<?php
$sql = "select * from `teblename` where `grade` = 2";
$arr = mysql_query($sql) or die(错了吧。);
while( $row = mysql_fetch_array($arr) )
{
echo $row['id']; echo '<br>';
}
?>
$sql = "select * from `teblename` where `grade` = 2";
$arr = mysql_query($sql) or die(错了吧。);
while( $row = mysql_fetch_array($arr) )
{
echo $row['id']; echo '<br>';
}
?>
解决方案 »
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