不知道行不行---------------------------------------------------------------- -- Author :DBA_Huangzj(發糞塗牆) -- Date :2013-10-14 14:09:05 -- Version: -- Microsoft SQL Server 2014 (CTP1) - 11.0.9120.5 (X64) -- Jun 10 2013 20:09:10 -- Copyright (c) Microsoft Corporation -- Enterprise Evaluation Edition (64-bit) on Windows NT 6.2 <X64> (Build 9200: ) (Hypervisor) -- ---------------------------------------------------------------- --> 测试数据:[huang] if object_id('[huang]') is not null drop table [huang] go create table [huang]([ID] int) insert [huang] select 1 union all select 1 union all select 1 union all select 2 union all select 2 union all select 2 union all select 3 union all select 3 union all select 3 --------------开始查询--------------------------select ROW_NUMBER()OVER (PARTITION BY id ORDER BY id)id from [huang] ----------------结果---------------------------- /* id -------------------- 1 2 3 1 2 3 1 2 3 */
insert into #tab select 1 union all select 1 union all select 1 union all select 2 union all select 2 union all select 2 union all select 3 union all select 3 union all select 3select ROW_NUMBER()over(partition by id order by id)as num ,* from #tab----------------------------------------------------------------- num id -------------------- ----------- 1 1 2 1 3 1 1 2 2 2 3 2 1 3 2 3 3 3(9 行受影响) 看看这样行不行。
create table lh(ID int)insert into lh select 1 union all select 1 union all select 1 union all select 2 union all select 2 union all select 2 union all select 3 union all select 3 union all select 3 select ID, row_number() over(partition by ID order by getdate()) 'New_ID' from lh/* ID New_ID ----------- -------------------- 1 1 1 2 1 3 2 1 2 2 2 3 3 1 3 2 3 3(9 row(s) affected) */
declare @tb table ( id int )insert into @tb select 1 union all select 1 union all select 1 union all select 2 union all select 2 union all select 2 union all select 3 union all select 3 union all select 3 select id from ( select *, ROW_NUMBER() over(partition by id order by id) as rownum from @tb )a order by rownum,id /* id 1 2 3 1 2 3 1 2 3 */
这样?---------------------------------------------------------------- -- Author :DBA_Huangzj(發糞塗牆) -- Date :2013-10-14 15:21:41 -- Version: -- Microsoft SQL Server 2014 (CTP1) - 11.0.9120.5 (X64) -- Jun 10 2013 20:09:10 -- Copyright (c) Microsoft Corporation -- Enterprise Evaluation Edition (64-bit) on Windows NT 6.2 <X64> (Build 9200: ) (Hypervisor) -- ---------------------------------------------------------------- --> 测试数据:[huang] if object_id('[huang]') is not null drop table [huang] go create table [huang]([id] int) insert [huang] select 1 union all select 1 union all select 2 union all select 2 union all select 3 union all select 3 union all select 3 union all select 4 union all select 4 union all select 4 union all select 4 union all select 4 union all select 5 union all select 5 --------------开始查询--------------------------select *-- ,ROW_NUMBER() OVER (PARTITION BY id ORDER BY id) from [huang] ORDER BY ROW_NUMBER() OVER (PARTITION BY id ORDER BY id),id ----------------结果---------------------------- /* id ----------- 1 2 3 4 5 1 2 3 4 5 3 4 4 4 */
declare @tb table ( id int )insert into @tb select 1 union all select 1 union all select 2 union all select 2 union all select 3 union all select 3 union all select 3 union all select 4 union all select 4 union all select 4 union all select 4 union all select 4 union all select 5 union all select 5 /* id 1 2 3 4 5 1 2 3 4 5 3 4 4 4 */ select id from ( select *, ROW_NUMBER() over(partition by id order by id) as rownum from @tb )a order by rownum,id /* id 1 2 3 4 5 1 2 3 4 5 3 4 4 4 */
-- Author :DBA_Huangzj(發糞塗牆)
-- Date :2013-10-14 14:09:05
-- Version:
-- Microsoft SQL Server 2014 (CTP1) - 11.0.9120.5 (X64)
-- Jun 10 2013 20:09:10
-- Copyright (c) Microsoft Corporation
-- Enterprise Evaluation Edition (64-bit) on Windows NT 6.2 <X64> (Build 9200: ) (Hypervisor)
--
----------------------------------------------------------------
--> 测试数据:[huang]
if object_id('[huang]') is not null drop table [huang]
go
create table [huang]([ID] int)
insert [huang]
select 1 union all
select 1 union all
select 1 union all
select 2 union all
select 2 union all
select 2 union all
select 3 union all
select 3 union all
select 3
--------------开始查询--------------------------select ROW_NUMBER()OVER (PARTITION BY id ORDER BY id)id
from [huang]
----------------结果----------------------------
/*
id
--------------------
1
2
3
1
2
3
1
2
3
*/
insert into #tab
select 1 union all
select 1 union all
select 1 union all
select 2 union all
select 2 union all
select 2 union all
select 3 union all
select 3 union all
select 3select ROW_NUMBER()over(partition by id order by id)as num
,* from #tab-----------------------------------------------------------------
num id
-------------------- -----------
1 1
2 1
3 1
1 2
2 2
3 2
1 3
2 3
3 3(9 行受影响)
看看这样行不行。
create table lh(ID int)insert into lh
select 1 union all
select 1 union all
select 1 union all
select 2 union all
select 2 union all
select 2 union all
select 3 union all
select 3 union all
select 3
select ID,
row_number() over(partition by ID order by getdate()) 'New_ID'
from lh/*
ID New_ID
----------- --------------------
1 1
1 2
1 3
2 1
2 2
2 3
3 1
3 2
3 3(9 row(s) affected)
*/
declare @tb table
(
id int
)insert into @tb
select 1 union all
select 1 union all
select 1 union all
select 2 union all
select 2 union all
select 2 union all
select 3 union all
select 3 union all
select 3
select id
from
(
select *,
ROW_NUMBER() over(partition by id order by id) as rownum
from @tb
)a
order by rownum,id
/*
id
1
2
3
1
2
3
1
2
3
*/
-- Author :DBA_Huangzj(發糞塗牆)
-- Date :2013-10-14 15:21:41
-- Version:
-- Microsoft SQL Server 2014 (CTP1) - 11.0.9120.5 (X64)
-- Jun 10 2013 20:09:10
-- Copyright (c) Microsoft Corporation
-- Enterprise Evaluation Edition (64-bit) on Windows NT 6.2 <X64> (Build 9200: ) (Hypervisor)
--
----------------------------------------------------------------
--> 测试数据:[huang]
if object_id('[huang]') is not null drop table [huang]
go
create table [huang]([id] int)
insert [huang]
select 1 union all
select 1 union all
select 2 union all
select 2 union all
select 3 union all
select 3 union all
select 3 union all
select 4 union all
select 4 union all
select 4 union all
select 4 union all
select 4 union all
select 5 union all
select 5
--------------开始查询--------------------------select *-- ,ROW_NUMBER() OVER (PARTITION BY id ORDER BY id)
from [huang]
ORDER BY ROW_NUMBER() OVER (PARTITION BY id ORDER BY id),id
----------------结果----------------------------
/*
id
-----------
1
2
3
4
5
1
2
3
4
5
3
4
4
4
*/
declare @tb table
(
id int
)insert into @tb
select 1 union all
select 1 union all
select 2 union all
select 2 union all
select 3 union all
select 3 union all
select 3 union all
select 4 union all
select 4 union all
select 4 union all
select 4 union all
select 4 union all
select 5 union all
select 5
/*
id
1
2
3
4
5
1
2
3
4
5
3
4
4
4
*/
select id
from
(
select *,
ROW_NUMBER() over(partition by id order by id) as rownum
from @tb
)a
order by rownum,id
/*
id
1
2
3
4
5
1
2
3
4
5
3
4
4
4
*/