with t1 as
(
select date, vip_no
from tablename
where product_id like '11%'
group by date, vip_no
), t2 as
(
select date, vip_no
from tablename
where product_id like '12%'
group by date, vip_no
)
select t1.date, count(1)
from t1, t2
where t1.date = t2.date
and t1.vip_no = t2.vip_no
group by t1.date;
(
select date, vip_no
from tablename
where product_id like '11%'
group by date, vip_no
), t2 as
(
select date, vip_no
from tablename
where product_id like '12%'
group by date, vip_no
)
select t1.date, count(1)
from t1, t2
where t1.date = t2.date
and t1.vip_no = t2.vip_no
group by t1.date;
-- Author :DBA_HuangZJ(發糞塗牆)
-- Date :2014-07-01 07:54:18
-- Version:
-- Microsoft SQL Server 2012 - 11.0.5058.0 (X64)
-- May 14 2014 18:34:29
-- Copyright (c) Microsoft Corporation
-- Enterprise Edition: Core-based Licensing (64-bit) on Windows NT 6.3 <X64> (Build 9600: ) (Hypervisor)
--
----------------------------------------------------------------
--> 测试数据:[huang]
if object_id('[huang]') is not null drop table [huang]
go
create table [huang]([date] int,[product_id] int,[vip_no] int)
insert [huang]
select 1,1101,135 union all
select 1,1202,135 union all
select 1,1103,136 union all
select 1,1203,136 union all
select 1,1104,137 union all
select 1,1105,137
--------------开始查询--------------------------SELECT [date],COUNT(vip_no)vip_count
FROM (
select [date],vip_no
from [huang]
WHERE [product_id] LIKE '11%'
INTERSECT
select [date],vip_no
from [huang]
WHERE [product_id] LIKE '12%' )a
GROUP BY [date]----------------结果----------------------------
/*
date vip_count
----------- -----------
1 2*/