---使用自定义函数:dbo.fn_ChangeBigSmall()select [name], sum(case gzx when '基本工资' then je end) as 基本工资, dbo.fn_ChangeBigSmall(sum(case gzx when '基本工资' then je end)) as 基本工资2, sum(case gzx when '奖金' then je end) as 奖金, dbo.fn_ChangeBigSmall(sum(case gzx when '奖金' then je end)) As 奖金2 from ygbd group by [name] --以下是自定义函数:金额小写转大写CREATE FUNCTION fn_ChangeBigSmall (@ChangeMoney money) RETURNS VarChar(100) AS BEGIN Declare @String1 char(20) Declare @String2 char(30) Declare @String4 Varchar(100) Declare @String3 Varchar(100) --从原A值中取出的值 Declare @i int --循环变量 Declare @J Int --A的值乘以100的字符串长度 Declare @Ch1 Varchar(100) --数字的汉语读法 Declare @Ch2 Varchar(100) --数字位的汉字读法 Declare @Zero Int --用来计算连续有几个零 Declare @ReturnValue VarChar(100) Select @ReturnValue = '' Select @String1 = '零壹贰叁肆伍陆柒捌玖' Select @String2 = '万仟佰拾亿仟佰拾万仟佰拾元角分' Select @String4 = Cast(@ChangeMoney*100 as int) select @J=len(cast((@ChangeMoney*100) as int)) Select @String2=Right(@String2,@J) Select @i = 1 while @i<= @j Begin Select @String3 = Substring(@String4,@i,1) if @String3<>'0' Begin Select @Ch1 = Substring(@String1, Cast(@String3 as Int) + 1, 1) Select @Ch2 = Substring(@String2, @i, 1) Select @Zero = 0 --表示本位不为零 end else Begin If (@Zero = 0) Or (@i = @J - 9) Or (@i = @J - 5) Or (@i = @J - 1) Select @Ch1 = '零' Else Select @Ch1 = '' Select @Zero = @Zero + 1 --表示本位为0
--如果转换的数值需要扩大,那么需改动以下表达式 I 的值。 Select @Ch2 = '' If @i = @J - 10 Begin Select @Ch2 = '亿' Select @Zero = 0 end
If @i = @J - 6 Begin Select @Ch2 = '万' Select @Zero = 0 end
if @i = @J - 2 Begin Select @Ch2 = '元' Select @Zero = 0 end
If @i = @J Select @Ch2 = '整'
end Select @ReturnValue = @ReturnValue + @Ch1 + @Ch2 select @i = @i+1 end --最后将多余的零去掉 If CharIndex('仟仟',@ReturnValue) <> 0 Select @ReturnValue = Replace(@ReturnValue, '仟仟', '仟') If CharIndex('佰佰',@ReturnValue) <> 0 Select @ReturnValue = Replace(@ReturnValue, '佰佰', '佰') If CharIndex('零元',@ReturnValue) <> 0 Select @ReturnValue = Replace(@ReturnValue, '零元', '元')
If CharIndex('零万',@ReturnValue) <> 0 Select @ReturnValue = Replace(@ReturnValue, '零万', '万')
If CharIndex('零亿',@ReturnValue) <> 0 Select @ReturnValue = Replace(@ReturnValue, '零亿', '亿')
If CharIndex('零整',@ReturnValue) <> 0 Select @ReturnValue = Replace(@ReturnValue, '零整', '整')
If CharIndex('零佰',@ReturnValue) <> 0 Select @ReturnValue = Replace(@ReturnValue, '零佰', '零') If CharIndex('零仟',@ReturnValue) <> 0 Select @ReturnValue = Replace(@ReturnValue, '零仟', '零') If CharIndex('元元',@ReturnValue) <> 0 Select @ReturnValue = Replace(@ReturnValue, '元元', '元') return @ReturnValueEND go
[name],
sum(case gzx when '基本工资' then je end) as 基本工资,
dbo.fn_ChangeBigSmall(sum(case gzx when '基本工资' then je end)) as 基本工资2,
sum(case gzx when '奖金' then je end) as 奖金,
dbo.fn_ChangeBigSmall(sum(case gzx when '奖金' then je end)) As 奖金2
from ygbd
group by [name]
--以下是自定义函数:金额小写转大写CREATE FUNCTION fn_ChangeBigSmall
(@ChangeMoney money)
RETURNS VarChar(100) AS BEGIN
Declare @String1 char(20)
Declare @String2 char(30)
Declare @String4 Varchar(100)
Declare @String3 Varchar(100) --从原A值中取出的值
Declare @i int --循环变量
Declare @J Int --A的值乘以100的字符串长度
Declare @Ch1 Varchar(100) --数字的汉语读法
Declare @Ch2 Varchar(100) --数字位的汉字读法
Declare @Zero Int --用来计算连续有几个零
Declare @ReturnValue VarChar(100) Select @ReturnValue = ''
Select @String1 = '零壹贰叁肆伍陆柒捌玖'
Select @String2 = '万仟佰拾亿仟佰拾万仟佰拾元角分' Select @String4 = Cast(@ChangeMoney*100 as int) select @J=len(cast((@ChangeMoney*100) as int)) Select @String2=Right(@String2,@J) Select @i = 1 while @i<= @j Begin Select @String3 = Substring(@String4,@i,1) if @String3<>'0' Begin Select @Ch1 = Substring(@String1, Cast(@String3 as Int) + 1, 1)
Select @Ch2 = Substring(@String2, @i, 1)
Select @Zero = 0 --表示本位不为零
end
else Begin
If (@Zero = 0) Or (@i = @J - 9) Or (@i = @J - 5) Or (@i = @J - 1)
Select @Ch1 = '零'
Else
Select @Ch1 = '' Select @Zero = @Zero + 1 --表示本位为0
--如果转换的数值需要扩大,那么需改动以下表达式 I 的值。
Select @Ch2 = '' If @i = @J - 10 Begin
Select @Ch2 = '亿'
Select @Zero = 0
end
If @i = @J - 6 Begin
Select @Ch2 = '万'
Select @Zero = 0
end
if @i = @J - 2 Begin
Select @Ch2 = '元'
Select @Zero = 0
end
If @i = @J
Select @Ch2 = '整'
end Select @ReturnValue = @ReturnValue + @Ch1 + @Ch2 select @i = @i+1
end --最后将多余的零去掉
If CharIndex('仟仟',@ReturnValue) <> 0
Select @ReturnValue = Replace(@ReturnValue, '仟仟', '仟') If CharIndex('佰佰',@ReturnValue) <> 0
Select @ReturnValue = Replace(@ReturnValue, '佰佰', '佰') If CharIndex('零元',@ReturnValue) <> 0
Select @ReturnValue = Replace(@ReturnValue, '零元', '元')
If CharIndex('零万',@ReturnValue) <> 0
Select @ReturnValue = Replace(@ReturnValue, '零万', '万')
If CharIndex('零亿',@ReturnValue) <> 0
Select @ReturnValue = Replace(@ReturnValue, '零亿', '亿')
If CharIndex('零整',@ReturnValue) <> 0
Select @ReturnValue = Replace(@ReturnValue, '零整', '整')
If CharIndex('零佰',@ReturnValue) <> 0
Select @ReturnValue = Replace(@ReturnValue, '零佰', '零') If CharIndex('零仟',@ReturnValue) <> 0
Select @ReturnValue = Replace(@ReturnValue, '零仟', '零') If CharIndex('元元',@ReturnValue) <> 0
Select @ReturnValue = Replace(@ReturnValue, '元元', '元') return @ReturnValueEND
go