别人的例子,可以参考一下 连接查询结果: 表a 列 a1 a2 记录 1 a 1 b 2 x 2 y 2 z 用select能选成以下结果: 1 ab 2 xyz 下面有两个例子: 1.使用pl/sql代码实现,但要求你组合后的长度不能超出oracle varchar2长度的限制 create or replace type strings_table is table of varchar2(20); / create or replace function merge (pv in strings_table) return varchar2 is ls varchar2(4000); begin for i in 1..pv.count loop ls := ls || pv(i); end loop; return ls; end; / create table t (id number,name varchar2(10)); insert into t values(1,'Joan'); insert into t values(1,'Jack'); insert into t values(1,'Tom'); insert into t values(2,'Rose'); insert into t values(2,'Jenny'); column names format a80; select t0.id,merge(cast(multiset(select name from t where t.id = t0.id) as strings_table)) names from (select distinct id from t) t0; drop type strings_table; drop function merge; drop table t; 2.纯粹用sql: 表dept, emp 要得到如下结果 deptno, dname, employees --------------------------------- 10, accounting, clark;king;miller 20, research, smith;adams;ford;scott;jones 30, sales, allen;blake;martin;james;turners 每个dept的employee串起来作为一条记录返回 This example uses a max of 6, and would need more cut n pasting to do more than that: SQL> select deptno, dname, emps 2 from ( 3 select d.deptno, d.dname, rtrim(e.ename ||', '|| 4 lead(e.ename,1) over (partition by d.deptno 5 order by e.ename) ||', '|| 6 lead(e.ename,2) over (partition by d.deptno 7 order by e.ename) ||', '|| 8 lead(e.ename,3) over (partition by d.deptno 9 order by e.ename) ||', '|| 10 lead(e.ename,4) over (partition by d.deptno 11 order by e.ename) ||', '|| 12 lead(e.ename,5) over (partition by d.deptno 13 order by e.ename),', ') emps, 14 row_number () over (partition by d.deptno 15 order by e.ename) x 16 from emp e, dept d 17 where d.deptno = e.deptno 18 ) 19 where x = 1 20 / DEPTNO DNAME EMPS ------- ----------- ------------------------------------------ 10 ACCOUNTING CLARK, KING, MILLER 20 RESEARCH ADAMS, FORD, JONES, ROONEY, SCOTT, SMITH 30 SALES ALLEN, BLAKE, JAMES, MARTIN, TURNER, WARD
连接查询结果:
表a 列 a1 a2
记录 1 a
1 b
2 x
2 y
2 z
用select能选成以下结果:
1 ab
2 xyz 下面有两个例子:
1.使用pl/sql代码实现,但要求你组合后的长度不能超出oracle varchar2长度的限制
create or replace type strings_table is table of varchar2(20);
/
create or replace function merge (pv in strings_table) return varchar2
is
ls varchar2(4000);
begin
for i in 1..pv.count loop
ls := ls || pv(i);
end loop;
return ls;
end;
/
create table t (id number,name varchar2(10));
insert into t values(1,'Joan');
insert into t values(1,'Jack');
insert into t values(1,'Tom');
insert into t values(2,'Rose');
insert into t values(2,'Jenny'); column names format a80;
select t0.id,merge(cast(multiset(select name from t where t.id = t0.id) as strings_table)) names
from (select distinct id from t) t0; drop type strings_table;
drop function merge;
drop table t;
2.纯粹用sql:
表dept, emp
要得到如下结果
deptno, dname, employees
---------------------------------
10, accounting, clark;king;miller
20, research, smith;adams;ford;scott;jones
30, sales, allen;blake;martin;james;turners
每个dept的employee串起来作为一条记录返回 This example uses a max of 6, and would need more cut n pasting to do more than that: SQL> select deptno, dname, emps
2 from (
3 select d.deptno, d.dname, rtrim(e.ename ||', '||
4 lead(e.ename,1) over (partition by d.deptno
5 order by e.ename) ||', '||
6 lead(e.ename,2) over (partition by d.deptno
7 order by e.ename) ||', '||
8 lead(e.ename,3) over (partition by d.deptno
9 order by e.ename) ||', '||
10 lead(e.ename,4) over (partition by d.deptno
11 order by e.ename) ||', '||
12 lead(e.ename,5) over (partition by d.deptno
13 order by e.ename),', ') emps,
14 row_number () over (partition by d.deptno
15 order by e.ename) x
16 from emp e, dept d
17 where d.deptno = e.deptno
18 )
19 where x = 1
20 / DEPTNO DNAME EMPS
------- ----------- ------------------------------------------
10 ACCOUNTING CLARK, KING, MILLER
20 RESEARCH ADAMS, FORD, JONES, ROONEY, SCOTT, SMITH
30 SALES ALLEN, BLAKE, JAMES, MARTIN, TURNER, WARD