表里数据
id type price
1 A 20
2 A 20
3 A 30
4 B 10
5 B 12
6 C 30
7 C 30求一个SQL语句,取某类的price最高的一行记录
注意,如果某类的最高price有两条或者更多的话,也只取其中的某一条。id不会重复
最后结果为id type price
3 A 30
5 B 12
6 C 30 (这条取6或者7都可)
id type price
1 A 20
2 A 20
3 A 30
4 B 10
5 B 12
6 C 30
7 C 30求一个SQL语句,取某类的price最高的一行记录
注意,如果某类的最高price有两条或者更多的话,也只取其中的某一条。id不会重复
最后结果为id type price
3 A 30
5 B 12
6 C 30 (这条取6或者7都可)
/******************************************************************************************************************************************************
1、Num、Name相同的重复值记录,没有大小关系只保留一条
2、Name相同,ID有大小关系时,保留大或小其中一个记录
整理人:中国风(Roy)日期:2008.06.06
******************************************************************************************************************************************************/--1、用于查询重复处理记录(如果列没有大小关系时2000用生成自增列和临时表处理,SQL2005用row_number函数处理)--> --> (Roy)生成測試數據
if not object_id('Tempdb..#T') is null
drop table #T
Go
Create table #T([ID] int,[Name] nvarchar(1),[Memo] nvarchar(2))
Insert #T
select 1,N'A',N'A1' union all
select 2,N'A',N'A2' union all
select 3,N'A',N'A3' union all
select 4,N'B',N'B1' union all
select 5,N'B',N'B2'
Go
--I、Name相同ID最小的记录(推荐用1,2,3),方法3在SQl05时,效率高于1、2
方法1:
Select * from #T a where not exists(select 1 from #T where Name=a.Name and ID<a.ID)方法2:
select a.* from #T a join (select min(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID方法3:
select * from #T a where ID=(select min(ID) from #T where Name=a.Name)方法4:
select a.* from #T a join #T b on a.Name=b.Name and a.ID>=b.ID group by a.ID,a.Name,a.Memo having count(1)=1 方法5:
select * from #T a group by ID,Name,Memo having ID=(select min(ID)from #T where Name=a.Name)方法6:
select * from #T a where (select count(1) from #T where Name=a.Name and ID<a.ID)=0方法7:
select * from #T a where ID=(select top 1 ID from #T where Name=a.name order by ID)方法8:
select * from #T a where ID!>all(select ID from #T where Name=a.Name)方法9(注:ID为唯一时可用):
select * from #T a where ID in(select min(ID) from #T group by Name)--SQL2005:方法10:
select ID,Name,Memo from (select *,min(ID)over(partition by Name) as MinID from #T a)T where ID=MinID方法11:select ID,Name,Memo from (select *,row_number()over(partition by Name order by ID) as MinID from #T a)T where MinID=1生成结果:
/*
ID Name Memo
----------- ---- ----
1 A A1
4 B B1(2 行受影响)
*/
--II、Name相同ID最大的记录,与min相反:
方法1:
Select * from #T a where not exists(select 1 from #T where Name=a.Name and ID>a.ID)方法2:
select a.* from #T a join (select max(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID order by ID方法3:
select * from #T a where ID=(select max(ID) from #T where Name=a.Name) order by ID方法4:
select a.* from #T a join #T b on a.Name=b.Name and a.ID<=b.ID group by a.ID,a.Name,a.Memo having count(1)=1 方法5:
select * from #T a group by ID,Name,Memo having ID=(select max(ID)from #T where Name=a.Name)方法6:
select * from #T a where (select count(1) from #T where Name=a.Name and ID>a.ID)=0方法7:
select * from #T a where ID=(select top 1 ID from #T where Name=a.name order by ID desc)方法8:
select * from #T a where ID!<all(select ID from #T where Name=a.Name)方法9(注:ID为唯一时可用):
select * from #T a where ID in(select max(ID) from #T group by Name)--SQL2005:方法10:
select ID,Name,Memo from (select *,max(ID)over(partition by Name) as MinID from #T a)T where ID=MinID方法11:
select ID,Name,Memo from (select *,row_number()over(partition by Name order by ID desc) as MinID from #T a)T where MinID=1生成结果2:
/*
ID Name Memo
----------- ---- ----
3 A A3
5 B B2(2 行受影响)
*/
(select 1 from 表 where type=a.type and price>a.price)
from 表 a
where not exists (select 1 from 表 where type=a.type and (
price>a.price or price=a.price and id >a.id ))
-- Author :fredrickhu(小F 向高手学习)
-- Date :2009-08-25 16:39:08
----------------------------------------------------------------
--> 测试数据:[tb]
if object_id('[tb]') is not null drop table [tb]
go
create table [tb]([id] int,[type] varchar(1),[price] int)
insert [tb]
select 1,'A',20 union all
select 2,'A',20 union all
select 3,'A',30 union all
select 4,'B',10 union all
select 5,'B',12 union all
select 6,'C',30 union all
select 7,'C',30
--------------开始查询--------------------------
select
*
from
tb t
where
not exists(select 1 from tb where type=t.type and (price>t.price or price=t.price and id <t.id ))
----------------结果----------------------------
/*id type price
----------- ---- -----------
3 A 30
5 B 12
6 C 30(3 行受影响)
*/
insert into @tablea
select 1,'A',20 union all
select 2,'A',20 union all
select 3,'A',30 union all
select 4,'B',10 union all
select 5,'B',12 union all
select 6,'C',30 union all
select 7,'C',30select MIN(id) as id, type, MAX(price)as price from @tablea group by type
----------------------------------------------------------------
-- Author :fredrickhu(小F 向高手学习)
-- Date :2009-08-25 16:39:08
----------------------------------------------------------------
--> 测试数据:[tb]
if object_id('[tb]') is not null drop table [tb]
go
create table [tb]([id] int,[type] varchar(1),[price] int)
insert [tb]
select 1,'A',20 union all
select 2,'A',20 union all
select 3,'A',30 union all
select 4,'B',10 union all
select 5,'B',12 union all
select 6,'C',30 union all
select 7,'C',30
--------------开始查询--------------------------
select
*
from
tb a
where
price=(select max(price) from tb where [type]=a.type)
and
id= (select max(id) from tb where [type]=a.type)
order by
price----------------结果----------------------------
/*id type price
----------- ---- -----------
3 A 30
5 B 12
6 C 30(3 行受影响)
*/
select type,max(price) 'price' from table1
group by type ) ts join table1 a on ts.type=a.type and ts.price=a.price
group by a.type
WHERE
NOT EXISTS(SELECT 1 FROM TB WHERE TYPE=T.TYPE AND PRICE>T.PRICE)
OR
NOT EXISTS(SELECT 1 FROM TB WHERE TYPE=T.TYPE AND PRICE=T.PRICE AND ID>T.ID)
if object_id('[tb]') is not null drop table [tb]
go
create table [tb]([id] int,[type] varchar(1),[price] int)
insert [tb]
select 1,'A',20 union all
select 2,'A',20 union all
select 3,'A',30 union all
select 4,'B',10 union all
select 5,'B',12 union all
select 6,'C',30 union all
select 7,'C',30SELECT * FROM TB T
WHERE
NOT EXISTS(SELECT 1 FROM TB WHERE TYPE=T.TYPE AND PRICE>T.PRICE)
AND
NOT EXISTS(SELECT 1 FROM TB WHERE TYPE=T.TYPE AND PRICE=T.PRICE AND ID>T.ID)(所影响的行数为 7 行)id type price
----------- ---- -----------
3 A 30
5 B 12
7 C 30(所影响的行数为 3 行)OR-->AND
from
(select type,max(price) price from #01 group by type) a
left join #01 on a.price=#01.price and a.type=#01.type group by a.type,a.price
insert into #01
select '1','A','20' union all
select '2','A','20' union all
select '3','A','30' union all
select '4','B','10' union all
select '5','B','12' union all
select '6','C','30' union all
select '7','C','30'select min(id) id,a.type,a.price
from
(select type,max(price) price from #01 group by type) a
left join #01 on a.price=#01.price and a.type=#01.type group by a.type,a.price 完整数据!
借下小F的数据建库~~
if object_id('[tb]') is not null drop table [tb]
go
create table [tb]([id] int,[type] varchar(1),[price] int)
insert [tb]
select 1,'A',20 union all
select 2,'A',20 union all
select 3,'A',30 union all
select 4,'B',10 union all
select 5,'B',12 union all
select 6,'C',30 union all
select 7,'C',30
create table #
([type] varchar(1),[price] int)
insert into #
select type,max(price) from tb group by type
select * from tb where exists(select * from # where tb.type=type and tb.price=price)
go
create table [tb]([id] int,[type] varchar(1),[price] int)
insert [tb]
select 1,'A',20 union all
select 2,'A',20 union all
select 3,'A',30 union all
select 4,'B',10 union all
select 5,'B',12 union all
select 6,'C',30 union all
select 7,'C',30
select * from tb a where not exists(select 1 from tb where type=a.type and price>a.price)
select min(id) from tb b,
(select type,max(price) as price from tb c group by type) t
where b.type=t.type and b.price=t.price group by b.type
)
drop table [tb]
go
create table [tb]([id] int,[type] varchar(1),[price] int)
insert [tb]
select 1,'A',20 union all
select 2,'A',20 union all
select 3,'A',30 union all
select 4,'B',10 union all
select 5,'B',12 union all
select 6,'C',30 union all
select 7,'C',30
select *
from tb a
where not exists (select 1 from tb where type=a.type and (
price>a.price or price=a.price and id >a.id ))/*
id type price
----------- ---- -----------
3 A 30
5 B 12
7 C 30*/
insert into tb(id,type,price)
select 1 , 'A' , 20 union allselect 2 , 'A' , 20 union all
select 3 , 'A' , 30 union all
select 4 , 'B' , 10 union all
select 5 , 'B' , 12 union all
select 6 , 'C' , 30 union all
select 7 , 'C' , 30
select * from tb t where not exists(select 1 from tb where type=t.type
and price>t.price)
-- 建立临时表
CREATE TABLE test
(
id int IDENTITY(1,1) NOT NULL
,type varchar(1) NOT NULL
,price int NOT NULL
)ON [PRIMARY]
GO-- 插入测试数据
INSERT INTO test VALUES
('A', 20)
,('A', 20)
,('A', 30)
,('B', 10)
,('B', 12)
,('C', 30)
,('C', 30);-- 查询结果
SELECT MAX(id) AS id, type, MAX(price) AS price FROM test GROUP BY type;/*
id type price
3 A 30
5 B 12
7 C 30
*/
select * from t_table where price in(select max(price) from t_table group by type )