select a.costid,a.add,sum(b.byy) from AA a,AA b where a.costid=substr(b.costid,
0,length(a.costid)) group by a.costid,a.add;
===============================================================
例:
SQL> select * from test4; ID COST NAME
---------- ---------- ----------
13 0 testname
1301 80 testname
1302 110 testnameSQL> select a.id,a.name,sum(b.cost) from test4 a,test4 b where a.id=substr(b.id,
0,length(a.id)) group by a.id,a.name; ID NAME SUM(B.COST)
---------- ---------- -----------
13 testname 190
1301 testname 80
1302 testname 110
0,length(a.costid)) group by a.costid,a.add;
===============================================================
例:
SQL> select * from test4; ID COST NAME
---------- ---------- ----------
13 0 testname
1301 80 testname
1302 110 testnameSQL> select a.id,a.name,sum(b.cost) from test4 a,test4 b where a.id=substr(b.id,
0,length(a.id)) group by a.id,a.name; ID NAME SUM(B.COST)
---------- ---------- -----------
13 testname 190
1301 testname 80
1302 testname 110
解决方案 »
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