select * from tablename a where ( select count(*) from tablename where sex=a.sex and age=a.age )>1
--三列相同 select name , sex , age from tb group by name , sex , age having count(*) > 1--name , sex 相同 select m.* from tb m where exists (select 1 from ( select name , sex from tb group by name , sex having count(*) > 1 ) n where n.name = m.name and n.sex = n.sex )
if not object_id('Tempdb..#T') is null drop table #T Go Create table #T([ID] int,[Name] nvarchar(1),[Memo] nvarchar(2)) Insert #T select 1,N'A',N'A1' union all select 2,N'A',N'A2' union all select 3,N'A',N'A3' union all select 4,N'B',N'B1' union all select 5,N'B',N'B2' Go --I、Name相同ID最小的记录(推荐用1,2,3),方法3在SQl05时,效率高于1、2 方法1: Select * from #T a where not exists(select 1 from #T where Name=a.Name and ID<a.ID)方法2: select a.* from #T a join (select min(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID方法3: select * from #T a where ID=(select min(ID) from #T where Name=a.Name)方法4: select a.* from #T a join #T b on a.Name=b.Name and a.ID>=b.ID group by a.ID,a.Name,a.Memo having count(1)=1 方法5: select * from #T a group by ID,Name,Memo having ID=(select min(ID)from #T where Name=a.Name)方法6: select * from #T a where (select count(1) from #T where Name=a.Name and ID<a.ID)=0方法7: select * from #T a where ID=(select top 1 ID from #T where Name=a.name order by ID)方法8: select * from #T a where ID!>all(select ID from #T where Name=a.Name)方法9(注:ID为唯一时可用): select * from #T a where ID in(select min(ID) from #T group by Name)--SQL2005:方法10: select ID,Name,Memo from (select *,min(ID)over(partition by Name) as MinID from #T a)T where ID=MinID方法11:select ID,Name,Memo from (select *,row_number()over(partition by Name order by ID) as MinID from #T a)T where MinID=1生成结果: /* ID Name Memo ----------- ---- ---- 1 A A1 4 B B1(2 行受影响) */ --II、Name相同ID最大的记录,与min相反: 方法1: Select * from #T a where not exists(select 1 from #T where Name=a.Name and ID>a.ID)方法2: select a.* from #T a join (select max(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID order by ID方法3: select * from #T a where ID=(select max(ID) from #T where Name=a.Name) order by ID方法4: select a.* from #T a join #T b on a.Name=b.Name and a.ID<=b.ID group by a.ID,a.Name,a.Memo having count(1)=1 方法5: select * from #T a group by ID,Name,Memo having ID=(select max(ID)from #T where Name=a.Name)方法6: select * from #T a where (select count(1) from #T where Name=a.Name and ID>a.ID)=0方法7: select * from #T a where ID=(select top 1 ID from #T where Name=a.name order by ID desc)方法8: select * from #T a where ID!<all(select ID from #T where Name=a.Name)方法9(注:ID为唯一时可用): select * from #T a where ID in(select max(ID) from #T group by Name)--SQL2005:方法10: select ID,Name,Memo from (select *,max(ID)over(partition by Name) as MinID from #T a)T where ID=MinID方法11: select ID,Name,Memo from (select *,row_number()over(partition by Name order by ID desc) as MinID from #T a)T where MinID=1生成结果2: /* ID Name Memo ----------- ---- ---- 3 A A3 5 B B2(2 行受影响) */--2、删除重复记录有大小关系时,保留大或小其中一个记录 --> --> (Roy)生成測試數據if not object_id('Tempdb..#T') is null drop table #T Go Create table #T([ID] int,[Name] nvarchar(1),[Memo] nvarchar(2)) Insert #T select 1,N'A',N'A1' union all select 2,N'A',N'A2' union all select 3,N'A',N'A3' union all select 4,N'B',N'B1' union all select 5,N'B',N'B2' Go--I、Name相同ID最小的记录(推荐用1,2,3),保留最小一条 方法1: delete a from #T a where exists(select 1 from #T where Name=a.Name and ID<a.ID)方法2: delete a from #T a left join (select min(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID where b.Id is null方法3: delete a from #T a where ID not in (select min(ID) from #T where Name=a.Name)方法4(注:ID为唯一时可用): delete a from #T a where ID not in(select min(ID)from #T group by Name)方法5: delete a from #T a where (select count(1) from #T where Name=a.Name and ID<a.ID)>0方法6: delete a from #T a where ID<>(select top 1 ID from #T where Name=a.name order by ID)方法7: delete a from #T a where ID>any(select ID from #T where Name=a.Name)select * from #T生成结果: /* ID Name Memo ----------- ---- ---- 1 A A1 4 B B1(2 行受影响) */ --II、Name相同ID保留最大的一条记录:方法1: delete a from #T a where exists(select 1 from #T where Name=a.Name and ID>a.ID)方法2: delete a from #T a left join (select max(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID where b.Id is null方法3: delete a from #T a where ID not in (select max(ID) from #T where Name=a.Name)方法4(注:ID为唯一时可用): delete a from #T a where ID not in(select max(ID)from #T group by Name)方法5: delete a from #T a where (select count(1) from #T where Name=a.Name and ID>a.ID)>0方法6: delete a from #T a where ID<>(select top 1 ID from #T where Name=a.name order by ID desc)方法7: delete a from #T a where ID<any(select ID from #T where Name=a.Name) select * from #T /* ID Name Memo ----------- ---- ---- 3 A A3 5 B B2(2 行受影响) */--3、删除重复记录没有大小关系时,处理重复值 --> --> (Roy)生成測試數據
if not object_id('Tempdb..#T') is null drop table #T Go Create table #T([Num] int,[Name] nvarchar(1)) Insert #T select 1,N'A' union all select 1,N'A' union all select 1,N'A' union all select 2,N'B' union all select 2,N'B' Go方法1: if object_id('Tempdb..#') is not null drop table # Select distinct * into # from #T--排除重复记录结果集生成临时表#truncate table #T--清空表insert #T select * from # --把临时表#插入到表#T中--查看结果 select * from #T/* Num Name ----------- ---- 1 A 2 B(2 行受影响) */--重新执行测试数据后用方法2 方法2:alter table #T add ID int identity--新增标识列 go delete a from #T a where exists(select 1 from #T where Num=a.Num and Name=a.Name and ID>a.ID)--只保留一条记录 go alter table #T drop column ID--删除标识列--查看结果 select * from #T/* Num Name ----------- ---- 1 A 2 B(2 行受影响)*/--重新执行测试数据后用方法3 方法3: declare Roy_Cursor cursor local for select count(1)-1,Num,Name from #T group by Num,Name having count(1)>1 declare @con int,@Num int,@Name nvarchar(1) open Roy_Cursor fetch next from Roy_Cursor into @con,@Num,@Name while @@Fetch_status=0 begin set rowcount @con; delete #T where Num=@Num and Name=@Name set rowcount 0; fetch next from Roy_Cursor into @con,@Num,@Name end close Roy_Cursor deallocate Roy_Cursor--查看结果 select * from #T /* Num Name ----------- ---- 1 A 2 B(2 行受影响) */
select a.* from 表 a, (select * from 表 where group by name,sex,age having count(*)>1) b where a.name=b.name and a.sex=b.sex and a.age=b.age
select name , sex , age from 表 grou by name , sex , age having count(1)>1
create table tb(name varchar(10) , sex varchar(10) , age int) insert into tb values('A' , 'M' , 17 ) insert into tb values('B' , 'M' , 22 ) insert into tb values('A' , 'F' , 67 ) insert into tb values('A' , 'M' , 17 ) go--三列相同 select name , sex , age from tb group by name , sex , age having count(*) > 1 /* name sex age ---------- ---------- ----------- A M 17(所影响的行数为 1 行) */--name , sex 相同 select m.* from tb m where exists (select 1 from ( select name , sex from tb group by name , sex having count(*) > 1 ) n where n.name = m.name and n.sex = m.sex )/* name sex age ---------- ---------- ----------- A M 17 A M 17(所影响的行数为 2 行) */drop table tb
select A.* from tb A where exists (select 1 from(select name , sex from tb group by name , sex having count(*) > 1) B where B.name = A.name and B.sex = B.sex)
--如果需要显示所有记录。 create table tb(name varchar(10) , sex varchar(10) , age int) insert into tb values('A' , 'M' , 17 ) insert into tb values('B' , 'M' , 22 ) insert into tb values('A' , 'F' , 67 ) insert into tb values('A' , 'M' , 17 ) go--三列相同 select m.* from tb m where exists (select 1 from ( select name , sex , age from tb group by name , sex , age having count(*) > 1 ) n where n.name = m.name and n.sex = m.sex and n.age = m.age ) /* name sex age ---------- ---------- ----------- A M 17 A M 17(所影响的行数为 2 行) */--name , sex 相同 select m.* from tb m where exists (select 1 from ( select name , sex from tb group by name , sex having count(*) > 1 ) n where n.name = m.name and n.sex = m.sex )/* name sex age ---------- ---------- ----------- A M 17 A M 17(所影响的行数为 2 行) */drop table tb
不好写 只会写那种针对特定对象的查询 例: select * from table where name=A and sex=M下面这句是我的想法 SELECT * FROM table WHERE (name = A) AND (sex = M) OR (name = A) AND (age = 17) OR (sex = M) AND (age = 17) OR (name = A) AND (sex = M) AND (age = 17)
老大~~ 不行啊,报group附近有语法错误
老大~~ 报的是having附近有语法错误....我的环境是sqlserver 2000
--沒錯誤Y select [name] , sex , age from tb group by [name] , sex , age having count(*) > 1
---测试数据--- if object_id('[tb]') is not null drop table [tb] go create table [tb]([name] varchar(1),[sex] varchar(1),[age] int) insert [tb] select 'A','M',17 union all select 'B','M',22 union all select 'A','F',67 union all select 'A','M',17 ---查询--- select * from [tb] t where (select count(1) from tb where sex=t.sex and age=t.age)>1---结果--- name sex age ---- ---- ----------- A M 17 A M 17(所影响的行数为 2 行)
SELECT * FROM reporter_information ORDER BY reporter_name , reporter_provin HAVING (COUNT(*) > 1)这么写的~~ reporter_information是我的表呵呵,我不是想把重复的去掉再显示~~ 我是想只显示出这些重复的~~ 方便我看一下再删~~5楼好像实现的是把重复的去掉的效果~~各位老大~~ 多谢
老大~~ 按您说的我写成SELECT * FROM reporter_information t WHERE ((SELECT COUNT(1) FROM reporter_information WHERE reporter_name = t.reporter_name AND reporter_provin = t.reporter_provin) > 1)然后报列名reporter_provin无效.....帮我看看~~ 多谢~~
SELECT * FROM reporter_information WHERE ((SELECT COUNT(1) FROM reporter_information t WHERE reporter_name = t.reporter_name AND reporter_provin = t.reporter_provin) > 1)
select a.* from #T a, (select * from #T group by [name],sex,age having count(*)>1) b where a.[name]=b.[name] and a.sex=b.sex and a.age=b.age 这样也可以吧...
楼上的老大~~ 多谢~~ 我明早一到office就试试~~ 多谢多谢~~
select name ,sex ,age from 表 group by name,sex,age having count(1)>=2
select * from tb t where (select count(1) from tb where sex=t.sex and age=t.age)>1
create table tb(name varchar(10) , sex varchar(10) , age int) insert into tb values('A' , 'M' , 17 ) insert into tb values('B' , 'M' , 22 ) insert into tb values('A' , 'F' , 67 ) insert into tb values('A' , 'M' , 17 ) goselect * from tb a where exists (select 1 from (select * from tb group by name,sex,age having count(*)>1) b where b.name=a.name and b.sex=a.sex and b.age=a.age)drop table tb
where (
select count(*) from tablename
where sex=a.sex and age=a.age
)>1
select name , sex , age from tb group by name , sex , age having count(*) > 1--name , sex 相同
select m.* from tb m where exists (select 1 from
(
select name , sex from tb group by name , sex having count(*) > 1
) n where n.name = m.name and n.sex = n.sex
)
/******************************************************************************************************************************************************
1、Num、Name相同的重复值记录,没有大小关系只保留一条
2、Name相同,ID有大小关系时,保留大或小其中一个记录
整理人:中国风(Roy)日期:2008.06.06
******************************************************************************************************************************************************/--1、用于查询重复处理记录(如果列没有大小关系时2000用生成自增列和临时表处理,SQL2005用row_number函数处理)--> --> (Roy)生成測試數據
if not object_id('Tempdb..#T') is null
drop table #T
Go
Create table #T([ID] int,[Name] nvarchar(1),[Memo] nvarchar(2))
Insert #T
select 1,N'A',N'A1' union all
select 2,N'A',N'A2' union all
select 3,N'A',N'A3' union all
select 4,N'B',N'B1' union all
select 5,N'B',N'B2'
Go
--I、Name相同ID最小的记录(推荐用1,2,3),方法3在SQl05时,效率高于1、2
方法1:
Select * from #T a where not exists(select 1 from #T where Name=a.Name and ID<a.ID)方法2:
select a.* from #T a join (select min(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID方法3:
select * from #T a where ID=(select min(ID) from #T where Name=a.Name)方法4:
select a.* from #T a join #T b on a.Name=b.Name and a.ID>=b.ID group by a.ID,a.Name,a.Memo having count(1)=1 方法5:
select * from #T a group by ID,Name,Memo having ID=(select min(ID)from #T where Name=a.Name)方法6:
select * from #T a where (select count(1) from #T where Name=a.Name and ID<a.ID)=0方法7:
select * from #T a where ID=(select top 1 ID from #T where Name=a.name order by ID)方法8:
select * from #T a where ID!>all(select ID from #T where Name=a.Name)方法9(注:ID为唯一时可用):
select * from #T a where ID in(select min(ID) from #T group by Name)--SQL2005:方法10:
select ID,Name,Memo from (select *,min(ID)over(partition by Name) as MinID from #T a)T where ID=MinID方法11:select ID,Name,Memo from (select *,row_number()over(partition by Name order by ID) as MinID from #T a)T where MinID=1生成结果:
/*
ID Name Memo
----------- ---- ----
1 A A1
4 B B1(2 行受影响)
*/
--II、Name相同ID最大的记录,与min相反:
方法1:
Select * from #T a where not exists(select 1 from #T where Name=a.Name and ID>a.ID)方法2:
select a.* from #T a join (select max(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID order by ID方法3:
select * from #T a where ID=(select max(ID) from #T where Name=a.Name) order by ID方法4:
select a.* from #T a join #T b on a.Name=b.Name and a.ID<=b.ID group by a.ID,a.Name,a.Memo having count(1)=1 方法5:
select * from #T a group by ID,Name,Memo having ID=(select max(ID)from #T where Name=a.Name)方法6:
select * from #T a where (select count(1) from #T where Name=a.Name and ID>a.ID)=0方法7:
select * from #T a where ID=(select top 1 ID from #T where Name=a.name order by ID desc)方法8:
select * from #T a where ID!<all(select ID from #T where Name=a.Name)方法9(注:ID为唯一时可用):
select * from #T a where ID in(select max(ID) from #T group by Name)--SQL2005:方法10:
select ID,Name,Memo from (select *,max(ID)over(partition by Name) as MinID from #T a)T where ID=MinID方法11:
select ID,Name,Memo from (select *,row_number()over(partition by Name order by ID desc) as MinID from #T a)T where MinID=1生成结果2:
/*
ID Name Memo
----------- ---- ----
3 A A3
5 B B2(2 行受影响)
*/--2、删除重复记录有大小关系时,保留大或小其中一个记录
--> --> (Roy)生成測試數據if not object_id('Tempdb..#T') is null
drop table #T
Go
Create table #T([ID] int,[Name] nvarchar(1),[Memo] nvarchar(2))
Insert #T
select 1,N'A',N'A1' union all
select 2,N'A',N'A2' union all
select 3,N'A',N'A3' union all
select 4,N'B',N'B1' union all
select 5,N'B',N'B2'
Go--I、Name相同ID最小的记录(推荐用1,2,3),保留最小一条
方法1:
delete a from #T a where exists(select 1 from #T where Name=a.Name and ID<a.ID)方法2:
delete a from #T a left join (select min(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID where b.Id is null方法3:
delete a from #T a where ID not in (select min(ID) from #T where Name=a.Name)方法4(注:ID为唯一时可用):
delete a from #T a where ID not in(select min(ID)from #T group by Name)方法5:
delete a from #T a where (select count(1) from #T where Name=a.Name and ID<a.ID)>0方法6:
delete a from #T a where ID<>(select top 1 ID from #T where Name=a.name order by ID)方法7:
delete a from #T a where ID>any(select ID from #T where Name=a.Name)select * from #T生成结果:
/*
ID Name Memo
----------- ---- ----
1 A A1
4 B B1(2 行受影响)
*/
--II、Name相同ID保留最大的一条记录:方法1:
delete a from #T a where exists(select 1 from #T where Name=a.Name and ID>a.ID)方法2:
delete a from #T a left join (select max(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID where b.Id is null方法3:
delete a from #T a where ID not in (select max(ID) from #T where Name=a.Name)方法4(注:ID为唯一时可用):
delete a from #T a where ID not in(select max(ID)from #T group by Name)方法5:
delete a from #T a where (select count(1) from #T where Name=a.Name and ID>a.ID)>0方法6:
delete a from #T a where ID<>(select top 1 ID from #T where Name=a.name order by ID desc)方法7:
delete a from #T a where ID<any(select ID from #T where Name=a.Name)
select * from #T
/*
ID Name Memo
----------- ---- ----
3 A A3
5 B B2(2 行受影响)
*/--3、删除重复记录没有大小关系时,处理重复值
--> --> (Roy)生成測試數據
if not object_id('Tempdb..#T') is null
drop table #T
Go
Create table #T([Num] int,[Name] nvarchar(1))
Insert #T
select 1,N'A' union all
select 1,N'A' union all
select 1,N'A' union all
select 2,N'B' union all
select 2,N'B'
Go方法1:
if object_id('Tempdb..#') is not null
drop table #
Select distinct * into # from #T--排除重复记录结果集生成临时表#truncate table #T--清空表insert #T select * from # --把临时表#插入到表#T中--查看结果
select * from #T/*
Num Name
----------- ----
1 A
2 B(2 行受影响)
*/--重新执行测试数据后用方法2
方法2:alter table #T add ID int identity--新增标识列
go
delete a from #T a where exists(select 1 from #T where Num=a.Num and Name=a.Name and ID>a.ID)--只保留一条记录
go
alter table #T drop column ID--删除标识列--查看结果
select * from #T/*
Num Name
----------- ----
1 A
2 B(2 行受影响)*/--重新执行测试数据后用方法3
方法3:
declare Roy_Cursor cursor local for
select count(1)-1,Num,Name from #T group by Num,Name having count(1)>1
declare @con int,@Num int,@Name nvarchar(1)
open Roy_Cursor
fetch next from Roy_Cursor into @con,@Num,@Name
while @@Fetch_status=0
begin
set rowcount @con;
delete #T where Num=@Num and Name=@Name
set rowcount 0;
fetch next from Roy_Cursor into @con,@Num,@Name
end
close Roy_Cursor
deallocate Roy_Cursor--查看结果
select * from #T
/*
Num Name
----------- ----
1 A
2 B(2 行受影响)
*/
select
a.*
from
表 a,
(select * from 表 where group by name,sex,age having count(*)>1) b
where
a.name=b.name and a.sex=b.sex and a.age=b.age
insert into tb values('A' , 'M' , 17 )
insert into tb values('B' , 'M' , 22 )
insert into tb values('A' , 'F' , 67 )
insert into tb values('A' , 'M' , 17 )
go--三列相同
select name , sex , age from tb group by name , sex , age having count(*) > 1
/*
name sex age
---------- ---------- -----------
A M 17(所影响的行数为 1 行)
*/--name , sex 相同
select m.* from tb m where exists (select 1 from
(
select name , sex from tb group by name , sex having count(*) > 1
) n where n.name = m.name and n.sex = m.sex
)/*
name sex age
---------- ---------- -----------
A M 17
A M 17(所影响的行数为 2 行)
*/drop table tb
create table tb(name varchar(10) , sex varchar(10) , age int)
insert into tb values('A' , 'M' , 17 )
insert into tb values('B' , 'M' , 22 )
insert into tb values('A' , 'F' , 67 )
insert into tb values('A' , 'M' , 17 )
go--三列相同
select m.* from tb m where exists (select 1 from
(
select name , sex , age from tb group by name , sex , age having count(*) > 1
) n where n.name = m.name and n.sex = m.sex and n.age = m.age
)
/*
name sex age
---------- ---------- -----------
A M 17
A M 17(所影响的行数为 2 行)
*/--name , sex 相同
select m.* from tb m where exists (select 1 from
(
select name , sex from tb group by name , sex having count(*) > 1
) n where n.name = m.name and n.sex = m.sex
)/*
name sex age
---------- ---------- -----------
A M 17
A M 17(所影响的行数为 2 行)
*/drop table tb
只会写那种针对特定对象的查询
例:
select * from table where name=A and sex=M下面这句是我的想法
SELECT *
FROM table
WHERE (name = A) AND (sex = M) OR
(name = A) AND (age = 17) OR
(sex = M) AND (age = 17) OR
(name = A) AND (sex = M) AND (age = 17)
老大~~ 不行啊,报group附近有语法错误
老大~~ 报的是having附近有语法错误....我的环境是sqlserver 2000
select [name] , sex , age from tb group by [name] , sex , age having count(*) > 1
---测试数据---
if object_id('[tb]') is not null drop table [tb]
go
create table [tb]([name] varchar(1),[sex] varchar(1),[age] int)
insert [tb]
select 'A','M',17 union all
select 'B','M',22 union all
select 'A','F',67 union all
select 'A','M',17
---查询---
select * from [tb] t
where (select count(1) from tb where sex=t.sex and age=t.age)>1---结果---
name sex age
---- ---- -----------
A M 17
A M 17(所影响的行数为 2 行)
SELECT *
FROM reporter_information
ORDER BY reporter_name , reporter_provin
HAVING (COUNT(*) > 1)这么写的~~ reporter_information是我的表呵呵,我不是想把重复的去掉再显示~~ 我是想只显示出这些重复的~~ 方便我看一下再删~~5楼好像实现的是把重复的去掉的效果~~各位老大~~ 多谢
老大~~ 按您说的我写成SELECT *
FROM reporter_information t
WHERE ((SELECT COUNT(1)
FROM reporter_information
WHERE reporter_name = t.reporter_name AND
reporter_provin = t.reporter_provin) > 1)然后报列名reporter_provin无效.....帮我看看~~ 多谢~~
SELECT *
FROM reporter_information
WHERE ((SELECT COUNT(1)
FROM reporter_information t
WHERE reporter_name = t.reporter_name AND
reporter_provin = t.reporter_provin) > 1)
select
a.*
from
#T a,
(select * from #T group by [name],sex,age having count(*)>1) b
where
a.[name]=b.[name] and a.sex=b.sex and a.age=b.age 这样也可以吧...
name
,sex
,age
from
表
group by
name,sex,age
having
count(1)>=2
不行....报reporter_provin列名无效..... 但是这列名写的肯定没错的......如果我去掉AND reporter_provin = t.reporter_provin 就有显示....... 但是不是我要的效果啊....我是想只要重名的记录.....
检查一下你的reporter_information表是否有reporter_provin这个字段?
where (select count(1) from tb where sex=t.sex and age=t.age)>1
create table tb(name varchar(10) , sex varchar(10) , age int)
insert into tb values('A' , 'M' , 17 )
insert into tb values('B' , 'M' , 22 )
insert into tb values('A' , 'F' , 67 )
insert into tb values('A' , 'M' , 17 )
goselect * from tb a where exists (select 1 from (select * from tb group by name,sex,age having count(*)>1) b where b.name=a.name and b.sex=a.sex and b.age=a.age)drop table tb