left (select SO_no,max(end_dd) end_dd,sum(fin_amt) fin_amt,salm=dbo.f(SO_no) from 表B group by SO_no,convert(char(7),end_dd,21)) b on a.SO_no = b.SO_no
(
SO_no nvarchar(50),
sta_dd datetime,
amt int
)
insert into A select 'so001','2009-1-1',100
insert into A select 'so002','2009-5-1',800
insert into A select 'so003','2009-1-1',500
insert into A select 'so004','2009-3-10',1000][/code]
(
SO_no nvarchar(50),
sta_dd datetime,
amt int
)
insert into A select 'so001','2009-1-1',100
insert into A select 'so002','2009-5-1',800
insert into A select 'so003','2009-1-1',500
insert into A select 'so004','2009-3-10',1000