SELECT a.`ID` , a.`用户名` ,`姓名`,`单位`,a.`操作IP`,a.`更新日期`,`操作类别`,`标题` FROM modify_log a LEFT JOIN usermanager b ON a.`用户名` = b.`帐户` LEFT JOIN news c ON a.`记录ID` = c.`ID` order by a.`ID` desc
还是先 Create table 吧 create table emp( id int not null primary key, name varchar(10) ); create table emp_dept( dept_id varchar(4) not null, emp_id int not null, emp_name varchar(10), primary key (dept_id,emp_id)); insert into emp() values (1,"Dennis-1"), (2,"Dennis-2"), (3,"Dennis-3"), (4,"Dennis-4"), (5,"Dennis-5"), (6,"Dennis-6"), (7,"Dennis-7"), (8,"Dennis-8"), (9,"Dennis-9"), (10,"Dennis-10"); insert into emp_dept() values ("R&D",1,"Dennis-1"), ("DEv",2,"Dennis-2"), ("R&D",3,"Dennis-3"), ("Test",4,"Dennis-4"), ("Test",5,"Dennis-5"); ("dddd",20,"eeee"); >> left join ------------- select a.id,a.name,b.dept_id from emp a left join emp_dept b on (a.id=b.emp_id); # 挑出左边的 table emp 中的所有资料,即使 emp_dept 中没有的资料也挑出来,没有的就用 NULL 来显示, # 也即显示资料是以左边的 table emp 中的资料为基础 mysql> select a.id,a.name,b.dept_id -> from emp a left join emp_dept b on (a.id=b.emp_id); +----+-----------+---------+ | id | name | dept_id | +----+-----------+---------+ | 1 | Dennis-1 | R&D | | 2 | Dennis-2 | DEv | | 3 | Dennis-3 | R&D | | 4 | Dennis-4 | Test | | 5 | Dennis-5 | Test | | 6 | Dennis-6 | NULL | | 7 | Dennis-7 | NULL | | 8 | Dennis-8 | NULL | | 9 | Dennis-9 | NULL | | 10 | Dennis-10 | NULL | +----+-----------+---------+ # 挑出 table emp 中有而 table emp_dept 中没有的人员资料 select a.id,a.name,b.dept_id from emp a left join emp_dept b on (a.id=b.emp_id) where b.dept_id IS NULL; mysql> select a.id,a.name,b.dept_id -> from emp a left join emp_dept b on (a.id=b.emp_id) -> where b.dept_id IS NULL; +----+-----------+---------+ | id | name | dept_id | +----+-----------+---------+ | 6 | Dennis-6 | NULL | | 7 | Dennis-7 | NULL | | 8 | Dennis-8 | NULL | | 9 | Dennis-9 | NULL | | 10 | Dennis-10 | NULL | +----+-----------+---------+ # 把 table emp_dept 放在左边的情形(当然以 emp_dept 中的数据为基础来显示资料,emp 中比emp_dept 中多的资料也就不会显示出来了): select a.id,a.name,b.dept_id from emp_dept b left join emp a on (a.id=b.emp_id); mysql> select a.id,a.name,b.dept_id -> from emp_dept b left join emp a on (a.id=b.emp_id); +------+----------+---------+ | id | name | dept_id | +------+----------+---------+ | NULL | NULL | dddd | | 2 | Dennis-2 | DEv | | 1 | Dennis-1 | R&D | | 3 | Dennis-3 | R&D | | 4 | Dennis-4 | Test | | 5 | Dennis-5 | Test | +------+----------+---------+ >> right join --------------- select a.id,a.name,b.dept_id from emp a right join emp_dept b on (a.id=b.emp_id); # 挑资料时以右边 table emp_dept 中的资料为基础来显示资料 mysql> select a.id,a.name,b.dept_id -> from emp a right join emp_dept b on (a.id=b.emp_id); +------+----------+---------+ | id | name | dept_id | +------+----------+---------+ | NULL | NULL | dddd | | 2 | Dennis-2 | DEv | | 1 | Dennis-1 | R&D | | 3 | Dennis-3 | R&D | | 4 | Dennis-4 | Test | | 5 | Dennis-5 | Test | +------+----------+---------+ 6 rows in set (0.00 sec) # 我们再把 table 的位置交换一下,再用 right join 试试 select a.id,a.name,b.dept_id from emp_dept b right join emp a on (a.id=b.emp_id); mysql> select a.id,a.name,b.dept_id -> from emp_dept b right join emp a on (a.id=b.emp_id); +----+-----------+---------+ | id | name | dept_id | +----+-----------+---------+ | 1 | Dennis-1 | R&D | | 2 | Dennis-2 | DEv | | 3 | Dennis-3 | R&D | | 4 | Dennis-4 | Test | | 5 | Dennis-5 | Test | | 6 | Dennis-6 | NULL | | 7 | Dennis-7 | NULL | | 8 | Dennis-8 | NULL | | 9 | Dennis-9 | NULL | | 10 | Dennis-10 | NULL | +----+-----------+---------+ # 是不是和 left join 一样了? >> inner join STRAIGHT_JOIN select a.id,a.name,b.dept_id from emp a ,emp_dept b where a.id=b.emp_id; mysql> select a.id,a.name,b.dept_id -> from emp a ,emp_dept b -> where a.id=b.emp_id; +----+----------+---------+ | id | name | dept_id | +----+----------+---------+ | 2 | Dennis-2 | DEv | | 1 | Dennis-1 | R&D | | 3 | Dennis-3 | R&D | | 4 | Dennis-4 | Test | | 5 | Dennis-5 | Test | +----+----------+---------+
id int not null primary key,
name varchar(10)
); create table emp_dept(
dept_id varchar(4) not null,
emp_id int not null,
emp_name varchar(10),
primary key (dept_id,emp_id)); insert into emp() values
(1,"Dennis-1"),
(2,"Dennis-2"),
(3,"Dennis-3"),
(4,"Dennis-4"),
(5,"Dennis-5"),
(6,"Dennis-6"),
(7,"Dennis-7"),
(8,"Dennis-8"),
(9,"Dennis-9"),
(10,"Dennis-10"); insert into emp_dept() values
("R&D",1,"Dennis-1"),
("DEv",2,"Dennis-2"),
("R&D",3,"Dennis-3"),
("Test",4,"Dennis-4"),
("Test",5,"Dennis-5");
("dddd",20,"eeee");
>> left join
-------------
select a.id,a.name,b.dept_id
from emp a left join emp_dept b on (a.id=b.emp_id); # 挑出左边的 table emp 中的所有资料,即使 emp_dept 中没有的资料也挑出来,没有的就用 NULL 来显示,
# 也即显示资料是以左边的 table emp 中的资料为基础 mysql> select a.id,a.name,b.dept_id
-> from emp a left join emp_dept b on (a.id=b.emp_id);
+----+-----------+---------+
| id | name | dept_id |
+----+-----------+---------+
| 1 | Dennis-1 | R&D |
| 2 | Dennis-2 | DEv |
| 3 | Dennis-3 | R&D |
| 4 | Dennis-4 | Test |
| 5 | Dennis-5 | Test |
| 6 | Dennis-6 | NULL |
| 7 | Dennis-7 | NULL |
| 8 | Dennis-8 | NULL |
| 9 | Dennis-9 | NULL |
| 10 | Dennis-10 | NULL |
+----+-----------+---------+
# 挑出 table emp 中有而 table emp_dept 中没有的人员资料
select a.id,a.name,b.dept_id
from emp a left join emp_dept b on (a.id=b.emp_id)
where b.dept_id IS NULL; mysql> select a.id,a.name,b.dept_id
-> from emp a left join emp_dept b on (a.id=b.emp_id)
-> where b.dept_id IS NULL;
+----+-----------+---------+
| id | name | dept_id |
+----+-----------+---------+
| 6 | Dennis-6 | NULL |
| 7 | Dennis-7 | NULL |
| 8 | Dennis-8 | NULL |
| 9 | Dennis-9 | NULL |
| 10 | Dennis-10 | NULL |
+----+-----------+---------+ # 把 table emp_dept 放在左边的情形(当然以 emp_dept 中的数据为基础来显示资料,emp 中比emp_dept 中多的资料也就不会显示出来了):
select a.id,a.name,b.dept_id
from emp_dept b left join emp a on (a.id=b.emp_id);
mysql> select a.id,a.name,b.dept_id
-> from emp_dept b left join emp a on (a.id=b.emp_id);
+------+----------+---------+
| id | name | dept_id |
+------+----------+---------+
| NULL | NULL | dddd |
| 2 | Dennis-2 | DEv |
| 1 | Dennis-1 | R&D |
| 3 | Dennis-3 | R&D |
| 4 | Dennis-4 | Test |
| 5 | Dennis-5 | Test |
+------+----------+---------+
>> right join
---------------
select a.id,a.name,b.dept_id
from emp a right join emp_dept b on (a.id=b.emp_id);
# 挑资料时以右边 table emp_dept 中的资料为基础来显示资料
mysql> select a.id,a.name,b.dept_id
-> from emp a right join emp_dept b on (a.id=b.emp_id);
+------+----------+---------+
| id | name | dept_id |
+------+----------+---------+
| NULL | NULL | dddd |
| 2 | Dennis-2 | DEv |
| 1 | Dennis-1 | R&D |
| 3 | Dennis-3 | R&D |
| 4 | Dennis-4 | Test |
| 5 | Dennis-5 | Test |
+------+----------+---------+
6 rows in set (0.00 sec)
# 我们再把 table 的位置交换一下,再用 right join 试试 select a.id,a.name,b.dept_id
from emp_dept b right join emp a on (a.id=b.emp_id); mysql> select a.id,a.name,b.dept_id
-> from emp_dept b right join emp a on (a.id=b.emp_id);
+----+-----------+---------+
| id | name | dept_id |
+----+-----------+---------+
| 1 | Dennis-1 | R&D |
| 2 | Dennis-2 | DEv |
| 3 | Dennis-3 | R&D |
| 4 | Dennis-4 | Test |
| 5 | Dennis-5 | Test |
| 6 | Dennis-6 | NULL |
| 7 | Dennis-7 | NULL |
| 8 | Dennis-8 | NULL |
| 9 | Dennis-9 | NULL |
| 10 | Dennis-10 | NULL |
+----+-----------+---------+
# 是不是和 left join 一样了?
>> inner join STRAIGHT_JOIN
select a.id,a.name,b.dept_id
from emp a ,emp_dept b
where a.id=b.emp_id; mysql> select a.id,a.name,b.dept_id
-> from emp a ,emp_dept b
-> where a.id=b.emp_id;
+----+----------+---------+
| id | name | dept_id |
+----+----------+---------+
| 2 | Dennis-2 | DEv |
| 1 | Dennis-1 | R&D |
| 3 | Dennis-3 | R&D |
| 4 | Dennis-4 | Test |
| 5 | Dennis-5 | Test |
+----+----------+---------+