相关的系统表,-- 索引 select * from sys.indexes-- schema select * from sys.schemas-- 作业 select * from msdb.dbo.sysjobs
-- 查询所有索引及所在的表名 select a.name 'TableName', b.name 'IndexName' from sys.tables a inner join sys.indexes b on a.[object_id]=b.[object_id] where b.index_id>0 order by a.name
索引及主键信息 -- ======================================================================== -- 索引及主键信息 -- 邹建 2005.08(引用请保留此信息) -- ======================================================================== SELECT TableId=O.[object_id], TableName=O.Name, IndexId=ISNULL(KC.[object_id],IDX.index_id), IndexName=IDX.Name, IndexType=ISNULL(KC.type_desc,'Index'), Index_Column_id=IDXC.index_column_id, ColumnID=C.Column_id, ColumnName=C.Name, Sort=CASE INDEXKEY_PROPERTY(IDXC.[object_id],IDXC.index_id,IDXC.index_column_id,'IsDescending') WHEN 1 THEN 'DESC' WHEN 0 THEN 'ASC' ELSE '' END, PrimaryKey=CASE WHEN IDX.is_primary_key=1 THEN N'√'ELSE N'' END, [UQIQUE]=CASE WHEN IDX.is_unique=1 THEN N'√'ELSE N'' END, Ignore_dup_key=CASE WHEN IDX.ignore_dup_key=1 THEN N'√'ELSE N'' END, Disabled=CASE WHEN IDX.is_disabled=1 THEN N'√'ELSE N'' END, Fill_factor=IDX.fill_factor, Padded=CASE WHEN IDX.is_padded=1 THEN N'√'ELSE N'' END FROM sys.indexes IDX INNER JOIN sys.index_columns IDXC ON IDX.[object_id]=IDXC.[object_id] AND IDX.index_id=IDXC.index_id LEFT JOIN sys.key_constraints KC ON IDX.[object_id]=KC.[parent_object_id] AND IDX.index_id=KC.unique_index_id INNER JOIN sys.objects O ON O.[object_id]=IDX.[object_id] INNER JOIN sys.columns C ON O.[object_id]=C.[object_id] AND O.type='U' AND O.is_ms_shipped=0 AND IDXC.Column_id=C.Column_id -- INNER JOIN -- 对于一个列包含多个索引的情况,只显示第1个索引信息 -- ( -- SELECT [object_id], Column_id, index_id=MIN(index_id) -- FROM sys.index_columns -- GROUP BY [object_id], Column_id -- ) IDXCUQ -- ON IDXC.[object_id]=IDXCUQ.[object_id] -- AND IDXC.Column_id=IDXCUQ.Column_id
JOB的没有去拼 应该也是差不多的
-- 1.表字段是否为自增列 select a.name 'TableName', b.name 'IndexName', b.is_identity '是否为自增列' from sys.tables a inner join sys.columns b on a.object_id=b.object_id-- 2.用户自定义类型 select * from sys.types where is_user_defined=1
1. select CASE WHEN is_identity=1 THEN '是自增列' ELSE '不是' END from sys.columns WHERE name='xxx' 2. select * from information_schema.domains
select * from sys.indexes-- schema
select * from sys.schemas-- 作业
select * from msdb.dbo.sysjobs
-- 查询所有索引及所在的表名
select a.name 'TableName',
b.name 'IndexName'
from sys.tables a
inner join sys.indexes b on a.[object_id]=b.[object_id]
where b.index_id>0
order by a.name
-- ========================================================================
-- 索引及主键信息
-- 邹建 2005.08(引用请保留此信息)
-- ========================================================================
SELECT
TableId=O.[object_id],
TableName=O.Name,
IndexId=ISNULL(KC.[object_id],IDX.index_id),
IndexName=IDX.Name,
IndexType=ISNULL(KC.type_desc,'Index'),
Index_Column_id=IDXC.index_column_id,
ColumnID=C.Column_id,
ColumnName=C.Name,
Sort=CASE INDEXKEY_PROPERTY(IDXC.[object_id],IDXC.index_id,IDXC.index_column_id,'IsDescending')
WHEN 1 THEN 'DESC' WHEN 0 THEN 'ASC' ELSE '' END,
PrimaryKey=CASE WHEN IDX.is_primary_key=1 THEN N'√'ELSE N'' END,
[UQIQUE]=CASE WHEN IDX.is_unique=1 THEN N'√'ELSE N'' END,
Ignore_dup_key=CASE WHEN IDX.ignore_dup_key=1 THEN N'√'ELSE N'' END,
Disabled=CASE WHEN IDX.is_disabled=1 THEN N'√'ELSE N'' END,
Fill_factor=IDX.fill_factor,
Padded=CASE WHEN IDX.is_padded=1 THEN N'√'ELSE N'' END
FROM sys.indexes IDX
INNER JOIN sys.index_columns IDXC
ON IDX.[object_id]=IDXC.[object_id]
AND IDX.index_id=IDXC.index_id
LEFT JOIN sys.key_constraints KC
ON IDX.[object_id]=KC.[parent_object_id]
AND IDX.index_id=KC.unique_index_id
INNER JOIN sys.objects O
ON O.[object_id]=IDX.[object_id]
INNER JOIN sys.columns C
ON O.[object_id]=C.[object_id]
AND O.type='U'
AND O.is_ms_shipped=0
AND IDXC.Column_id=C.Column_id
-- INNER JOIN -- 对于一个列包含多个索引的情况,只显示第1个索引信息
-- (
-- SELECT [object_id], Column_id, index_id=MIN(index_id)
-- FROM sys.index_columns
-- GROUP BY [object_id], Column_id
-- ) IDXCUQ
-- ON IDXC.[object_id]=IDXCUQ.[object_id]
-- AND IDXC.Column_id=IDXCUQ.Column_id
-- 1.表字段是否为自增列
select a.name 'TableName',
b.name 'IndexName',
b.is_identity '是否为自增列'
from sys.tables a
inner join sys.columns b on a.object_id=b.object_id-- 2.用户自定义类型
select * from sys.types where is_user_defined=1
2. select * from information_schema.domains
msdb下
几个系统表查询
msdb.dbo.sysjobs
msdb.dbo.sysjobschedules
msdb.dbo.sysjobhistory
msdb.dbo.sysjobservers
msdb.dbo.sysjobsteps
等等
这个得看:select * from sys.columns 视图