有一张表,有一个uniqueid字段 唯一, 有一个字段 last_replytime,我想取得按last_replytime降序排列后,第5到10条记录,我是这样写的select top 10 * from mytable where uniqueid not in(select top 4 uniqueid from mytable order by last_replytime desc) order by last_replytime desc大这看这样写对吗?有什么更简洁更高效 的写法没
select top m * from tablename where id not in (select top n id from tablename order by id asc/*|desc*/) 2.
select top m * into 临时表(或表变量) from tablename order by columnname -- 将top m笔插入到临时表
set rowcount n --只取n条结果
select * from 表变量 order by columnname desc 3.
select top n * from
(select top m * from tablename order by columnname) a
order by columnname desc
4.如果tablename里没有其他identity列,那么:
先生成一个序列,存储在一临时表中.
select identity(int) id0,* into #temp from tablename 取n到m条的语句为:
select * from #temp where id0 > =n and id0 <= m 如果你在执行select identity(int) id0,* into #temp from tablename这条语句的时候报错,那是因为你的DB中间的select into/bulkcopy属性没有打开要先执行:
exec sp_dboption 你的DB名字,'select into/bulkcopy',true
5.如果表里有identity属性,那么简单:
select * from tablename where identity_col between n and m 6.SQL2005开始.可以使用row_number() over()生成行号
;with cte as
(
select id0=row_number() over(order by id),* from tablename
)
select * from cte where id0 between n to m
from (
select uniqueid,id=row_number() over (order by last_replytime desc) from mytable
) t
where 5<=id and id<=10
select top 5 * from
(select top 10 * from 表 order by uniqueid desc) 表
;with cte as
(
select id0=row_number() over(order by id),* from tablename
)
select * from cte where id0 between n to m