上面的格式乱了, 整理如下:
F1 F2 F3 F4
----------------------------
1 1 56 01,02,03,04
1 13 56 01
1 1 57 01,07,08
1 2 57 03
1 13 57 01,02
1 1 58 01,07,08
1 13 58 08
1 1 59 01,02,03,04,07,08
1 1 60 01,02,03,04,07,08 要求不可使用用游标,合并后的结果如下:
F1 F3 F4
-----------------------------
1 56 01,02,03,04
1 57 01,02,03,07,08
1 58 01,07,08
1 59 01,02,03,04,07,08
1 60 01,02,03,04,07,08
F1 F2 F3 F4
----------------------------
1 1 56 01,02,03,04
1 13 56 01
1 1 57 01,07,08
1 2 57 03
1 13 57 01,02
1 1 58 01,07,08
1 13 58 08
1 1 59 01,02,03,04,07,08
1 1 60 01,02,03,04,07,08 要求不可使用用游标,合并后的结果如下:
F1 F3 F4
-----------------------------
1 56 01,02,03,04
1 57 01,02,03,07,08
1 58 01,07,08
1 59 01,02,03,04,07,08
1 60 01,02,03,04,07,08
-- 合并列值
--******************************************************************
表结构,数据如下:
id value
----- ------
1 aa
1 bb
2 aaa
2 bbb
2 ccc 需要得到结果:
id values
------ -----------
1 aa,bb
2 aaa,bbb,ccc
即:group by id, 求 value 的和(字符串相加) 1. 旧的解决方法(在sql server 2000中只能用函数解决。)
--===================================================================
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
--1. 创建处理函数
CREATE FUNCTION dbo.f_strUnite(@id int)
RETURNS varchar(8000)
AS
BEGIN
DECLARE @str varchar(8000)
SET @str = ''
SELECT @str = @str + ',' + value FROM tb WHERE id=@id
RETURN STUFF(@str, 1, 1, '')
END
GO
-- 调用函数
SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id
drop table tb
drop function dbo.f_strUnite
go
/*
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
(所影响的行数为 2 行)
*/
--===================================================================================
2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。)
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
-- 查询处理
SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY(
SELECT [values]= STUFF(REPLACE(REPLACE(
(
SELECT value FROM tb N
WHERE id = A.id
FOR XML AUTO
), ' <N value="', ','), '"/>', ''), 1, 1, '')
)N
drop table tb /*
id values
----------- -----------
1 aa,bb
2 aaa,bbb,ccc (2 行受影响)
*/ --SQL2005中的方法2
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go select id, [values]=stuff((select ','+[value] from tb t where id=tb.id
for xml path('')), 1, 1, '')
from tb
group by id /*
id values
----------- --------------------
1 aa,bb
2 aaa,bbb,ccc (2 row(s) affected) */ drop table tb
DROP TABLE LI
GOCREATE TABLE LI (F1 INT, F2 INT,F3 INT,F4 VARCHAR(50))
INSERT INTO LI (F1,F2,F3,F4)
SELECT 1,1,56,'01,02,03,04' UNION ALL
SELECT 1, 13, 56, '01' UNION ALL
SELECT 1, 1, 57, '01,07,08' UNION ALL
SELECT 1, 2, 57, '03' UNION ALL
SELECT 1, 13, 57, '01,02' UNION ALL
SELECT 1, 1, 58, '01,07,08' UNION ALL
SELECT 1, 13, 58, '08' UNION ALL
SELECT 1, 1, 59, '01,02,03,04,07,08' UNION ALL
SELECT 1, 1, 60, '01,02,03,04,07,08' --创建过滤函数
CREATE FUNCTION dbo.F_GetStr(@F4 nvarchar(30))
returns nvarchar(50)
as
begin
declare @str nvarchar(50),@temp nvarchar(30)
set @str=''
set @temp=''
while charindex(',', @F4+',')>0
begin
set @temp=left(@F4, charindex(',', @F4+',')-1)
if charindex(','+@temp+',', ','+@str+',')=0
set @str=@str+','+@temp
set @F4=stuff(@F4, 1, charindex(',', @F4+','), '')
end
return stuff(@str, 1, 1, '')
end
go--聚合操作语句
;WITH TLI AS
(
SELECT A.F1,A.F3,N.F4LIST FROM(
SELECT DISTINCT F1,F3 FROM LI
)A OUTER APPLY(
SELECT [F4LIST]= STUFF(REPLACE(REPLACE(
(
SELECT F4 FROM LI N
WHERE F1 = A.F1 AND F3 = A.F3
FOR XML AUTO
), '<N F4="', ','), '"/>', ''), 1, 1, '')
)N )--最终结果
select F1,F3,dbo.F_GetStr(F4LIST) AS F4
From TLI/* 结果
F1 F3 F4
1 56 01,02,03,04
1 57 01,07,08,03,02
1 58 01,07,08
1 59 01,02,03,04,07,08
1 60 01,02,03,04,07,08
*/
create function dbo.combine(@F1 int,@F3 int)
returns nvarchar(50)
as
begin
declare @s varchar(8000)set @s = ''
select
@s = @s + ',' + F4
from ta
where F1 = @F1 and F3 = @F3set @s = @s + ','declare @str nvarchar(50) --据俄国字符串
declare @value nvarchar(30)--要筛选的值set @str=''
set @value=''while charindex( ',', @s)>0
begin
--取得要筛选的值
set @value=left(@s, charindex(',', @s+',')-1) --如果在动态结果字符串中不存在
if charindex(',' + @value +',',','+@str+',') = 0
begin
set @str=@str + ',' + @value--赋值
end set @s=stuff(@s, 1, charindex(',', @s+','), '')
endreturn stuff(@str,1,1,'')
end
go
--
create table ta
(
F1 int,
F2 int,
F3 int,
F4 varchar(8000)
)insert into taselect 1, 1, 56, '01,02,03,04' union all
select 1, 13, 56 ,'01' union all
select 1, 1, 57, '01,07,08' union all
select 1, 2, 57, '03' union all
select 1, 13, 57, '01,02' union all
select 1, 1, 58, '01,07,08' union all
select 1, 13, 58, '08' union all
select 1, 1, 59, '01,02,03,04,07,08' union all
select 1 , 1, 60, '01,02,03,04,07,08' select
F1,
F3,
F4 =dbo.combine(F1,F3)
from ta
group by F1,F3drop table ta结果:
1 56 01,02,03,04
1 57 01,07,08,03,02
1 58 01,07,08
1 59 01,02,03,04,07,08
1 60 01,02,03,04,07,08
首先谢谢大家的回复!
因没有SQL2005环境, 所以涉及到SQL2005的代码没有测试.hyde100 的代码可行. 只是有个新的需求解决不了, 请指点!
新的需求:
指定F2的值, 对F3相同的记录,合并F4的值.原始记录:
F1 F2 F3 F4
----------------------------
1 1 56 01,02,03,04
1 13 56 01
1 1 57 01,07,08
1 2 57 03
1 13 57 01,02
1 1 58 01,07,08
1 13 58 08
1 1 59 01,02,03,04,07,08
1 1 60 01,02,03,04,07,08 结果1, 合并F2=1的记录:
F1 F3 F4
----------------------------
1 56 01,02,03,04
1 57 01,07,08
1 58 01,07,08
1 59 01,02,03,04,07,08
1 60 01,02,03,04,07,08 结果2, 合并F2=1,13的记录:
F1 F3 F4
---------------------------
1 56 01,02,03,04
1 57 01,02,07,08
1 58 01,07,08
1 59 01,02,03,04,07,08
1 60 01,02,03,04,07,08 结果3, 合并F2=1,2,13的记录:
F1 F3 F4
---------------------------
1 56 01,02,03,04
1 57 01,02,03,07,08
1 58 01,07,08
1 59 01,02,03,04,07,08
1 60 01,02,03,04,07,08