create table t (numbers varchar(10),date datetime)
insert t select '1000 ', '2011-10-01 07:16:00.000 '
union all select '1000 ', '2011-10-01 12:00:00.000 '
union all select '1000 ', '2011-10-03 12:00:00.000 '
union all select '1001 ', '2011-10-03 13:14:00.000 '
union all select '1001 ', '2011-10-03 08:00:00.000 '
/*
结果想要成
Numbers 日期 时间
1000 2011-10-01 07:16:00.000,12:00:00.000
1000 2011-10-03 12:00:00.000
1001 2011-10-03 13:14:00.000,08:00:00.000
*/
insert t select '1000 ', '2011-10-01 07:16:00.000 '
union all select '1000 ', '2011-10-01 12:00:00.000 '
union all select '1000 ', '2011-10-03 12:00:00.000 '
union all select '1001 ', '2011-10-03 13:14:00.000 '
union all select '1001 ', '2011-10-03 08:00:00.000 ' select numbers , date ,
case when min_time <> max_time then convert(varchar(8),min_time,108) + '.000,' +
convert(varchar(8),max_time,108) + '.000'
else convert(varchar(8),min_time,108) + '.000'
end 时间
from
(
select numbers , convert(varchar(10),date,120) date ,
min(date) min_time,
max(date) max_time
from t
group by numbers , convert(varchar(10),date,120)
) mdrop table t/*
numbers date 时间
---------- ---------- -------------------------
1000 2011-10-01 07:16:00.000,12:00:00.000
1000 2011-10-03 12:00:00.000
1001 2011-10-03 08:00:00.000,13:14:00.000（所影响的行数为 3 行）
*/
sql 2000得用函数.
那就如下的操作了.
/*
标题：按某字段合并字符串之一(简单合并)
作者：爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开)
时间：2008-11-06
地点：广东深圳描述：将如下形式的数据按id字段合并value字段。
id value
----- ------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
需要得到结果：
id value
------ -----------
1 aa,bb
2 aaa,bbb,ccc
即：group by id, 求 value 的和（字符串相加）
*/
--1、sql2000中只能用自定义的函数解决
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
gocreate function dbo.f_str(@id varchar(10)) returns varchar(1000)
as
begin
declare @str varchar(1000)
select @str = isnull(@str + ',' , '') + cast(value as varchar) from tb where id = @id
return @str
end
go--调用函数
select id , value = dbo.f_str(id) from tb group by iddrop function dbo.f_str
drop table tb
--2、sql2005中的方法
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
goselect id, [value] = stuff((select ',' + [value] from tb t where id = tb.id for xml path('')) , 1 , 1 , '')
from tb
group by iddrop table tb
--3、使用游标合并数据
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
declare @t table(id int,value varchar(100))--定义结果集表变量
--定义游标并进行合并处理
declare my_cursor cursor local for
select id , value from tb
declare @id_old int , @id int , @value varchar(10) , @s varchar(100)
open my_cursor
fetch my_cursor into @id , @value
select @id_old = @id , @s=''
while @@FETCH_STATUS = 0
begin
if @id = @id_old
select @s = @s + ',' + cast(@value as varchar)
else
begin
insert @t values(@id_old , stuff(@s,1,1,''))
select @s = ',' + cast(@value as varchar) , @id_old = @id
end
fetch my_cursor into @id , @value
END
insert @t values(@id_old , stuff(@s,1,1,''))
close my_cursor
deallocate my_cursorselect * from @t
drop table tb
SELECT t1.numbers ,
CONVERT(VARCHAR(10), date, 120) AS date ,
time = STUFF(( SELECT ',' + RIGHT(date, 12)
FROM t
WHERE numbers = t1.numbers
AND CONVERT(VARCHAR(10), t1.date, 120) = CONVERT(VARCHAR(10), date, 120)
FOR
XML PATH('')
), 1, 1, '')
FROM t t1
GROUP BY t1.numbers ,
CONVERT(VARCHAR(10), date, 120)/*
numbers date 时间
---------- ---------- -------------------------
1000 2011-10-01 07:16:00.000,12:00:00.000
1000 2011-10-03 12:00:00.000
1001 2011-10-03 08:00:00.000,13:14:00.000
*/