--折分数组中的元素,并计算当前元素在数组中的位置pos CREATE TABLE dbo.Arrays ( arrid VARCHAR(10) NOT NULL PRIMARY KEY, array VARCHAR(8000) NOT NULL )INSERT INTO Arrays(arrid, array) VALUES('A', '20,22,25,25,14'); INSERT INTO Arrays(arrid, array) VALUES('B', '30,33,28'); INSERT INTO Arrays(arrid, array) VALUES('C', '12,10,8,12,12,13,12,14,10,9'); INSERT INTO Arrays(arrid, array) VALUES('D', '-4,-6,-4,-2'); GO select identity(int,1,1) as n into #temp1 from syscolumnsSELECT arrid, n - LEN(REPLACE(LEFT(array, n), ',', '')) + 1 AS pos, SUBSTRING(array, n, CHARINDEX(',', array + ',', n) - n) AS element FROM dbo.Arrays JOIN dbo.#temp1 ON n <= LEN(array) AND SUBSTRING(',' + array, n, 1) = ',';结果: arrid pos element A 1 20 A 2 22 A 3 25 A 4 25 A 5 14 B 1 30 B 2 33 B 3 28 C 1 12 C 2 10 C 3 8 C 4 12 C 5 12 C 6 13 C 7 12 C 8 14 C 9 10 C 10 9 D 1 -4 D 2 -6 D 3 -4 D 4 -2
拆分表:--> --> (Roy)生成測試數據
if not object_id('Tab') is null drop table Tab Go Create table Tab([Col1] int,[COl2] nvarchar(5)) Insert Tab select 1,N'a,b,c' union all select 2,N'd,e' union all select 3,N'f' GoSQL2000用辅助表: if object_id('Tempdb..#Num') is not null drop table #Num go select top 100 ID=Identity(int,1,1) into #Num from syscolumns a,syscolumns b Select a.Col1,COl2=substring(a.Col2,b.ID,charindex(',',a.Col2+',',b.ID)-b.ID) from Tab a,#Num b where charindex(',',','+a.Col2,b.ID)=b.ID --也可用 substring(','+a.COl2,b.ID,1)=',' SQL2005用Xml:select a.COl1,b.Col2 from (select Col1,COl2=convert(xml,'<root><v>'+replace(COl2,',','</v><v>')+'</v></root>') from Tab)a outer apply (select Col2=C.v.value('.','nvarchar(100)') from a.COl2.nodes('/root/v')C(v))b SQL05用CTE:;with roy as (select Col1,COl2=cast(left(Col2,charindex(',',Col2+',')-1) as nvarchar(100)),Split=cast(stuff(COl2+',',1,charindex(',',Col2+','),'') as nvarchar(100)) from Tab union all select Col1,COl2=cast(left(Split,charindex(',',Split)-1) as nvarchar(100)),Split= cast(stuff(Split,1,charindex(',',Split),'') as nvarchar(100)) from Roy where split>'' ) select COl1,COl2 from roy order by COl1 option (MAXRECURSION 0)生成结果: /* Col1 COl2 ----------- ----- 1 a 1 b 1 c 2 d 2 e 3 f */
declare @str varchar(100)set @str = 'a,b,c'set @str = 'select name='''+replace(@str,',',''''+' union all select ''')+''''--set @str=left(@str,len(@str)-1)exec (@str)/* name ---- a b c*/
if object_id('[tb]') is not null drop table [tb] go create table [tb]([id] int,[name] varchar(10)) insert [tb] select 1,'a' union all select 2,'b' union all select 3,'c' select STUFF((select ','+name from tb for xml path('')),1,1,'') /* ------------ a,b,c(1 行受影响) */
if object_id('[tb]') is not null drop table [tb] go create table [tb]([name] varchar(10)) insert [tb] select 'a,b,c'select id=ROW_NUMBER() over(order by getdate()),b.name from (select name=convert(xml,'<v>'+replace(name,',','</v><v>')+'</v>') from tb) a cross apply (select name=C.v.value('.','nvarchar(100)') from a.name.nodes('/v')C(v)) b
/* id name -------------------- ---------------------------------------------------------------------------------------------------- 1 a 2 b 3 c(3 行受影响) */看反了.
3楼的,不过你变成A1,B2,C3这样的值后就报错了呢?
declare @str varchar(100)set @str = 'a1,b1,c2,d1,e3,f5'set @str = 'select name='''+replace(@str,',',''''+' union all select ''')+''''set @str=left(@str,len(@str)-1)exec (@str) sdhdy :这样你试一下,报啥错?
把长度设的大一些。看红字部分,上面的只是举个例子 declare @str varchar(8000) set @str = 'a1,b1,c2,d1,e3,f5' set @str = 'select name='''+replace(@str,',',''''+' union all select ''')+'''' print @str exec (@str)
declare @str varchar(8000) set @str = 'a1,b1,c2,d1,e3,f5' set @str = 'select name='''+replace(@str,',',''''+' union all select ''')+''')' set @str=left(@str,len(@str)-1) --print @Str exec (@str)
'select name='''+replace(@str,',',''''+' union all select ''')+''')' sdhdy 你这里这么多''''是啥意思呢?哪和哪是一对啊?
--set @str=left(@str,len(@str)-1)这句去掉
'select name='''+replace(@str,',',''''+' union all select ''')+''')' sdhdy 你这里这么多''''是啥意思呢?哪和哪是一对啊?有点晕,指点一下吧
楼主要看不明白的话,就print @str看看,琢磨琢磨,几句话也说不明白。
这么说吧,我就是要把里面的'替换为' union all select ' 但是在变量里是不能这么写的。'一般都成对出现,2个'代表一个',当然还有前后的运算符都要用'连接。
我现在有一字段值为:a,b,c 分隔符为逗号. 我现在想实现目地值为: 字段: id name 1 a 2 b 3 c 在SQL中咋实现呢?
declare @str varchar(8000) set @str = 'a1,b1,c2,d1,e3,f5' set @str = 'select name='''+replace(@str,',',''''+' union all select ''')+'''' --如果要编号的话,那就这样。set @str='select id=identity(int,1,1),name into #temp from ('+@str+') a select * from #temp drop table #temp'exec(@str) /*(所影响的行数为 6 行)id name ----------- ---- 1 a1 2 b1 3 c2 4 d1 5 e3 6 f5(所影响的行数为 6 行)*/
sdhdy 的不报错的。csdyyr的资料经典, 学习!
!!怎么都是sqlserver,有沒有研究oracle數據庫的?
我简化了一下,容易懂declare @str varchar(8000) set @str= 'a1,b1,b3,a1,b1,b3,a1,b1,b3,a1,b1,b3,a1,b1,b3,a1,b1,b3,a1,b1,b3' set @str = 'select name='''+ replace(@str,',',''' union all select ''')+'''' print @Str exec (@str)
没太看懂意思,献丑:表名:aaa 列名:asql语句:select '1' as id,substr(a,1,instr(a,',',1,1)-1) as name from aaa union select '2' as id,substr(a,instr(a,',',1,1)+1,instr(a,',',1,2)-instr(a,',',1,1)-1) as name from aaa union select '3' as id,substr(a,instr(a,',',1,2)+1,length(a)-instr(a,',',1,2)) as name from aaa
把 '1' as id 用一个序列替换比较好
1楼的可以解析一下 SELECT arrid, n - LEN(REPLACE(LEFT(array, n), ',', '')) + 1 AS pos, SUBSTRING(array, n, CHARINDEX(',', array + ',', n) - n) AS element FROM dbo.Arrays JOIN dbo.#temp1 ON n <= LEN(array) AND SUBSTRING(',' + array, n, 1) = ','; 这条语句的含义么,把大概的思想说一下
CREATE TABLE Arrays ( arrid VARCHAR(10) NOT NULL PRIMARY KEY, array VARCHAR(8000) NOT NULL )INSERT INTO Arrays(arrid, array) VALUES('A', '20,22,25,25,14'); INSERT INTO Arrays(arrid, array) VALUES('B', '30,33,28'); INSERT INTO Arrays(arrid, array) VALUES('C', '12,10,8,12,12,13,12,14,10,9'); INSERT INTO Arrays(arrid, array) VALUES('D', '-4,-6,-4,-2'); select * from arrays --表值函数,拆分字段 create function split(@array varchar(500)) returns @resault table(ay varchar(10)) as beginwhile charindex(',',@array)!=0 begin insert into @resault select substring(@array,1,charindex(',',@array)-1) set @array=right(@array,len(@array)-charindex(',',@array)) end insert into @resault select @array return end select arrid,ay from arrays cross apply split(arrays.array)
CREATE TABLE dbo.Arrays
(
arrid VARCHAR(10) NOT NULL PRIMARY KEY,
array VARCHAR(8000) NOT NULL
)INSERT INTO Arrays(arrid, array) VALUES('A', '20,22,25,25,14');
INSERT INTO Arrays(arrid, array) VALUES('B', '30,33,28');
INSERT INTO Arrays(arrid, array) VALUES('C', '12,10,8,12,12,13,12,14,10,9');
INSERT INTO Arrays(arrid, array) VALUES('D', '-4,-6,-4,-2');
GO
select identity(int,1,1) as n into #temp1 from syscolumnsSELECT arrid, n - LEN(REPLACE(LEFT(array, n), ',', '')) + 1 AS pos, SUBSTRING(array, n, CHARINDEX(',', array + ',', n) - n) AS element
FROM dbo.Arrays
JOIN dbo.#temp1
ON n <= LEN(array)
AND SUBSTRING(',' + array, n, 1) = ',';结果:
arrid pos element
A 1 20
A 2 22
A 3 25
A 4 25
A 5 14
B 1 30
B 2 33
B 3 28
C 1 12
C 2 10
C 3 8
C 4 12
C 5 12
C 6 13
C 7 12
C 8 14
C 9 10
C 10 9
D 1 -4
D 2 -6
D 3 -4
D 4 -2
if not object_id('Tab') is null
drop table Tab
Go
Create table Tab([Col1] int,[COl2] nvarchar(5))
Insert Tab
select 1,N'a,b,c' union all
select 2,N'd,e' union all
select 3,N'f'
GoSQL2000用辅助表:
if object_id('Tempdb..#Num') is not null
drop table #Num
go
select top 100 ID=Identity(int,1,1) into #Num from syscolumns a,syscolumns b
Select
a.Col1,COl2=substring(a.Col2,b.ID,charindex(',',a.Col2+',',b.ID)-b.ID)
from
Tab a,#Num b
where
charindex(',',','+a.Col2,b.ID)=b.ID --也可用 substring(','+a.COl2,b.ID,1)=','
SQL2005用Xml:select
a.COl1,b.Col2
from
(select Col1,COl2=convert(xml,'<root><v>'+replace(COl2,',','</v><v>')+'</v></root>') from Tab)a
outer apply
(select Col2=C.v.value('.','nvarchar(100)') from a.COl2.nodes('/root/v')C(v))b
SQL05用CTE:;with roy as
(select Col1,COl2=cast(left(Col2,charindex(',',Col2+',')-1) as nvarchar(100)),Split=cast(stuff(COl2+',',1,charindex(',',Col2+','),'') as nvarchar(100)) from Tab
union all
select Col1,COl2=cast(left(Split,charindex(',',Split)-1) as nvarchar(100)),Split= cast(stuff(Split,1,charindex(',',Split),'') as nvarchar(100)) from Roy where split>''
)
select COl1,COl2 from roy order by COl1 option (MAXRECURSION 0)生成结果:
/*
Col1 COl2
----------- -----
1 a
1 b
1 c
2 d
2 e
3 f
*/
name
----
a
b
c*/
go
create table [tb]([id] int,[name] varchar(10))
insert [tb] select 1,'a'
union all select 2,'b'
union all select 3,'c'
select STUFF((select ','+name from tb for xml path('')),1,1,'')
/*
------------
a,b,c(1 行受影响)
*/
go
create table [tb]([name] varchar(10))
insert [tb] select 'a,b,c'select
id=ROW_NUMBER() over(order by getdate()),b.name
from
(select name=convert(xml,'<v>'+replace(name,',','</v><v>')+'</v>') from tb) a
cross apply
(select name=C.v.value('.','nvarchar(100)') from a.name.nodes('/v')C(v)) b
/*
id name
-------------------- ----------------------------------------------------------------------------------------------------
1 a
2 b
3 c(3 行受影响)
*/看反了.
sdhdy :这样你试一下,报啥错?
declare @str varchar(8000) set @str = 'a1,b1,c2,d1,e3,f5' set @str = 'select name='''+replace(@str,',',''''+' union all select ''')+''''
print @str
exec (@str)
--print @Str
exec (@str)
分隔符为逗号.
我现在想实现目地值为:
字段:
id name
1 a
2 b
3 c 在SQL中咋实现呢?
/*(所影响的行数为 6 行)id name
----------- ----
1 a1
2 b1
3 c2
4 d1
5 e3
6 f5(所影响的行数为 6 行)*/
set @str= 'a1,b1,b3,a1,b1,b3,a1,b1,b3,a1,b1,b3,a1,b1,b3,a1,b1,b3,a1,b1,b3'
set @str = 'select name='''+ replace(@str,',',''' union all select ''')+''''
print @Str
exec (@str)
<TABLE WIDTH=420 BORDER=0 CELLPADDING=0 CELLSPACING=0 align=center>
<TR>
<TD><IMG SRC="images/login_admin1.jpg" WIDTH=420 HEIGHT=36></TD>
</TR>
<TR>
<TD><IMG SRC="images/login_admin2.jpg" WIDTH=420 HEIGHT=106></TD>
</TR>
<TR>
<TD background="images/login_admin3.jpg" WIDTH=420 HEIGHT=137>
<form name="form" method="post" action="login.jsp" onSubmit="return LoginCheck_jy()">
<table width="342" border="0" align="center" cellpadding="2" cellspacing="1">
<tr>
<td width="80%" > 用户帐号:
<input name="User" type="text" class="chinese" id="User" style="font-size: 12px" size="16" maxlength="16"></td>
<td width="20%" align="center">
<input class="go-wenbenkuang" name="imageField" value="管理登陆" type="submit" onClick="return check();">
</td>
</tr>
<tr>
<td> 用户密码:
<input name="Pwd" type="password" class="chinese" id="Pwd" style="font-size: 12px" size="16" maxlength="16"></td>
<td align="center">
<input class="go-wenbenkuang" onClick="ClearReset()" type=reset name="Clear" value="清除重来"><input name="Action" type="hidden" id="Action" value="Login">
</td>
</tr>
<tr>
<td>程序验证码:
<input name="VerifyCode" type="text" class="chinese" id="VerifyCode" style="font-size: 12px" size="6" maxlength="6">
<span class="info1"> <img src="VerifyCode.jsp"><br>(区分大小写)<%=((String)session.getAttribute("error")==null)? "" : (String)session.getAttribute("error")%></span> </td>
<td align="center">
</td>
</tr>
</table>
</form></TD>
</TR>
<TR>
<TD>
<IMG SRC="images/login_admin4.jpg" WIDTH=420 HEIGHT=51></TD>
</TR>
</TABLE>
</body>
</html>
列名:asql语句:select '1' as id,substr(a,1,instr(a,',',1,1)-1) as name from aaa
union select '2' as id,substr(a,instr(a,',',1,1)+1,instr(a,',',1,2)-instr(a,',',1,1)-1) as name from aaa
union select '3' as id,substr(a,instr(a,',',1,2)+1,length(a)-instr(a,',',1,2)) as name from aaa
SELECT arrid, n - LEN(REPLACE(LEFT(array, n), ',', '')) + 1 AS pos, SUBSTRING(array, n, CHARINDEX(',', array + ',', n) - n) AS element
FROM dbo.Arrays
JOIN dbo.#temp1
ON n <= LEN(array)
AND SUBSTRING(',' + array, n, 1) = ',';
这条语句的含义么,把大概的思想说一下
我在这里学习了我提出一种大家不长用的方法吧(SQLServer2005)
大家可以试试用CRL
c#在字符串分析方面效率高于T-SQL
如果有感兴趣的可以E-Mail我([email protected])
(
arrid VARCHAR(10) NOT NULL PRIMARY KEY,
array VARCHAR(8000) NOT NULL
)INSERT INTO Arrays(arrid, array) VALUES('A', '20,22,25,25,14');
INSERT INTO Arrays(arrid, array) VALUES('B', '30,33,28');
INSERT INTO Arrays(arrid, array) VALUES('C', '12,10,8,12,12,13,12,14,10,9');
INSERT INTO Arrays(arrid, array) VALUES('D', '-4,-6,-4,-2');
select * from arrays
--表值函数,拆分字段
create function split(@array varchar(500)) returns @resault table(ay varchar(10))
as
beginwhile charindex(',',@array)!=0
begin
insert into @resault
select substring(@array,1,charindex(',',@array)-1)
set @array=right(@array,len(@array)-charindex(',',@array))
end
insert into @resault
select @array
return
end
select arrid,ay from arrays cross apply split(arrays.array)