我有一个表a
如下表
itemid typeid typename
1 1 aaa
1 2 bbb
2 3 ccc
2 5 ddd
3 5 ddd表b如下表
itemid itemname
1 kkkk
2 llll
3 ooooa表同b表通过itemid 关联,取出下表记录格式
itemid itemname typename
1 kkkk aaa,bbb
2 llll ccc,ddd
3 oooo ddd请高手指教如何才能得到这个结果格式的SQL语句,多谢!
如下表
itemid typeid typename
1 1 aaa
1 2 bbb
2 3 ccc
2 5 ddd
3 5 ddd表b如下表
itemid itemname
1 kkkk
2 llll
3 ooooa表同b表通过itemid 关联,取出下表记录格式
itemid itemname typename
1 kkkk aaa,bbb
2 llll ccc,ddd
3 oooo ddd请高手指教如何才能得到这个结果格式的SQL语句,多谢!
select itemid,itemname,wm_concat(typename) typename
from a,b
where a.itemid=b.itemid
group by itemid,itemname
SQL> select * from a;
/*
ITEMID TYPEID TYPENAME
--------------------------------------- --------------------------------------- ----------
1 2 bbb
2 3 ccc
2 5 ddd
3 5 ddd
1 1 aaa
*/
SQL> select * from b;
/*
ITEMID ITEMNAME
--------------------------------------- ----------
1 kkk
2 lll
3 ooo
*/
SQL> select a.itemid,b.itemname,wmsys.wm_concat(a.typename)
2 from a,b
3 where a.itemid=b.itemid
4 group by a.itemid,b.itemname;
/*
ITEMID ITEMNAME WMSYS.WM_CONCAT(A.TYPENAME)
--------------------------------------- ---------- --------------------------------------------------------------------------------
1 kkk bbb,aaa
2 lll ccc,ddd
3 ooo ddd
*/