declare @n int
set @n=11
select top 1 * from (
select a.f,b.f x from t a
left join t b on a.f=b.f-1
) a
where f>@n and x is null
order by f
set @n=11
select top 1 * from (
select a.f,b.f x from t a
left join t b on a.f=b.f-1
) a
where f>@n and x is null
order by f
where not exists (select 1 from tble where yy=a.yy+1)
create table ap(num int)insert into ap(num)
select 1 union all
select 2 union all
select 3 union all
select 4 union all
select 5 union all
select 6 union all
select 7 union all
select 9 union all
select 10 union all
select 11 union all
select 12 union all
select 13 union all
select 14 union all
select 15 union all
select 18 union all
select 19 union all
select 20 union all
select 21
-- 建函数
create function dbo.fn_maxnum
(@x int) returns int
as
begin
declare @y int;with t as
(select num,
row_number() over(order by num) 'rn'
from ap)
select top 1 @y=num
from
(select a.num
from t a
left join t b on a.rn=b.rn-1
where b.num-a.num<>1 or b.rn is null) t
where num>=@xreturn @y
end
-- 建输入表
create table #t(x int)
insert into #t(x)
select 1 union all
select 2 union all
select 3 union all
select 4 union all
select 5 union all
select 6 union all
select 7 union all
select 9 union all
select 10 union all
select 11 union all
select 12 union all
select 13 union all
select 14 union all
select 15 union all
select 18 union all
select 19 union all
select 20 union all
select 21
-- 调用函数
select x,dbo.fn_maxnum(x) 'y' from #t-- 结果
/*
x y
----------- -----------
1 7
2 7
3 7
4 7
5 7
6 7
7 7 --> 输入 1-7 都应该找到7
9 15
10 15
11 15
12 15
13 15
14 15
15 15 --> 输入9-15 都应该找到 15
18 21
19 21
20 21
21 21 --> 输入18-21 应该找到21(18 row(s) affected)
*/
CREATE TABLE tb(col1 varchar(10),col2 int)
INSERT tb SELECT 'a',2
UNION ALL SELECT 'a',3
UNION ALL SELECT 'a',6
UNION ALL SELECT 'a',7
UNION ALL SELECT 'a',8
UNION ALL SELECT 'b',1
UNION ALL SELECT 'b',5
UNION ALL SELECT 'b',6
UNION ALL SELECT 'b',7
GO--缺号分布查询
SELECT a.col1,start_col2=a.col2+1,
end_col2=(
SELECT MIN(col2) FROM tb aa
WHERE col1=a.col1 AND col2>a.col2
AND NOT EXISTS(
SELECT * FROM tb WHERE col1=aa.col1 AND col2=aa.col2-1))
-1
FROM(
SELECT col1,col2 FROM tb
UNION ALL --为每组编号补充查询起始编号是否缺号的辅助记录
SELECT DISTINCT col1,0 FROM tb
)a,(SELECT col1,col2=MAX(col2) FROM tb GROUP BY col1)b
WHERE a.col1=b.col1 AND a.col2<b.col2 --过滤掉每组数据中,编号最大的记录
AND NOT EXISTS(
SELECT * FROM tb WHERE col1=a.col1 AND col2=a.col2+1)
ORDER BY a.col1,start_col2
/*--结果
col1 start_col2 end_col2
-------------- -------------- -----------
a 1 1
a 4 5
b 2 4
--*/
--测试数据
CREATE TABLE tb(col1 varchar(10),col2 int)
INSERT tb SELECT 'a',2
UNION ALL SELECT 'a',3
UNION ALL SELECT 'a',6
UNION ALL SELECT 'a',7
UNION ALL SELECT 'a',8
UNION ALL SELECT 'b',1
UNION ALL SELECT 'b',5
UNION ALL SELECT 'b',6
UNION ALL SELECT 'b',7
GO--缺号分布查询
SELECT a.col1,start_col2=a.col2+1,
end_col2=(
SELECT MIN(col2) FROM tb aa
WHERE col1=a.col1 AND col2>a.col2
AND NOT EXISTS(
SELECT * FROM tb WHERE col1=aa.col1 AND col2=aa.col2-1))
-1
FROM(
SELECT col1,col2 FROM tb
UNION ALL --为每组编号补充查询起始编号是否缺号的辅助记录
SELECT DISTINCT col1,0 FROM tb
)a,(SELECT col1,col2=MAX(col2) FROM tb GROUP BY col1)b
WHERE a.col1=b.col1 AND a.col2<b.col2 --过滤掉每组数据中,编号最大的记录
AND NOT EXISTS(
SELECT * FROM tb WHERE col1=a.col1 AND col2=a.col2+1)
ORDER BY a.col1,start_col2
/*--结果
col1 start_col2 end_col2
-------------- -------------- -----------
a 1 1
a 4 5
b 2 4
--*/
让你望见影子<[email protected]> 9:49:01
--生成已用编号分布字符串的函数
CREATE FUNCTION f_GetStrSeries(@col1 varchar(10))
RETURNS varchar(8000)
AS
BEGIN
DECLARE @re varchar(8000),@pid int
SELECT @re='',@pid=-1
SELECT @re=CASE
WHEN col2=@pid+1 THEN @re
ELSE @re
+CASE
WHEN RIGHT(@re,CHARINDEX(',',REVERSE(@re)+',')-1)=@pid THEN ''
ELSE CAST(-@pid as varchar)
END
+','+CAST(col2 as varchar)
END,
@pid=col2
FROM tb
WHERE col1=@col1
ORDER BY col2
RETURN(STUFF(@re,1,2,'')
+CASE
WHEN RIGHT(@re,CHARINDEX(',',REVERSE(@re)+',')-1)=@pid THEN ''
ELSE CAST(-@pid as varchar)
END)
END
GO--生成缺号分布字符串的函数
CREATE FUNCTION f_GetStrNSeries(@col1 varchar(10))
RETURNS VARCHAR(8000)
AS
BEGIN
DECLARE @re varchar(8000),@pid int
SELECT @re='',@pid=0
SELECT @re=CASE
WHEN col2=@pid+1 THEN @re
ELSE @re+','+CAST(@pid+1 as varchar)
+CASE
WHEN @pid+1=col2-1 THEN ''
ELSE CAST(1-col2 as varchar)
END
END,
@pid=col2
FROM tb
WHERE col1=@col1
ORDER BY col2
RETURN(STUFF(@re,1,1,''))
END
GO--调用测试
--测试数据
CREATE TABLE tb(col1 varchar(10),col2 int)
INSERT tb SELECT 'a',2
UNION ALL SELECT 'a',3
UNION ALL SELECT 'a',5
UNION ALL SELECT 'a',8
UNION ALL SELECT 'a',9
UNION ALL SELECT 'b',1
UNION ALL SELECT 'b',5
UNION ALL SELECT 'b',6
UNION ALL SELECT 'b',7--查询
SELECT col1,
col2_Series=dbo.f_GetStrSeries(col1),
col2_Series=dbo.f_GetStrNSeries(col1)
FROM tb
GROUP BY col1
/*--结果
col1 col2_Series col2_Series
-------------- ------------------------ --------------
a 2-3,5,8-9 1,4,6-7
b 1,5-7 2-4
--*/
insert into @t(f)
select 1 union all
select 2 union all
select 3 union all
select 4 union all
select 5 union all
select 6 union all
select 7 union all
select 9 union all
select 10 union all
select 11 union all
select 12 union all
select 13 union all
select 14 union all
select 15 union all
select 18 union all
select 19 union all
select 20 union all
select 21
declare @n int
set @n=1 --7,11,18
select top 1 * from (
select a.f,b.f x from @t a
left join @t b on a.f=b.f-1
) a
where f>@n and x is null
order by f
go
--借用楼上测试数据
--测试数据
CREATE TABLE tb(col1 varchar(10),col2 int)
INSERT tb SELECT 'a',2
UNION ALL SELECT 'a',3
UNION ALL SELECT 'a',6
UNION ALL SELECT 'a',7
UNION ALL SELECT 'a',8
UNION ALL SELECT 'b',1
UNION ALL SELECT 'b',5
UNION ALL SELECT 'b',6
UNION ALL SELECT 'b',7
GO
--提供一个新思路
select
col1,ltrim(MIN(col2))+'-'+ltrim(MAX(col2)) as arr
from(
select
col1,col2,col2-ROW_NUMBER()over(partition by col1 order by col2 asc) as arr
from tb)t group by col1,arr
order by 1
/*
col1 arr
-------------------------
a 2-3
a 6-8
b 1-1
b 5-7
*/
drop table tb
--借用楼上数据
select 1 union all
select 2 union all
select 3 union all
select 4 union all
select 5 union all
select 6 union all
select 7 union all
select 9 union all
select 10 union all
select 11 union all
select 12 union all
select 13 union all
select 14 union all
select 15 union all
select 18 union all
select 19 union all
select 20 union all
select 21
),b as(
select a,a-ROW_NUMBER()over(order by a) num from a
)
select a,(select MAX(a) from b where num=b1.num) from b b1
insert into #t(x)
select 1 union all
select 2 union all
select 3 union all
select 4 union all
select 5 union all
select 6 union all
select 7 union all
select 9 union all
select 10 union all
select 11 union all
select 12 union all
select 13 union all
select 14 union all
select 15 union all
select 18 union all
select 19 union all
select 20 union all
select 21
selec t x from #t a
where not exists (select 1 from #t where x=a.x+1)答案:
7
15
21