方法我在网上已经搜索出来了,但是不知道咋调用到表中方法如下:
CREATE OR REPLACE TYPE ty_str_split IS TABLE OF VARCHAR2 (4000);
CREATE OR REPLACE FUNCTION fn_split (p_str IN VARCHAR2, p_delimiter IN VARCHAR2)
RETURN ty_str_split
IS
j INT := 0;
i INT := 1;
len INT := 0;
len1 INT := 0;
str VARCHAR2 (4000);
str_split ty_str_split := ty_str_split ();
BEGIN
len := LENGTH (p_str);
len1 := LENGTH (p_delimiter);
WHILE j < len
LOOP
j := INSTR (p_str, p_delimiter, i);
IF j = 0
THEN
j := len;
str := SUBSTR (p_str, i);
str_split.EXTEND;
str_split (str_split.COUNT) := str;
IF i >= len
THEN
EXIT;
END IF;
ELSE
str := SUBSTR (p_str, i, j - i);
i := j + len1;
str_split.EXTEND;
str_split (str_split.COUNT) := str;
END IF;
END LOOP;
RETURN str_split;
END fn_split;调用:
单独拆分一个字符
如:select fn_split('a,b,c,aa,d',',') from dual
执行结果是
a
b
c
aa
d但如果我是要拆分表A中的 d字段内容呢 A表有很多条记录。我该怎么用,求帮忙
CREATE OR REPLACE TYPE ty_str_split IS TABLE OF VARCHAR2 (4000);
CREATE OR REPLACE FUNCTION fn_split (p_str IN VARCHAR2, p_delimiter IN VARCHAR2)
RETURN ty_str_split
IS
j INT := 0;
i INT := 1;
len INT := 0;
len1 INT := 0;
str VARCHAR2 (4000);
str_split ty_str_split := ty_str_split ();
BEGIN
len := LENGTH (p_str);
len1 := LENGTH (p_delimiter);
WHILE j < len
LOOP
j := INSTR (p_str, p_delimiter, i);
IF j = 0
THEN
j := len;
str := SUBSTR (p_str, i);
str_split.EXTEND;
str_split (str_split.COUNT) := str;
IF i >= len
THEN
EXIT;
END IF;
ELSE
str := SUBSTR (p_str, i, j - i);
i := j + len1;
str_split.EXTEND;
str_split (str_split.COUNT) := str;
END IF;
END LOOP;
RETURN str_split;
END fn_split;调用:
单独拆分一个字符
如:select fn_split('a,b,c,aa,d',',') from dual
执行结果是
a
b
c
aa
d但如果我是要拆分表A中的 d字段内容呢 A表有很多条记录。我该怎么用,求帮忙
SQL> create table ta as
2 select 'a,b,c,aa,d' chr from dual
3 /
Table created
SQL> select * from ta;
CHR
----------
a,b,c,aa,dSQL> create table tb as
2 select * from ta
3 where 1=0
4 /
Table created
SQL> select count(*) from tb;
COUNT(*)
----------
0
SQL> insert into tb
2 select regexp_substr(chr,'[^,]+',1,level) chr
3 from ta
4 connect by
5 level <= length(chr)-
6 length(replace(chr,',',''))+1
7 /
5 rows inserted
SQL> select * from tb;
CHR
----------
a
b
c
aa
d
SQL>
select 'test' name,'a,b,c,aa,d' id from dual
)
select name,regexp_substr(id,'[^,]+',1,level) as newid
from tab
connect by
level<=length(id)-length(replace(id,',',''))+1NAME NEWID
------------
test a
test b
test c
test aa
test d