SQL> select to_date('2002-01-01','yyyy-mm-dd')-to_date('2002-01-12','yyyy-mm-dd') from dual;TO_DATE('2002-01-01','YYYY-MM-DD')-TO_DATE('2002-01-12','YYYY-MM-DD')
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-11
带绝对值:
SQL> select abs(to_date('2002-01-01','yyyy-mm-dd')-to_date('2002-01-12','yyyy-mm-dd')) from dual;ABS(TO_DATE('2002-01-01','YYYY-MM-DD')-TO_DATE('2002-01-12','YYYY-MM-DD'))
--------------------------------------------------------------------------
11
-----------------------------------------
-11
带绝对值:
SQL> select abs(to_date('2002-01-01','yyyy-mm-dd')-to_date('2002-01-12','yyyy-mm-dd')) from dual;ABS(TO_DATE('2002-01-01','YYYY-MM-DD')-TO_DATE('2002-01-12','YYYY-MM-DD'))
--------------------------------------------------------------------------
11
解决方案 »
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