-- 既然不知道表的字段,那么第20条到第30条按什么排序得来的? select top(30) * from tab except select top(20) * from tab
取n到m行1. select top m * from tablename where id not in (select top n id from tablename order by id asc/*|desc*/) 2. select top m * into 临时表(或表变量) from tablename order by columnname -- 将top m笔插入到临时表 set rowcount n --只取n条结果 select * from 表变量 order by columnname desc 3. select top n * from (select top m * from tablename order by columnname) a order by columnname desc 4.如果tablename里没有其他identity列,那么: 先生成一个序列,存储在一临时表中. select identity(int) id0,* into #temp from tablename 取n到m条的语句为: select * from #temp where id0 > =n and id0 <= m 如果你在执行select identity(int) id0,* into #temp from tablename这条语句的时候报错,那是因为你的DB中间的select into/bulkcopy属性没有打开要先执行: exec sp_dboption 你的DB名字,'select into/bulkcopy',true 5.如果表里有identity属性,那么简单: select * from tablename where identity_col between n and m 6.SQL2005开始.可以使用row_number() over()生成行号 ;with cte as ( select id0=row_number() over(order by id),* from tablename ) select * from cte where id0 between n to m
select *,id=identity(int,1,1) into #t from tbselect * from tb where id between 20 and 30
----sinpoal --既然不知道。如果不排序,加入ID= identity(INT,1,1),再取id为20——30在数据 select *,ID=identity(INT,1,1) into #t from TAselect * from TA where id between 20 and 30
-- 既然不知道表的字段,那么第20条到第30条按什么排序得来的?
select top(30) * from tab
except
select top(20) * from tab
select top m * from tablename where id not in (select top n id from tablename order by id asc/*|desc*/) 2.
select top m * into 临时表(或表变量) from tablename order by columnname -- 将top m笔插入到临时表
set rowcount n --只取n条结果
select * from 表变量 order by columnname desc 3.
select top n * from
(select top m * from tablename order by columnname) a
order by columnname desc
4.如果tablename里没有其他identity列,那么:
先生成一个序列,存储在一临时表中.
select identity(int) id0,* into #temp from tablename 取n到m条的语句为:
select * from #temp where id0 > =n and id0 <= m 如果你在执行select identity(int) id0,* into #temp from tablename这条语句的时候报错,那是因为你的DB中间的select into/bulkcopy属性没有打开要先执行:
exec sp_dboption 你的DB名字,'select into/bulkcopy',true
5.如果表里有identity属性,那么简单:
select * from tablename where identity_col between n and m 6.SQL2005开始.可以使用row_number() over()生成行号
;with cte as
(
select id0=row_number() over(order by id),* from tablename
)
select * from cte where id0 between n to m
----sinpoal
--既然不知道。如果不排序,加入ID= identity(INT,1,1),再取id为20——30在数据
select *,ID=identity(INT,1,1) into #t from TAselect * from TA where id between 20 and 30