现有五月销售表saleinfo201205,表里有:
vipcardno(会员卡号),saleno(流水号),sstotal(销售金额),xsdate(销售时间)现在要会员单笔流水低于1000且是第一次消费的记录也就是要最小时间,单笔流水低于1000的
怎么样又能按这个vipcardno分组求小xsdate,还能按saleno分组求sstotal总额
我都快哭死了,整了好久,求高手垂怜!!!
vipcardno(会员卡号),saleno(流水号),sstotal(销售金额),xsdate(销售时间)现在要会员单笔流水低于1000且是第一次消费的记录也就是要最小时间,单笔流水低于1000的
怎么样又能按这个vipcardno分组求小xsdate,还能按saleno分组求sstotal总额
我都快哭死了,整了好久,求高手垂怜!!!
vipcardno varchar(20),saleno varchar(20),sstotal float,xsdate datetime)
insert into saleinfo201205 values('101','1',600,'2012-01-01')
insert into saleinfo201205 values( '102','1',500,'2012-01-02')
insert into saleinfo201205 values( '103','1',400,'2012-01-03')
insert into saleinfo201205 values( '101','2',600,'2012-01-02')
insert into saleinfo201205 values( '101','3',600,'2012-01-03')
insert into saleinfo201205 values( '101','4',600,'2012-01-04')
insert into saleinfo201205 values( '105','1',1200,'2012-01-01')
insert into saleinfo201205 values( '105','2',600,'2012-01-03')select * from saleinfo201205 a where exists(select 1 from (
select vipcardno,min(xsdate) as xsdate from saleinfo201205 group by vipcardno)b where a.xsdate=xsdate and a.vipcardno=vipcardno )
and sstotal<1000101 1 600 2012-01-01 00:00:00.000
102 1 500 2012-01-02 00:00:00.000
103 1 400 2012-01-03 00:00:00.000
vipcardno SaleNo xsdate sstotal
580872 2012050115126642 2012-05-01 20:44:08.000 598.00
580874 2012051915037170 2012-05-19 16:14:32.000 54.00
580876 2012052605248185 2012-05-26 11:28:45.000 0.30
580876 2012052605248185 2012-05-26 11:28:45.000 9.90
580876 2012052605248185 2012-05-26 11:28:45.000 27.20
580876 2012052605248185 2012-05-26 11:28:45.000 6.70
580876 2012052605248185 2012-05-26 11:28:45.000 9.60
580876 2012052605248185 2012-05-26 11:28:45.000 9.60
580876 2012052605248185 2012-05-26 11:28:45.000 6.04
580876 2012052605248186 2012-05-26 11:29:46.000 3.36
580876 2012052605248186 2012-05-26 11:29:46.000 18.03
580876 2012052605248186 2012-05-26 11:29:46.000 22.90
580876 2012052605248186 2012-05-26 11:29:46.000 53.90
580883 2012050311015023 2012-05-03 14:20:11.000 299.00
580883 2012050311015032 2012-05-03 14:33:55.000 150.00要的结果:
vipcardno SaleNo xsdate sstotal
580872 2012050115126642 2012-05-01 20:44:08.000 598.00
580874 2012051915037170 2012-05-19 16:14:32.000 54.00
580876 2012052605248185 2012-05-26 11:28:45.000 167.53
580883 2012050311015023 2012-05-03 14:20:11.000 299.00相同流水号SaleNo求和,同一个vipcardno,时间最小的一条记录显示
select vipcardno,saleno,sstotal,xsdate from(
select
px=ROW_NUMBER()over(partition by vipcardno,saleno order by xsdate asc),*
from tbl)t
where vipcardno in(select vipcardno from(
select vipcardno,COUNT(1) from tbl group by vipcardno having COUNT(1)=1)m)
and px=1 and sstotal<=1000
select vipcardno,min(xsdate) as xsdate from saleinfo201205 group by vipcardno)b where a.xsdate=xsdate and a.vipcardno=vipcardno )
group by vipcardno,xsdate having sum(sstotal)<1000
测试数据:
vipcardno SaleNo xsdate sstotal
580872 2012050115126642 2012-05-01 20:44:08.000 598.00
580874 2012051915037170 2012-05-19 16:14:32.000 54.00
580876 2012052605248185 2012-05-26 11:28:45.000 0.30
580876 2012052605248185 2012-05-26 11:28:45.000 9.90
580876 2012052605248185 2012-05-26 11:28:45.000 27.20
580876 2012052605248185 2012-05-26 11:28:45.000 6.70
580876 2012052605248185 2012-05-26 11:28:45.000 9.60
580876 2012052605248185 2012-05-26 11:28:45.000 9.60
580876 2012052605248185 2012-05-26 11:28:45.000 6.04
580876 2012052605248186 2012-05-26 11:29:46.000 3.36
580876 2012052605248186 2012-05-26 11:29:46.000 18.03
580876 2012052605248186 2012-05-26 11:29:46.000 22.90
580876 2012052605248186 2012-05-26 11:29:46.000 53.90
580883 2012050311015023 2012-05-03 14:20:11.000 299.00
580883 2012050311015032 2012-05-03 14:33:55.000 150.00要的结果:
vipcardno SaleNo xsdate sstotal
580872 2012050115126642 2012-05-01 20:44:08.000 598.00
580874 2012051915037170 2012-05-19 16:14:32.000 54.00
580876 2012052605248185 2012-05-26 11:28:45.000 69.34--刚刚是我写错了
580883 2012050311015023 2012-05-03 14:20:11.000 299.00相同流水号SaleNo求和,同一个vipcardno,时间最小的一条记录显示
vipcardno varchar(20),saleno varchar(20),sstotal float,xsdate datetime)
truncate table saleinfo201205
insert into saleinfo201205 values('580872', '2012050115126642',598.00, '2012-05-01 20:44:08.000')
insert into saleinfo201205 values('580874' ,'2012051915037170',54.00 ,'2012-05-19 16:14:32.000 ')
insert into saleinfo201205 values('580876' ,'2012052605248185',0.30 ,'2012-05-26 11:28:45.000 ')
insert into saleinfo201205 values('580876' ,'2012052605248185',9.90 ,'2012-05-26 11:28:45.000 ')
insert into saleinfo201205 values('580876' ,'2012052605248185',27.20 ,'2012-05-26 11:28:45.000 ')
insert into saleinfo201205 values('580876' ,'2012052605248185',6.70 ,'2012-05-26 11:28:45.000 ')
insert into saleinfo201205 values('580876' ,'2012052605248185',9.60 ,'2012-05-26 11:28:45.000 ')
insert into saleinfo201205 values('580876' ,'2012052605248185',9.60 ,'2012-05-26 11:28:45.000 ')
insert into saleinfo201205 values('580876' ,'2012052605248185',6.04 ,'2012-05-26 11:28:45.000 ')
insert into saleinfo201205 values('580876' ,'2012052605248186',3.36 ,'2012-05-26 11:29:46.000 ')
insert into saleinfo201205 values('580876' ,'2012052605248186',18.03 ,'2012-05-26 11:29:46.000 ')
insert into saleinfo201205 values('580876' ,'2012052605248186',22.90 ,'2012-05-26 11:29:46.000 ')
insert into saleinfo201205 values('580876' ,'2012052605248186',53.90 ,'2012-05-26 11:29:46.000 ')
insert into saleinfo201205 values('580883', '2012050311015023',299.00 ,'2012-05-03 14:20:11.000 ')
insert into saleinfo201205 values('580883', '2012050311015032',150.00 ,'2012-05-03 14:33:55.000 ') select vipcardno,min(saleno) as saleno,sum(sstotal) as sstotal,xsdate from saleinfo201205 a where exists(select 1 from (
select vipcardno,min(saleno) as saleno,sum(sstotal) as sstotal,min(xsdate) as xsdate from saleinfo201205 group by vipcardno)b where a.xsdate=xsdate and a.vipcardno=vipcardno )
group by vipcardno,xsdate having sum(sstotal)<1000
--> 测试数据:[test]
if object_id('[test]') is not null drop table [test]
create table [test](
[vipcardno] int,
[SaleNo] bigint,
[xsdate] datetime,
[sstotal] numeric(8,2)
)
insert [test]
select 580872,2012050115126642,'2012-05-01 20:44:08.000',598.00 union all
select 580874,2012051915037170,'2012-05-19 16:14:32.000',54.00 union all
select 580876,2012052605248185,'2012-05-26 11:28:45.000',0.30 union all
select 580876,2012052605248185,'2012-05-26 11:28:45.000',9.90 union all
select 580876,2012052605248185,'2012-05-26 11:28:45.000',27.20 union all
select 580876,2012052605248185,'2012-05-26 11:28:45.000',6.70 union all
select 580876,2012052605248185,'2012-05-26 11:28:45.000',9.60 union all
select 580876,2012052605248185,'2012-05-26 11:28:45.000',9.60 union all
select 580876,2012052605248185,'2012-05-26 11:28:45.000',6.04 union all
select 580876,2012052605248186,'2012-05-26 11:29:46.000',3.36 union all
select 580876,2012052605248186,'2012-05-26 11:29:46.000',18.03 union all
select 580876,2012052605248186,'2012-05-26 11:29:46.000',22.90 union all
select 580876,2012052605248186,'2012-05-26 11:29:46.000',53.90 union all
select 580883,2012050311015023,'2012-05-03 14:20:11.000',299.00 union all
select 580883,2012050311015032,'2012-05-03 14:33:55.000',150.00
select distinct [vipcardno],[SaleNo],[xsdate],
SUM([sstotal])over( partition by [SaleNo]) as [sstotal]
from test a
where [xsdate]=(select MIN([xsdate]) from test b
where a.vipcardno=b.vipcardno)/*
vipcardno SaleNo xsdate sstotal
580872 2012050115126642 2012-05-01 20:44:08.000 598.00
580874 2012051915037170 2012-05-19 16:14:32.000 54.00
580876 2012052605248185 2012-05-26 11:28:45.000 69.34
580883 2012050311015023 2012-05-03 14:20:11.000 299.00
*/
--哎,给的测试数据时间都是一样的
with cte as
(
select '580872' as vipcardno,'2012050115126642' as SaleNo,'2012-05-01 20:44:08.000' as xsdate,598.00 as sstotal union all
select '580874','2012051915037170','2012-05-19 16:14:32.000',54.00 union all
select '580876','2012052605248185','2012-05-26 11:28:45.000',0.30 union all
select '580876','2012052605248185','2012-05-26 11:28:45.000',9.90 union all
select '580876','2012052605248185','2012-05-26 11:28:45.000',27.20 union all
select '580876','2012052605248185','2012-05-26 11:28:45.000',6.70 union all
select '580876','2012052605248185','2012-05-26 11:28:45.000',9.60 union all
select '580876','2012052605248185','2012-05-26 11:28:45.000',9.60 union all
select '580876','2012052605248185','2012-05-26 11:28:45.000',6.04 union all
select '580876','2012052605248186','2012-05-26 11:29:46.000',3.36 union all
select '580876','2012052605248186','2012-05-26 11:29:46.000',18.03 union all
select '580876','2012052605248186','2012-05-26 11:29:46.000',22.90 union all
select '580876','2012052605248186','2012-05-26 11:29:46.000',53.90 union all
select '580883','2012050311015023','2012-05-03 14:20:11.000',299.00 union all
select '580883','2012050311015032','2012-05-03 14:33:55.000',150.00
)
select
distinct
vipcardno
,min(SaleNo) over(partition by vipcardno) as min_saleNo
,min(xsdate) over(partition by vipcardno) as min_xsdate
,sum(sstotal) over(partition by xsdate) as sum_sstotal
from cte
where sstotal <1000--vipcardno min_saleNo min_xsdate sum_sstotal
----------- ---------------- ----------------------- ---------------------------------------
--580872 2012050115126642 2012-05-01 20:44:08.000 598.00
--580874 2012051915037170 2012-05-19 16:14:32.000 54.00
--580876 2012052605248185 2012-05-26 11:28:45.000 69.34
--580876 2012052605248185 2012-05-26 11:28:45.000 98.19
--580883 2012050311015023 2012-05-03 14:20:11.000 150.00
--580883 2012050311015023 2012-05-03 14:20:11.000 299.00--(6 row(s) affected)
楼主给的测试结果是不是有问题?
你的结果里 167.53和299.00 一个是汇总一个时根据时间取值
with cte as
(
select '580872' as vipcardno,'2012050115126642' as SaleNo,'2012-05-01 20:44:08.000' as xsdate,598.00 as sstotal union all
select '580874','2012051915037170','2012-05-19 16:14:32.000',54.00 union all
select '580876','2012052605248185','2012-05-26 11:28:45.000',0.30 union all
select '580876','2012052605248185','2012-05-26 11:28:45.000',9.90 union all
select '580876','2012052605248185','2012-05-26 11:28:45.000',27.20 union all
select '580876','2012052605248185','2012-05-26 11:28:45.000',6.70 union all
select '580876','2012052605248185','2012-05-26 11:28:45.000',9.60 union all
select '580876','2012052605248185','2012-05-26 11:28:45.000',9.60 union all
select '580876','2012052605248185','2012-05-26 11:28:45.000',6.04 union all
select '580876','2012052605248186','2012-05-26 11:29:46.000',3.36 union all
select '580876','2012052605248186','2012-05-26 11:29:46.000',18.03 union all
select '580876','2012052605248186','2012-05-26 11:29:46.000',22.90 union all
select '580876','2012052605248186','2012-05-26 11:29:46.000',53.90 union all
select '580883','2012050311015023','2012-05-03 14:20:11.000',299.00 union all
select '580883','2012050311015032','2012-05-03 14:33:55.000',150.00
),
cte2 as
(
select
distinct
a.vipcardno
,min(a.SaleNo) over(partition by vipcardno) as min_saleNo
,min(a.xsdate) over(partition by vipcardno) as min_xsdate
,sum(a.sstotal)over(partition by vipcardno) as sum_sstotal
from cte a
where a.xsdate in
(
--同一条记录,显示时间最小的...
select MIN (xsdate) from cte b where b.vipcardno=a.vipcardno
)
)
--过滤汇总后结果<1000
select * from cte2 where sum_sstotal<1000--vipcardno min_saleNo min_xsdate sum_sstotal
----------- ---------------- ----------------------- ---------------------------------------
--580872 2012050115126642 2012-05-01 20:44:08.000 598.00
--580874 2012051915037170 2012-05-19 16:14:32.000 54.00
--580876 2012052605248185 2012-05-26 11:28:45.000 69.34
--580883 2012050311015023 2012-05-03 14:20:11.000 299.00--(4 row(s) affected)
参考TravyLee 的
加上个过滤条件
先膜拜三下