SELECT *
FROM A FULL OUTER JOIN B
ON A.xm=B.xm
或者
SELECT *
FROM A FULL OUTER JOIN B
USING(xm)
或者
SELECT *
FROM A NATUREL FULL OUTER JOIN B
FROM A FULL OUTER JOIN B
ON A.xm=B.xm
或者
SELECT *
FROM A FULL OUTER JOIN B
USING(xm)
或者
SELECT *
FROM A NATUREL FULL OUTER JOIN B
解决方案 »
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where a.xm=b.xm
where a.xm=b.xm
select * from a
where xm in (
select xm from (
select xm from a
union all
select xm from b
) as c
having count(xm)>1
)表B:
select * from b
where xm in (
select xm from (
select xm from a
union all
select xm from b
) as chaving count(xm)>1
)
select * from a
where xm in (
select xm from (
select xm from a
union all
select xm from b
) as c
having count(xm)>1
)表B:
select * from b
where xm in (
select xm from (
select xm from a
union all
select xm from b
) as chaving count(xm)>1
)
select * from xmjlb
where (xm) in
(
select xm from xmjlb
group by xm
having count(*)>1
)
order by xm
这是在一个表中查询重复数据的代码,weixy(),你帮我研究一下怎么在一个语句用嵌套实现,我来看看临时表,只要有一个方法实现就行了。谢谢谢谢!!!
select * from a
where xm in (
select xm from (
select xm from a
union all
select xm from b
) as c
group by xm
having count(xm)>1
)表B:
select * from b
where xm in (
select xm from (
select xm from a
union all
select xm from b
) as c
group by xm
having count(xm)>1
)合在一起,要求:只能查询两表都有的字段。select * from (
select 'a' as fromtable,xm,col1,col2... from a
union all
select 'b' as fromtable,xm,col1,col2... from b
) as d
where xm in (
select xm from (
select xm from a
union all
select xm from b
) as c
group by xm
having count(xm)>1
)
成功!!!!
Yang_(扬帆破浪) 牛!!!!!!!
加五十!!!