要是有部分重合呢?结果也是单纯的加在一起吗? /* 标题:简单数据拆分(version 2.0) 作者:爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开) 时间:2010-05-07 地点:重庆航天职业学院 描述:有表tb, 如下: id value ----------- ----------- 1 aa,bb 2 aaa,bbb,ccc 欲按id,分拆value列, 分拆后结果如下: id value ----------- -------- 1 aa 1 bb 2 aaa 2 bbb 2 ccc */--1. 旧的解决方法(sql server 2000)create table tb(id int,value varchar(30)) insert into tb values(1,'aa,bb') insert into tb values(2,'aaa,bbb,ccc') go--方法1.使用临时表完成 SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b SELECT A.id, value = SUBSTRING(A.[value], B.id, CHARINDEX(',', A.[value] + ',', B.id) - B.id) FROM tb A, # B WHERE SUBSTRING(',' + A.[value], B.id, 1) = ','DROP TABLE #--方法2.如果数据量小,可不使用临时表 select a.id , value = substring(a.value , b.number , charindex(',' , a.value + ',' , b.number) - b.number) from tb a join master..spt_values b on b.type='p' and b.number between 1 and len(a.value) where substring(',' + a.value , b.number , 1) = ','--2. 新的解决方法(sql server 2005) create table tb(id int,value varchar(30)) insert into tb values(1,'aa,bb') insert into tb values(2,'aaa,bbb,ccc') go--方法1.使用xml完成 SELECT A.id, B.value FROM ( SELECT id, [value] = CONVERT(xml,'<root><v>' + REPLACE([value], ',', '</v><v>') + '</v></root>') FROM tb ) A OUTER APPLY ( SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v) ) B--方法2.使用CTE完成 ;with tt as (select id,[value]=cast(left([value],charindex(',',[value]+',')-1) as nvarchar(100)),Split=cast(stuff([value]+',',1,charindex(',',[value]+','),'') as nvarchar(100)) from tb union all select id,[value]=cast(left(Split,charindex(',',Split)-1) as nvarchar(100)),Split= cast(stuff(Split,1,charindex(',',Split),'') as nvarchar(100)) from tt where split>'' ) select id,[value] from tt order by id option (MAXRECURSION 0) DROP TABLE tb/* id value ----------- ------------------------------ 1 aa 1 bb 2 aaa 2 bbb 2 ccc(5 行受影响) */
with cte as (select left(col,charindex(',',col)-1) a, substring(col,charindex(',',col)+1,len(col)) b from [table]) select a+(select ','+b from cte where a=t.a for xml path('')) from cte t
create table #tb (col varchar(100)) insert into #tb select 'a1,aa,p' union select 'a1,bb,r' union select 'a2,qq,p' union select 'a2,cc,r'with cte as (select left(col,charindex(',',col)-1) a, substring(col,charindex(',',col)+1,len(col)) b from #tb) select a+(select ','+b from cte where a=t.a for xml path('')) from cte t group by a/* a1,aa,p,bb,r a2,qq,p,cc,r*/
看看题目再写SQL呀,兄弟!!!!!!!!!!!!!!
有问题?create table #tb (col varchar(100)) insert into #tb select 'a1,aa,p' union select 'a1,bb,r' union select 'a2,qq,p' union select 'a2,cc,r' select a+(select ','+b from cte where a=t.a for xml path('')) from (select left(col,charindex(',',col)-1) a, substring(col,charindex(',',col)+1,len(col)) b from #tb) t group by a/* a1,aa,p,bb,r a2,qq,p,cc,r*/
/* 标题:简单数据拆分(version 2.0) 作者:爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开) 时间:2010-05-07 地点:重庆航天职业学院 描述:有表tb, 如下: id value ----------- ----------- 1 aa,bb 2 aaa,bbb,ccc 欲按id,分拆value列, 分拆后结果如下: id value ----------- -------- 1 aa 1 bb 2 aaa 2 bbb 2 ccc */--1. 旧的解决方法(sql server 2000)create table tb(id int,value varchar(30)) insert into tb values(1,'aa,bb') insert into tb values(2,'aaa,bbb,ccc') go--方法1.使用临时表完成 SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b SELECT A.id, value = SUBSTRING(A.[value], B.id, CHARINDEX(',', A.[value] + ',', B.id) - B.id) FROM tb A, # B WHERE SUBSTRING(',' + A.[value], B.id, 1) = ','DROP TABLE #--方法2.如果数据量小,可不使用临时表 select a.id , value = substring(a.value , b.number , charindex(',' , a.value + ',' , b.number) - b.number) from tb a join master..spt_values b on b.type='p' and b.number between 1 and len(a.value) where substring(',' + a.value , b.number , 1) = ','--2. 新的解决方法(sql server 2005) create table tb(id int,value varchar(30)) insert into tb values(1,'aa,bb') insert into tb values(2,'aaa,bbb,ccc') go--方法1.使用xml完成 SELECT A.id, B.value FROM ( SELECT id, [value] = CONVERT(xml,'<root><v>' + REPLACE([value], ',', '</v><v>') + '</v></root>') FROM tb ) A OUTER APPLY ( SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v) ) B--方法2.使用CTE完成 ;with tt as (select id,[value]=cast(left([value],charindex(',',[value]+',')-1) as nvarchar(100)),Split=cast(stuff([value]+',',1,charindex(',',[value]+','),'') as nvarchar(100)) from tb union all select id,[value]=cast(left(Split,charindex(',',Split)-1) as nvarchar(100)),Split= cast(stuff(Split,1,charindex(',',Split),'') as nvarchar(100)) from tt where split>'' ) select id,[value] from tt order by id option (MAXRECURSION 0) DROP TABLE tb/* id value ----------- ------------------------------ 1 aa 1 bb 2 aaa 2 bbb 2 ccc(5 行受影响) */
--> 测试数据:[tb] if object_id('[tb]') is not null drop table [tb] go create table [tb]([F1] varchar(2),[F2] varchar(2),[F3] varchar(1)) insert [tb] select 'a1','aa','p' union all select 'a1','bb','r' union all select 'a2','qq','p' union all select 'a2','cc','r' go select * from tbwith cte as (select *,id=ROW_NUMBER()over(partition by F1 order by getdate()) from tb)select a.F1,a.F2,a.F3,b.F2 as F4,b.F3 as F5 from (select * from cte where id=1) a left join (select * from cte where id=2) b on a.F1=b.F1/* F1 F2 F3 F2 F3 ---- ---- ---- ---- ---- a1 aa p bb r a2 qq p cc r(2 行受影响) */
--方法一见#11 --方法二 --> 测试数据:[tb] if object_id('[tb]') is not null drop table [tb] go create table [tb]([F1] varchar(2),[F2] varchar(2),[F3] varchar(1)) insert [tb] select 'a1','aa','p' union all select 'a1','bb','r' union all select 'a2','qq','p' union all select 'a2','cc','r' gowith cte as ( select F1,F2=(select ''+F2 from tb where F1=t.F1 for xml path('')),F3=(select ''+F3 from tb where F1=t.F1 for xml path('')) from tb t group by F1)select F1,LEFT(F2,2) F2,LEFT(F3,2) F3,RIGHT(F2,2) F4,RIGHT(F3,2) F5 from cte/* F1 F2 F3 F4 F5 ---- ---- ---- ---- ---- a1 aa p bb r a2 qq p cc r(2 行受影响) */
/*
标题:简单数据拆分(version 2.0)
作者:爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开)
时间:2010-05-07
地点:重庆航天职业学院
描述:有表tb, 如下:
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
欲按id,分拆value列, 分拆后结果如下:
id value
----------- --------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
*/--1. 旧的解决方法(sql server 2000)create table tb(id int,value varchar(30))
insert into tb values(1,'aa,bb')
insert into tb values(2,'aaa,bbb,ccc')
go--方法1.使用临时表完成
SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b SELECT A.id, value = SUBSTRING(A.[value], B.id, CHARINDEX(',', A.[value] + ',', B.id) - B.id)
FROM tb A, # B
WHERE SUBSTRING(',' + A.[value], B.id, 1) = ','DROP TABLE #--方法2.如果数据量小,可不使用临时表
select a.id , value = substring(a.value , b.number , charindex(',' , a.value + ',' , b.number) - b.number)
from tb a join master..spt_values b
on b.type='p' and b.number between 1 and len(a.value)
where substring(',' + a.value , b.number , 1) = ','--2. 新的解决方法(sql server 2005)
create table tb(id int,value varchar(30))
insert into tb values(1,'aa,bb')
insert into tb values(2,'aaa,bbb,ccc')
go--方法1.使用xml完成
SELECT A.id, B.value FROM
(
SELECT id, [value] = CONVERT(xml,'<root><v>' + REPLACE([value], ',', '</v><v>') + '</v></root>') FROM tb
) A OUTER APPLY
(
SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v)
) B--方法2.使用CTE完成
;with tt as
(select id,[value]=cast(left([value],charindex(',',[value]+',')-1) as nvarchar(100)),Split=cast(stuff([value]+',',1,charindex(',',[value]+','),'') as nvarchar(100)) from tb
union all
select id,[value]=cast(left(Split,charindex(',',Split)-1) as nvarchar(100)),Split= cast(stuff(Split,1,charindex(',',Split),'') as nvarchar(100)) from tt where split>''
)
select id,[value] from tt order by id option (MAXRECURSION 0)
DROP TABLE tb/*
id value
----------- ------------------------------
1 aa
1 bb
2 aaa
2 bbb
2 ccc(5 行受影响)
*/
with cte as
(select left(col,charindex(',',col)-1) a,
substring(col,charindex(',',col)+1,len(col)) b
from [table])
select a+(select ','+b from cte where a=t.a for xml path(''))
from cte t
create table #tb (col varchar(100)) insert into #tb
select 'a1,aa,p'
union select 'a1,bb,r'
union select 'a2,qq,p'
union select 'a2,cc,r'with cte as
(select left(col,charindex(',',col)-1) a,
substring(col,charindex(',',col)+1,len(col)) b
from #tb)
select a+(select ','+b from cte where a=t.a for xml path(''))
from cte t group by a/*
a1,aa,p,bb,r
a2,qq,p,cc,r*/
有问题?create table #tb (col varchar(100)) insert into #tb
select 'a1,aa,p'
union select 'a1,bb,r'
union select 'a2,qq,p'
union select 'a2,cc,r'
select a+(select ','+b from cte where a=t.a for xml path(''))
from (select left(col,charindex(',',col)-1) a,
substring(col,charindex(',',col)+1,len(col)) b
from #tb)
t group by a/*
a1,aa,p,bb,r
a2,qq,p,cc,r*/
标题:简单数据拆分(version 2.0)
作者:爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开)
时间:2010-05-07
地点:重庆航天职业学院
描述:有表tb, 如下:
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
欲按id,分拆value列, 分拆后结果如下:
id value
----------- --------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
*/--1. 旧的解决方法(sql server 2000)create table tb(id int,value varchar(30))
insert into tb values(1,'aa,bb')
insert into tb values(2,'aaa,bbb,ccc')
go--方法1.使用临时表完成
SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b SELECT A.id, value = SUBSTRING(A.[value], B.id, CHARINDEX(',', A.[value] + ',', B.id) - B.id)
FROM tb A, # B
WHERE SUBSTRING(',' + A.[value], B.id, 1) = ','DROP TABLE #--方法2.如果数据量小,可不使用临时表
select a.id , value = substring(a.value , b.number , charindex(',' , a.value + ',' , b.number) - b.number)
from tb a join master..spt_values b
on b.type='p' and b.number between 1 and len(a.value)
where substring(',' + a.value , b.number , 1) = ','--2. 新的解决方法(sql server 2005)
create table tb(id int,value varchar(30))
insert into tb values(1,'aa,bb')
insert into tb values(2,'aaa,bbb,ccc')
go--方法1.使用xml完成
SELECT A.id, B.value FROM
(
SELECT id, [value] = CONVERT(xml,'<root><v>' + REPLACE([value], ',', '</v><v>') + '</v></root>') FROM tb
) A OUTER APPLY
(
SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v)
) B--方法2.使用CTE完成
;with tt as
(select id,[value]=cast(left([value],charindex(',',[value]+',')-1) as nvarchar(100)),Split=cast(stuff([value]+',',1,charindex(',',[value]+','),'') as nvarchar(100)) from tb
union all
select id,[value]=cast(left(Split,charindex(',',Split)-1) as nvarchar(100)),Split= cast(stuff(Split,1,charindex(',',Split),'') as nvarchar(100)) from tt where split>''
)
select id,[value] from tt order by id option (MAXRECURSION 0)
DROP TABLE tb/*
id value
----------- ------------------------------
1 aa
1 bb
2 aaa
2 bbb
2 ccc(5 行受影响)
*/
--> 测试数据:[tb]
if object_id('[tb]') is not null drop table [tb]
go
create table [tb]([F1] varchar(2),[F2] varchar(2),[F3] varchar(1))
insert [tb]
select 'a1','aa','p' union all
select 'a1','bb','r' union all
select 'a2','qq','p' union all
select 'a2','cc','r'
go
select * from tbwith cte as
(select *,id=ROW_NUMBER()over(partition by F1 order by getdate()) from tb)select a.F1,a.F2,a.F3,b.F2 as F4,b.F3 as F5
from (select * from cte where id=1) a
left join (select * from cte where id=2) b
on a.F1=b.F1/*
F1 F2 F3 F2 F3
---- ---- ---- ---- ----
a1 aa p bb r
a2 qq p cc r(2 行受影响)
*/
--方法一见#11
--方法二 --> 测试数据:[tb]
if object_id('[tb]') is not null drop table [tb]
go
create table [tb]([F1] varchar(2),[F2] varchar(2),[F3] varchar(1))
insert [tb]
select 'a1','aa','p' union all
select 'a1','bb','r' union all
select 'a2','qq','p' union all
select 'a2','cc','r'
gowith cte as (
select F1,F2=(select ''+F2 from tb where F1=t.F1 for xml path('')),F3=(select ''+F3 from tb where F1=t.F1 for xml path(''))
from tb t group by F1)select F1,LEFT(F2,2) F2,LEFT(F3,2) F3,RIGHT(F2,2) F4,RIGHT(F3,2) F5 from cte/*
F1 F2 F3 F4 F5
---- ---- ---- ---- ----
a1 aa p bb r
a2 qq p cc r(2 行受影响)
*/