/*
任意给定两个时间点start_time,end_time(两个时间点可能同一天,也可能不同),另外给定一个时间区段[ss,ee],其中时间区段[ss,ee]只有小时和分钟(无日期)。
要求:找出从start_time开始到end_time结束这段时间内,有多长时间是在[ss,ee]里面的?(最终时长以分钟计算)
跨天的有点麻烦。。
*/ --建表
--对于ss和ee列,数字0表示时间00:00,数字1000表示10:00,数字400表示04:00,数字2400表示时间24:00(次日的00:00),
--其他类似create table temp(start_time datetime,end_time datetime,ss int,ee int)
go
insert into temp values('2011-12-20 22:10:00','2011-12-20 23:15:00',1000,2400);
insert into temp values('2011-11-01 00:15:00','2011-11-01 05:13:00',0,200);
insert into temp values('2011-11-01 05:15:00','2011-11-01 06:13:00',400,600);
insert into temp values('2011-10-20 23:45:00','2011-10-21 05:20:00',2200,2400);
insert into temp values('2011-10-20 23:45:00','2011-10-21 08:20:00',0,200);
insert into temp values('2011-10-20 23:45:00','2011-10-23 08:20:00',2200,2400);
go/*
结果应该是:(period单位:分钟)
period
65
45
58
15
120
150
*/
之前数据看歪了,正确结果为:
period
65
105
45
15
120
150
create table temp(start_time datetime,end_time datetime,ss int,ee int)
go
insert into temp values('2011-12-20 22:10:00','2011-12-20 23:15:00',1000,2400);
insert into temp values('2011-11-01 00:15:00','2011-11-01 05:13:00',0,200);
insert into temp values('2011-11-01 05:15:00','2011-11-01 06:13:00',400,600);
insert into temp values('2011-10-20 23:45:00','2011-10-21 05:20:00',2200,2400);
insert into temp values('2011-10-20 23:45:00','2011-10-21 08:20:00',0,200);
insert into temp values('2011-10-20 23:45:00','2011-10-23 08:20:00',2200,2400);
go;with ach as
(
select a.start_time,a.end_time,ss,ee,
dateadd(dd,b.number,
(case when b.number <> 0 then convert(datetime,convert(varchar(8),a.start_time,112))
else a.start_time end)) fact_start
from temp a,master..spt_values b
where b.[type] = 'p' and b.number between 0 and datediff(dd,a.start_time,a.end_time)
),art as
(
select start_time,end_time,ss,ee,
convert(datetime,convert(varchar(11),fact_start,120)+
(case when ss/100 in (24,0) then '00' else right(100+ss/100,2) end)+':'
+right(100+ss%100,2)) new_start,
dateadd(dd,(case when ee/100=24 then 1 else 0 end),
convert(datetime,convert(varchar(11),fact_start,120)+
(case when ee/100 in (24,0) then '00' else right(100+ee/100,2) end)+':'
+right(100+ee%100,2))) new_end
from ach
)select start_time,end_time,ss,ee,
sum(case when new_start between start_time and end_time
or start_time between new_start and new_end
then
(datediff(mi,(case when start_time >= new_start then start_time else new_start end),
(case when end_time <= new_end then end_time else new_end end)))
else 0 end) miu
from art
group by start_time,end_time,ss,eedrop table temp/********************************start_time end_time ss ee miu
----------------------- ----------------------- ----------- ----------- -----------
2011-10-20 23:45:00.000 2011-10-21 05:20:00.000 2200 2400 15
2011-10-20 23:45:00.000 2011-10-21 08:20:00.000 0 200 120
2011-10-20 23:45:00.000 2011-10-23 08:20:00.000 2200 2400 255
2011-11-01 00:15:00.000 2011-11-01 05:13:00.000 0 200 105
2011-11-01 05:15:00.000 2011-11-01 06:13:00.000 400 600 45
2011-12-20 22:10:00.000 2011-12-20 23:15:00.000 1000 2400 65(6 行受影响)