--> 生成测试数据: @tb DECLARE @tb TABLE (id int,号码 int,机主 varchar(3),提供人 varchar(3)) INSERT INTO @tb SELECT 1,101,'张1','李1' UNION ALL SELECT 2,101,'张2','李2' UNION ALL SELECT 3,102,'张3','李3' UNION ALL SELECT 4,101,'张4','李4' UNION ALL SELECT 5,103,'张5','李5' UNION ALL SELECT 6,103,'张6','李6'--SQL查询如下:SELECT A.id,A.号码, STUFF(B.x.query('/x1/text()').value('.','varchar(MAX)'),1,1,'') AS 机主, STUFF(B.x.query('/x2/text()').value('.','varchar(MAX)'),1,1,'') AS 提供人 FROM (SELECT MIN(id) AS id,号码 FROM @tb GROUP BY 号码) AS A CROSS APPLY ( SELECT x=(SELECT x1='|'+机主, x2='|'+提供人 FROM @tb WHERE A.号码=号码 FOR XML PATH(''),TYPE) ) AS B/* id 号码 机主 提供人 1 101 张1|张2|张4 李1|李2|李4 3 102 张3 李3 5 103 张5|张6 李5|李6 */
---------------------------------------------------------------- -- Author :fredrickhu(小F,向高手学习) -- Date :2009-12-20 10:12:09 -- Version: -- Microsoft SQL Server 2005 - 9.00.4035.00 (Intel X86) -- Nov 24 2008 13:01:59 -- Copyright (c) 1988-2005 Microsoft Corporation -- Developer Edition on Windows NT 5.1 (Build 2600: Service Pack 3) -- ---------------------------------------------------------------- --> 测试数据:[tb] if object_id('[tb]') is not null drop table [tb] go create table [tb]([id] int,[号码] int,[机主] varchar(3),[提供人] varchar(3)) insert [tb] select 1,101,'张1','李1' union all select 2,101,'张2','李2' union all select 3,102,'张3','李3' union all select 4,101,'张4','李4' union all select 5,103,'张5','李5' union all select 6,103,'张6','李6' --------------开始查询-------------------------- select 号码, [机主]=stuff((select '|'+[机主] from tb where 号码=t.号码 for xml path('')), 1, 1, ''), [提供人]=stuff((select '|'+[提供人] from tb where 号码=t.号码 for xml path('')), 1, 1, '') from tb t group by 号码 ----------------结果---------------------------- /* 号码 机主 提供人 ----------- ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- 101 张1|张2|张4 李1|李2|李4 102 张3 李3 103 张5|张6 李5|李6(3 行受影响)*/
合并列值 --******************************************************************************************* 表结构,数据如下: id value ----- ------ 1 aa 1 bb 2 aaa 2 bbb 2 ccc 需要得到结果: id values ------ ----------- 1 aa,bb 2 aaa,bbb,ccc 即:group by id, 求 value 的和(字符串相加) 1. 旧的解决方法(在sql server 2000中只能用函数解决。) --============================================================================= create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go --1. 创建处理函数 CREATE FUNCTION dbo.f_strUnite(@id int) RETURNS varchar(8000) AS BEGIN DECLARE @str varchar(8000) SET @str = '' SELECT @str = @str + ',' + value FROM tb WHERE id=@id RETURN STUFF(@str, 1, 1, '') END GO -- 调用函数 SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id drop table tb drop function dbo.f_strUnite go /* id value ----------- ----------- 1 aa,bb 2 aaa,bbb,ccc (所影响的行数为 2 行) */ --=================================================================================== 2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。) create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go -- 查询处理 SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY( SELECT [values]= STUFF(REPLACE(REPLACE( ( SELECT value FROM tb N WHERE id = A.id FOR XML AUTO ), ' <N value="', ','), '"/>', ''), 1, 1, '') )N drop table tb /* id values ----------- ----------- 1 aa,bb 2 aaa,bbb,ccc (2 行受影响) */ --SQL2005中的方法2 create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '') from tb group by id /* id values ----------- -------------------- 1 aa,bb 2 aaa,bbb,ccc (2 row(s) affected) */ drop table tb
-- Author : liangCK 梁爱兰
-- Comment: 小梁 爱 兰儿
-- Date : 2009-12-20 10:00:43
-------------------------------------
--> 生成测试数据: @tb
DECLARE @tb TABLE (id int,号码 int,机主 varchar(3),提供人 varchar(3))
INSERT INTO @tb
SELECT 1,101,'张1','李1' UNION ALL
SELECT 2,101,'张2','李2' UNION ALL
SELECT 3,102,'张3','李3' UNION ALL
SELECT 4,101,'张4','李4' UNION ALL
SELECT 5,103,'张5','李5' UNION ALL
SELECT 6,103,'张6','李6'--SQL查询如下:SELECT A.id,A.号码,
STUFF(B.x.query('/x1/text()').value('.','varchar(MAX)'),1,1,'') AS 机主,
STUFF(B.x.query('/x2/text()').value('.','varchar(MAX)'),1,1,'') AS 提供人
FROM (SELECT MIN(id) AS id,号码 FROM @tb GROUP BY 号码) AS A
CROSS APPLY (
SELECT x=(SELECT
x1='|'+机主,
x2='|'+提供人
FROM @tb
WHERE A.号码=号码
FOR XML PATH(''),TYPE)
) AS B/*
id 号码 机主 提供人
1 101 张1|张2|张4 李1|李2|李4
3 102 张3 李3
5 103 张5|张6 李5|李6
*/
-- Author :fredrickhu(小F,向高手学习)
-- Date :2009-12-20 10:12:09
-- Version:
-- Microsoft SQL Server 2005 - 9.00.4035.00 (Intel X86)
-- Nov 24 2008 13:01:59
-- Copyright (c) 1988-2005 Microsoft Corporation
-- Developer Edition on Windows NT 5.1 (Build 2600: Service Pack 3)
--
----------------------------------------------------------------
--> 测试数据:[tb]
if object_id('[tb]') is not null drop table [tb]
go
create table [tb]([id] int,[号码] int,[机主] varchar(3),[提供人] varchar(3))
insert [tb]
select 1,101,'张1','李1' union all
select 2,101,'张2','李2' union all
select 3,102,'张3','李3' union all
select 4,101,'张4','李4' union all
select 5,103,'张5','李5' union all
select 6,103,'张6','李6'
--------------开始查询--------------------------
select
号码,
[机主]=stuff((select '|'+[机主] from tb where 号码=t.号码 for xml path('')), 1, 1, ''),
[提供人]=stuff((select '|'+[提供人] from tb where 号码=t.号码 for xml path('')), 1, 1, '')
from
tb t
group by
号码
----------------结果----------------------------
/* 号码 机主 提供人
----------- ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- ----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
101 张1|张2|张4 李1|李2|李4
102 张3 李3
103 张5|张6 李5|李6(3 行受影响)*/
--*******************************************************************************************
表结构,数据如下:
id value
----- ------
1 aa
1 bb
2 aaa
2 bbb
2 ccc 需要得到结果:
id values
------ -----------
1 aa,bb
2 aaa,bbb,ccc
即:group by id, 求 value 的和(字符串相加) 1. 旧的解决方法(在sql server 2000中只能用函数解决。)
--=============================================================================
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
--1. 创建处理函数
CREATE FUNCTION dbo.f_strUnite(@id int)
RETURNS varchar(8000)
AS
BEGIN
DECLARE @str varchar(8000)
SET @str = ''
SELECT @str = @str + ',' + value FROM tb WHERE id=@id
RETURN STUFF(@str, 1, 1, '')
END
GO
-- 调用函数
SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id
drop table tb
drop function dbo.f_strUnite
go
/*
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
(所影响的行数为 2 行)
*/
--===================================================================================
2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。)
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
-- 查询处理
SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY(
SELECT [values]= STUFF(REPLACE(REPLACE(
(
SELECT value FROM tb N
WHERE id = A.id
FOR XML AUTO
), ' <N value="', ','), '"/>', ''), 1, 1, '')
)N
drop table tb /*
id values
----------- -----------
1 aa,bb
2 aaa,bbb,ccc (2 行受影响)
*/ --SQL2005中的方法2
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '')
from tb
group by id /*
id values
----------- --------------------
1 aa,bb
2 aaa,bbb,ccc (2 row(s) affected) */ drop table tb