还是有解的,只是需要做两个函数,以便实现IF OBJECT_ID('[dbo].[Dec2Bin]')IS NOT NULL
DROP FUNCTION [dbo].[Dec2Bin]
GO
CREATE FUNCTION [dbo].[Dec2Bin](@Dec INT, @StrLen INT)
RETURNS VARCHAR(31) -- INT型,4字节,正数转为二进制字符串最多31位
AS
BEGIN
DECLARE @BinStr AS VARCHAR(31) -- 二进制表示的字符串
DECLARE @Div2 AS INT -- 商
DECLARE @Mod2 AS INT -- 模/余数
IF @Dec < 0
RETURN 'NULL' -- 不支持负数的转换
SET @Div2 = @Dec / 2
SET @Mod2 = @Dec % 2
SET @BinStr = ''
WHILE @Div2 <> 0
BEGIN
SET @BinStr = CAST(@Mod2 AS CHAR(1)) + @BinStr
SET @Dec = @Dec / 2
SET @Div2 = @Dec / 2
SET @Mod2 = @Dec % 2
END;
SET @BinStr = CAST(@Mod2 AS CHAR(1)) + @BinStr -- 至此,已完成十进制到二进制的转换
IF @StrLen > LEN(@BinStr) -- 如果用户指定的长度大于实际长度,则需要左边补0
BEGIN
IF @StrLen > 31 -- 返回的长度,最长为32
SET @StrLen = 31
DECLARE @ZeroStr VARCHAR(31) -- 需要补充的"0000..."
DECLARE @OffsetLen TINYINT -- 需要补充几个"0"
SET @ZeroStr = ''
SET @OffsetLen = @StrLen - LEN(@BinStr)
WHILE @OffsetLen > 0
BEGIN
SET @ZeroStr = @ZeroStr + '0'
SET @OffsetLen = @OffsetLen - 1
END
SET @BinStr = @ZeroStr + @BinStr
END
RETURN @BinStr
END
GO
IF OBJECT_ID('[dbo].[Bin2Dec]')IS NOT NULL
DROP FUNCTION [dbo].[Bin2Dec]
GO
CREATE FUNCTION [dbo].[Bin2Dec](@BinStr VARCHAR(31))
RETURNS BIGINT
AS
BEGIN
DECLARE @LEN INT
SET @LEN=LEN(@BinStr)
DECLARE @Bit BIGINT
SET @Bit=0
SELECT @Bit=@Bit+SUBSTRING(@BinStr,number,1)*POWER(2,@LEN-number)
FROM master..spt_values
WHERE type='P'AND number>0 AND number<=@LEN
RETURN @Bit
END
GO
--有以上函数后,就可以自由取交集了
SELECT [dbo].[Dec2Bin]([dbo].[Bin2Dec]('1111110000')&[dbo].[Bin2Dec]('0011000110')&[dbo].[Bin2Dec]('1010100011'),10)
DROP FUNCTION [dbo].[Dec2Bin]
GO
CREATE FUNCTION [dbo].[Dec2Bin](@Dec INT, @StrLen INT)
RETURNS VARCHAR(31) -- INT型,4字节,正数转为二进制字符串最多31位
AS
BEGIN
DECLARE @BinStr AS VARCHAR(31) -- 二进制表示的字符串
DECLARE @Div2 AS INT -- 商
DECLARE @Mod2 AS INT -- 模/余数
IF @Dec < 0
RETURN 'NULL' -- 不支持负数的转换
SET @Div2 = @Dec / 2
SET @Mod2 = @Dec % 2
SET @BinStr = ''
WHILE @Div2 <> 0
BEGIN
SET @BinStr = CAST(@Mod2 AS CHAR(1)) + @BinStr
SET @Dec = @Dec / 2
SET @Div2 = @Dec / 2
SET @Mod2 = @Dec % 2
END;
SET @BinStr = CAST(@Mod2 AS CHAR(1)) + @BinStr -- 至此,已完成十进制到二进制的转换
IF @StrLen > LEN(@BinStr) -- 如果用户指定的长度大于实际长度,则需要左边补0
BEGIN
IF @StrLen > 31 -- 返回的长度,最长为32
SET @StrLen = 31
DECLARE @ZeroStr VARCHAR(31) -- 需要补充的"0000..."
DECLARE @OffsetLen TINYINT -- 需要补充几个"0"
SET @ZeroStr = ''
SET @OffsetLen = @StrLen - LEN(@BinStr)
WHILE @OffsetLen > 0
BEGIN
SET @ZeroStr = @ZeroStr + '0'
SET @OffsetLen = @OffsetLen - 1
END
SET @BinStr = @ZeroStr + @BinStr
END
RETURN @BinStr
END
GO
IF OBJECT_ID('[dbo].[Bin2Dec]')IS NOT NULL
DROP FUNCTION [dbo].[Bin2Dec]
GO
CREATE FUNCTION [dbo].[Bin2Dec](@BinStr VARCHAR(31))
RETURNS BIGINT
AS
BEGIN
DECLARE @LEN INT
SET @LEN=LEN(@BinStr)
DECLARE @Bit BIGINT
SET @Bit=0
SELECT @Bit=@Bit+SUBSTRING(@BinStr,number,1)*POWER(2,@LEN-number)
FROM master..spt_values
WHERE type='P'AND number>0 AND number<=@LEN
RETURN @Bit
END
GO
--有以上函数后,就可以自由取交集了
SELECT [dbo].[Dec2Bin]([dbo].[Bin2Dec]('1111110000')&[dbo].[Bin2Dec]('0011000110')&[dbo].[Bin2Dec]('1010100011'),10)
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