一列的时间怎么统计 本帖最后由 chirea 于 2011-06-30 22:27:35 编辑 解决方案 » 免费领取超大流量手机卡,每月29元包185G流量+100分钟通话, 中国电信官方发货 SELECT numbers, DATEADD(second,SUM(DATEDIFF(second,0,datetimes)),0)FROM tbGROUP BY numbers select numbers,sum(datediff(mi,'1900-01-01',datetimes)) as 分钟from tbgroup by nunbers number -------------------------------------------------- -----------------------001 1900-01-02 23:29:00.000002 1900-01-02 07:00:10.000003 1900-01-02 07:00:28.000(3 row(s) affected)number datetimes-------------------------------------------------- -----------------------001 1900-01-01 00:30:00.000001 1900-01-01 15:29:00.000001 1900-01-01 16:00:00.000001 1900-01-01 15:30:00.000002 1900-01-01 15:30:00.000002 1900-01-01 15:30:10.000003 1900-01-01 15:30:11.000003 1900-01-01 15:30:17.000(8 row(s) affected)搞定了.谢谢各位的热心 求一分组统计SQL 数据库模糊查询 关于自动增长的问题 存储过程问题,请大家来指正,高手必进~~~ 我的代码错吗? 怎样把表中的描述一起导出来? 寻找事业单位工资管理系统 zjcxc(邹建)大虾进来,有关触发器的几个很小的问题 sql server2000数据库自动备份加自动压缩,求大家帮帮我,先谢谢了 !!![Microsoft][ODBC SQL Server Driver][SQL Server]Invalid column name 'CF' sql broker 为什么自动关闭 咨询一个常见sql写法
DATEADD(second,SUM(DATEDIFF(second,0,datetimes)),0)
FROM tb
GROUP BY numbers
from tb
group by nunbers
number
-------------------------------------------------- -----------------------
001 1900-01-02 23:29:00.000
002 1900-01-02 07:00:10.000
003 1900-01-02 07:00:28.000(3 row(s) affected)number datetimes
-------------------------------------------------- -----------------------
001 1900-01-01 00:30:00.000
001 1900-01-01 15:29:00.000
001 1900-01-01 16:00:00.000
001 1900-01-01 15:30:00.000
002 1900-01-01 15:30:00.000
002 1900-01-01 15:30:10.000
003 1900-01-01 15:30:11.000
003 1900-01-01 15:30:17.000(8 row(s) affected)搞定了.谢谢各位的热心