我有一表mc
id ch
1 wwk-222
2 wwk-222
3 wwk-086
4 wwk-076
5 wwk-089
6 wwk-079CREATE procedure dwchts
@ch varchar(10)
as
begin
if len(@ch)=1
exec('select count(ch) as ts from mc where SUBSTRING(ch,7,1)='+''''+@ch+'''')
if len(@ch)=2
exec('select count(ch) as ts from mc where SUBSTRING(ch,6,2)='+''''+@ch+'''')
if len(@ch)=3
exec('select count(ch) as ts from mc where SUBSTRING(ch,5,3)='+''''+@ch+'''')
end
GO
执行存储过程是统计6条
我想得到ch完全相同的作1条,应该是5条,如何写
id ch
1 wwk-222
2 wwk-222
3 wwk-086
4 wwk-076
5 wwk-089
6 wwk-079CREATE procedure dwchts
@ch varchar(10)
as
begin
if len(@ch)=1
exec('select count(ch) as ts from mc where SUBSTRING(ch,7,1)='+''''+@ch+'''')
if len(@ch)=2
exec('select count(ch) as ts from mc where SUBSTRING(ch,6,2)='+''''+@ch+'''')
if len(@ch)=3
exec('select count(ch) as ts from mc where SUBSTRING(ch,5,3)='+''''+@ch+'''')
end
GO
执行存储过程是统计6条
我想得到ch完全相同的作1条,应该是5条,如何写
而wwk-086 和 kwk-086也成为1条
--> 测试数据:[test]
if object_id('[test]') is not null drop table [test]
create table [test]([id] int,[ch] varchar(7))
insert [test]
select 1,'wwk-222' union all
select 2,'wwk-222' union all
select 3,'wwk-086' union all
select 4,'wwk-076' union all
select 5,'wwk-089' union all
select 6,'wwk-079'select COUNT(distinct [ch]) as [ch] from test
/*
ch
------
5
*/--去掉重复使用distinct
--> 测试数据:[test]
if object_id('[test]') is not null drop table [test]
create table [test]([id] int,[ch] varchar(7))
insert [test]
select 1,'wwk-222' union all
select 2,'wwk-222' union all
select 3,'wwk-086' union all
select 4,'wwk-076' union all
select 5,'wwk-089' union all
select 6,'wwk-079'select * from test a
where a.id=(select MIN(b.id) from test b where a.ch=b.ch)
order by id
--相同的ch取最大id的时候把min改成max
/*
id ch
-------------------
1 wwk-222
3 wwk-086
4 wwk-076
5 wwk-089
6 wwk-079
*/