select a.corp_id,a.corp_name,(select sum(b.sale_money) from x_sale sale_corp=a.corp_id)as salemoney,(select sum(b.saleout_money) from x_saleout saleout_corp=a.corp_id)as saleoutmoney,这里怎么写才可以salemoney和saleoutmoney 相减 from x_kcorp a
调试欢乐多
a.corp_id,
a.corp_name,
b.salemoney,
c.saleoutmoney,
b.salemoney-c.saleoutmoney
from x_kcorp a
join (select sale_corp,sum(sale_money) as salemoney from x_sale group by sale_corp) b
on a.corp_id=b.sale_corp
join (select saleout_corp,sum(saleout_money) as saleoutmoney from x_saleout group by saleout_corp) c
on a.a.corp_id=c.saleout_corp
go--#1.直接减就可以
select
a.corp_id,
a.corp_name,
(select sum(b.sale_money) from x_sale where sale_corp=a.corp_id) as salemoney,
(select sum(b.saleout_money) from x_saleout where saleout_corp=a.corp_id) as saleoutmoney,
diff = (select sum(b.sale_money) from x_sale where sale_corp=a.corp_id) - (select sum(b.saleout_money) from x_saleout where saleout_corp=a.corp_id)
from x_kcorp a--#2.或者用子查询
select
*,
diff = salemoney - saleoutmoney
from
(
select
a.corp_id,
a.corp_name,
(select sum(b.sale_money) from x_sale where sale_corp=a.corp_id) as salemoney,
(select sum(b.saleout_money) from x_saleout where saleout_corp=a.corp_id) as saleoutmoney
from x_kcorp a
) T
gmoney=diff*100,应该如何写
a.corp_id,
a.corp_name,
b.salemoney,
c.saleoutmoney,
b.salemoney-c.saleoutmoney as diff
from x_kcorp a
join (select sale_corp,sum(sale_money) as salemoney from x_sale group by sale_corp) b
on a.corp_id=b.sale_corp
join (select saleout_corp,sum(saleout_money) as saleoutmoney from x_saleout group by saleout_corp) c
on a.a.corp_id=c.saleout_corp
where b.salemoney-c.saleoutmoney!=0
*,
diff = salemoney - saleoutmoney
from
(
select
a.corp_id,
a.corp_name,
(select sum(b.sale_money) from x_sale where sale_corp=a.corp_id) as salemoney,
(select sum(b.saleout_money) from x_saleout where saleout_corp=a.corp_id) as saleoutmoney
from x_kcorp a
) T
如何去掉realmoney为零的记录