Union all 的各个结果集 count数 取得。。。 用Union all 的时候如何取得各个结果集 count数 这个Union all 是写在函数里的。 解决方案 » 免费领取超大流量手机卡,每月29元包185G流量+100分钟通话, 中国电信官方发货 select count(*) from(select * from a union allselect * from b ) select count(*) from(select 1 as a from a union allselect 2 as a from b )group by a这样应该可以吧1 select count(*) from (select * from a union all select * from b ) x select cn1 + cn2 from (select count(*) cn1 from a),(select count(*) cn2 from b ) select count(*) from (select 'X' from tbl1 union select 'X' from tbl2 ) 请帮忙解释一下这个正则表达式,谢谢! odbc连不上,请高手指点 Oracle Developer 6i 到底是什么? oracle中load用法 oracle9i下,多对多下的sql语句怎么写 Oracle的Bug 创建表时出现的奇怪情况. 登录独立启动时可以,但登录到Oracl Managerment Server 时就不行!!! ID自动增加怎么设? 一个略难的oracle分组查询问题 查询某表空间下某表中包含某个字段的表名 求验证ip地址的正则表达式?
(select * from a union all
select * from b )
(select 1 as a from a
union all
select 2 as a from b )
group by a这样应该可以吧1
select count(*) from
(select * from a union all
select * from b )
x
(select count(*) cn1 from a),(select count(*) cn2 from b )
(select 'X' from tbl1
union
select 'X' from tbl2 )