不是已经给了写了一个?/*
标题:分拆列值
作者:爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开)
时间:2008-11-20
地点:广东深圳
描述有表tb, 如下:
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
欲按id,分拆value列, 分拆后结果如下:
id value
----------- --------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
*/--1. 旧的解决方法(sql server 2000)
SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b SELECT A.id, SUBSTRING(A.[values], B.id, CHARINDEX(',', A.[values] + ',', B.id) - B.id)
FROM tb A, # B
WHERE SUBSTRING(',' + A.[values], B.id, 1) = ','DROP TABLE #--2. 新的解决方法(sql server 2005)
create table tb(id int,value varchar(30))
insert into tb values(1,'aa,bb')
insert into tb values(2,'aaa,bbb,ccc')
go
SELECT A.id, B.value
FROM(
SELECT id, [value] = CONVERT(xml,'<root><v>' + REPLACE([value], ',', '</v><v>') + '</v></root>') FROM tb
)A
OUTER APPLY(
SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v)
)BDROP TABLE tb/*
id value
----------- ------------------------------
1 aa
1 bb
2 aaa
2 bbb
2 ccc(5 行受影响)
*/
标题:分拆列值
作者:爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开)
时间:2008-11-20
地点:广东深圳
描述有表tb, 如下:
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
欲按id,分拆value列, 分拆后结果如下:
id value
----------- --------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
*/--1. 旧的解决方法(sql server 2000)
SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b SELECT A.id, SUBSTRING(A.[values], B.id, CHARINDEX(',', A.[values] + ',', B.id) - B.id)
FROM tb A, # B
WHERE SUBSTRING(',' + A.[values], B.id, 1) = ','DROP TABLE #--2. 新的解决方法(sql server 2005)
create table tb(id int,value varchar(30))
insert into tb values(1,'aa,bb')
insert into tb values(2,'aaa,bbb,ccc')
go
SELECT A.id, B.value
FROM(
SELECT id, [value] = CONVERT(xml,'<root><v>' + REPLACE([value], ',', '</v><v>') + '</v></root>') FROM tb
)A
OUTER APPLY(
SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v)
)BDROP TABLE tb/*
id value
----------- ------------------------------
1 aa
1 bb
2 aaa
2 bbb
2 ccc(5 行受影响)
*/
insert into tb values(1 , 'f0826585、e05691' , 'f08954、y89302、e05691')
insert into tb values(2 , 'x96384、u58963012' , 'x96384')
insert into tb values(3 , 'u06312' , 't96582')
goSELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b select distinct n.* from (
SELECT A.id, re = SUBSTRING(A.[re], B.id, CHARINDEX('、', A.[re] + '、', B.id) - B.id)
FROM tb A, # B
WHERE SUBSTRING('、' + A.[re], B.id, 1) = '、') m , tb n where m.id = n.id and charindex(m.re , n.re1) > 0DROP TABLE #
drop table tb/*
id re re1
----------- ------------------------------ --------------------------------------------------
1 f0826585、e05691 f08954、y89302、e05691
2 x96384、u58963012 x96384(所影响的行数为 2 行)
*/
-- Author: happyflystone
-- Date:2008-12-15 16:53:26
-------------------------------------- Test Data: TA
IF OBJECT_ID('TA') IS NOT NULL
DROP TABLE TA
Go
CREATE TABLE TA(re NVARCHAR(16))
Go
INSERT INTO TA
SELECT 'f0826585、e05691' UNION ALL
SELECT 'x96384、u58963012' UNION ALL
SELECT 'u06312'
GO
-- Test Data: TB
IF OBJECT_ID('TB') IS NOT NULL
DROP TABLE TB
Go
CREATE TABLE TB(re1 NVARCHAR(20))
Go
INSERT INTO TB
SELECT 'f08954、y89302、e05691' UNION ALL
SELECT 'x96384' UNION ALL
SELECT 't96582'
GO
--Start
SELECT
*
FROM
TA d
CROSS APPLY (
SELECT re1,B.[value]
FROM(
SELECT re1,
[value] = CONVERT(xml,'<root><v>' + REPLACE(re1, '、', '</v><v>') + '</v></root>')
FROM tb
)A
OUTER APPLY(
SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v)
)B )c
where charindex('、'+c.[value]+'、','、'+d.re+'、') > 0
--Result:
/*
re re1 value
---------------- -------------------- -----------
f0826585、e05691 f08954、y89302、e05691 e05691
x96384、u58963012 x96384 x96384(2 行受影响)
*/
--End