情况描述:
select id from table XXX 可以获取到
1
2
5
7
9
10
11
12
13
14
15
16
17
直接用sql来编写使
select 各种天才想法 id from table XXX得到结果为
1-2,5,7,9-17这么个结果
没有思路哇,高手给大家表演下。~~~~~~~~~鼓掌!!!
select id from table XXX 可以获取到
1
2
5
7
9
10
11
12
13
14
15
16
17
直接用sql来编写使
select 各种天才想法 id from table XXX得到结果为
1-2,5,7,9-17这么个结果
没有思路哇,高手给大家表演下。~~~~~~~~~鼓掌!!!
--写个……………………
select *
from (select level rn
from dual
connect by level<18)
where rn not in(3,4,6,8)
[SYS@orcl] SQL>WITH xxx AS(
2 SELECT 1 ID FROM DUAL UNION ALL
3 SELECT 2 ID FROM DUAL UNION ALL
4 SELECT 5 ID FROM DUAL UNION ALL
5 SELECT 7 ID FROM DUAL UNION ALL
6 SELECT 9 ID FROM DUAL UNION ALL
7 SELECT 10 ID FROM DUAL UNION ALL
8 SELECT 11 ID FROM DUAL UNION ALL
9 SELECT 12 ID FROM DUAL UNION ALL
10 SELECT 13 ID FROM DUAL UNION ALL
11 SELECT 14 ID FROM DUAL UNION ALL
12 SELECT 15 ID FROM DUAL UNION ALL
13 SELECT 16 ID FROM DUAL UNION ALL
14 SELECT 17 ID FROM DUAL)
15 SELECT WM_CONCAT(DECODE(MIID, MAID, TO_CHAR(MAID), MIID || '-' || MAID))
16 FROM (SELECT MIN(ID) MIID, MAX(ID) MAID
17 FROM (SELECT ID, ID - DENSE_RANK() OVER(ORDER BY ID) ROW_ FROM XXX)
18 GROUP BY ROW_
19 ORDER BY MIID);WM_CONCAT(DECODE(MIID,MAID,TO_CHAR(MAID),MIID||'-'||MAID))
--------------------------------------------------------------------------------
1-2,5,7,9-17
with xxx as
(select rownum id
from dual
connect by rownum < 18
minus (select 3
from dual
union all
select 4
from dual
union
select 6
from dual
union
select 8 from dual))
--以上是测试数据
select cast (wm_concat(id) as varchar2(4000)) id
from (select case count(1)
when 1 then
to_char(min(id))
else
min(id) || '-' || max(id)
end id
from (select id from xxx order by id)
group by rownum - id
order by id)
SELECT ID,ROWNUM rn FROM vnum ORDER BY ID)
GROUP BY ID-rn
ORDER BY gd;