数组重组

Question

#原数组
$list = array(
0=>array('mid'=>1,'menu'=>'m1','level'=>1,'belong'=>0,'higher'=>'a1'),
1=>array('mid'=>1,'menu'=>'m1','level'=>1,'belong'=>0,'higher'=>'a2'),
2=>array('mid'=>1,'menu'=>'m1','level'=>1,'belong'=>0,'higher'=>'a3'),
3=>array('mid'=>2,'menu'=>'m2','level'=>1,'belong'=>0,'higher'=>' '),
4=>array('mid'=>3,'menu'=>'m3','level'=>1,'belong'=>0,'higher'=>' '),
5=>array('mid'=>4,'menu'=>'m4','level'=>1,'belong'=>0,'higher'=>'d1'),
6=>array('mid'=>5,'menu'=>'m5','level'=>1,'belong'=>0,'higher'=>'e1'),
7=>array('mid'=>5,'menu'=>'m5','level'=>1,'belong'=>0,'higher'=>'e2')
);
#从原数组中提取新数组
$menuArr = array(
0=>array('mid'=>1,'main'=>'m1','child'=>array('a1','a2','a3') ),
1=>array('mid'=>2,'main'=>'m2','child'=>' ',
2=>array('mid'=>3,'main'=>'m3','child'=>' ',
3=>array('mid'=>4,'main'=>'m4','child'=>array('d1') ),
4=>array('mid'=>5,'main'=>'m5','child'=>array('e1','e2') ),
);
#自己搞半天搞晕了：
$sign = null;
$n = 0;
$menuArr = array();
foreach($list as $men){
if($sign == $men['mid']){
echo "n:{$n}<br>";
$menuArr[$men['mid']]['main'] = $men['menu'];
$menuArr[$men['mid']]['child'][$n] = $men['higher'];  #提示这里不可解析
//array_push($menuArr[$men['mid']]['child'], $men['higher']);
$n++;
}else{
$n = 0;
$menuArr[$men['mid']]['main'] = $men['menu'];
$menuArr[$men['mid']]['child'] = $men['higher'];
}
$sign = $men['mid'];
}
print_r($menuArr);
#帮帮忙……
PHP数组

Answer 1

$list = array(
    0=>array('mid'=>1,'menu'=>'m1','level'=>1,'belong'=>0,'higher'=>'a1'),
    1=>array('mid'=>1,'menu'=>'m1','level'=>1,'belong'=>0,'higher'=>'a2'),
    2=>array('mid'=>1,'menu'=>'m1','level'=>1,'belong'=>0,'higher'=>'a3'),
    3=>array('mid'=>2,'menu'=>'m2','level'=>1,'belong'=>0,'higher'=>' '),
    4=>array('mid'=>3,'menu'=>'m3','level'=>1,'belong'=>0,'higher'=>' '),
    5=>array('mid'=>4,'menu'=>'m4','level'=>1,'belong'=>0,'higher'=>'d1'),
    6=>array('mid'=>5,'menu'=>'m5','level'=>1,'belong'=>0,'higher'=>'e1'),
    7=>array('mid'=>5,'menu'=>'m5','level'=>1,'belong'=>0,'higher'=>'e2')
    );
$menuArr = array();foreach($list as $v) {
  if(! isset($menuArr[$v['mid']]))
    $menuArr[$v['mid']] = array('mid' => $v['mid'], 'main' => $v['menu'], 'child' => array($v['higher']));
  else $menuArr[$v['mid']]['child'][] = $v['higher'];
}
$menuArr = array_values($menuArr);
print_r($menuArr);
Array
(
    [0] => Array
        (
            [mid] => 1
            [main] => m1
            [child] => Array
                (
                    [0] => a1
                    [1] => a2
                    [2] => a3
                )        )    [1] => Array
        (
            [mid] => 2
            [main] => m2
            [child] => Array
                (
                    [0] =>  
                )        )    [2] => Array
        (
            [mid] => 3
            [main] => m3
            [child] => Array
                (
                    [0] =>  
                )        )    [3] => Array
        (
            [mid] => 4
            [main] => m4
            [child] => Array
                (
                    [0] => d1
                )        )    [4] => Array
        (
            [mid] => 5
            [main] => m5
            [child] => Array
                (
                    [0] => e1
                    [1] => e2
                )        ))

Answer 2

为什么你的第6行
else $menuArr[$v['mid']]['child'][] = $v['higher'];
}没有报错？
我的这样写 $menuArr[$men['mid']]['child'][] = $men['higher']; 
提示：Fatal error: [] operator not supported for strings？

Answer 3

不明白你$sign == $men['mid']的作用,$men['mid']都不可能是空。用你的代码改了一下，可以了。
#原数组
$list = array(
    0=>array('mid'=>1,'menu'=>'m1','level'=>1,'belong'=>0,'higher'=>'a1'),
    1=>array('mid'=>1,'menu'=>'m1','level'=>1,'belong'=>0,'higher'=>'a2'),
    2=>array('mid'=>1,'menu'=>'m1','level'=>1,'belong'=>0,'higher'=>'a3'),
    3=>array('mid'=>2,'menu'=>'m2','level'=>1,'belong'=>0,'higher'=>' '),
    4=>array('mid'=>3,'menu'=>'m3','level'=>1,'belong'=>0,'higher'=>' '),
    5=>array('mid'=>4,'menu'=>'m4','level'=>1,'belong'=>0,'higher'=>'d1'),
    6=>array('mid'=>5,'menu'=>'m5','level'=>1,'belong'=>0,'higher'=>'e1'),
    7=>array('mid'=>5,'menu'=>'m5','level'=>1,'belong'=>0,'higher'=>'e2')
    );$menuArr = array();
foreach($list as $men){
    if(!isset($menuArr[$men['mid']])){
        $menuArr[$men['mid']]['mid'] = $men['mid'];
        $menuArr[$men['mid']]['main'] = $men['menu'];
        $menuArr[$men['mid']]['child'] = array($men['higher']);  #提示这里不可解析
    }else{
        array_push($menuArr[$men['mid']]['child'],$men['higher']);
    }
}
$menuArr = array_values($menuArr);echo '<pre>';
print_r($menuArr);
echo '</pre>';

Answer 4

没有说$men['mid']值是空，在我的代码的寓意是指当数组中$men['mid']的值相同时执行...

Answer 5

<?php#原数组
$list = array(
0=>array('mid'=>1,'menu'=>'m1','level'=>1,'belong'=>0,'higher'=>'a1'),
1=>array('mid'=>1,'menu'=>'m1','level'=>1,'belong'=>0,'higher'=>'a2'),
2=>array('mid'=>1,'menu'=>'m1','level'=>1,'belong'=>0,'higher'=>'a3'),
3=>array('mid'=>2,'menu'=>'m2','level'=>1,'belong'=>0,'higher'=>' '),
4=>array('mid'=>3,'menu'=>'m3','level'=>1,'belong'=>0,'higher'=>' '),
5=>array('mid'=>4,'menu'=>'m4','level'=>1,'belong'=>0,'higher'=>'d1'),
6=>array('mid'=>5,'menu'=>'m5','level'=>1,'belong'=>0,'higher'=>'e1'),
7=>array('mid'=>5,'menu'=>'m5','level'=>1,'belong'=>0,'higher'=>'e2')
);
#从原数组中提取新数组
$menuArr = array(
0=>array('mid'=>1,'main'=>'m1','child'=>array('a1','a2','a3') ),
1=>array('mid'=>2,'main'=>'m2','child'=>' '),
2=>array('mid'=>3,'main'=>'m3','child'=>' '),
3=>array('mid'=>4,'main'=>'m4','child'=>array('d1') ),
4=>array('mid'=>5,'main'=>'m5','child'=>array('e1','e2') )
);
#自己搞半天搞晕了：
$sign = null;
$n = 0; 
$menuArr = array();
foreach($list as $men){
if($sign == $men['mid']){
echo "n:{$n}<br>";
$menuArr[$men['mid']]['main'] = $men['menu'];
// index = 1时， $menuArr[$men['mid']]['child'] = 'a1', 一个字符串当作数组用你说能不出错么？
$menuArr[$men['mid']]['child'][$n] = $men['higher'];  #提示这里不可解析
//array_push($menuArr[$men['mid']]['child'], $men['higher']);
$n++;
}else{
$n = 1;
$menuArr[$men['mid']]['main'] = $men['menu'];
// index = 0时， $menuArr[$men['mid']]['child'] = 'a1'
//$menuArr[$men['mid']]['child'] = $men['higher'];
$menuArr[$men['mid']]['child'] = $men['higher'] != ' ' ? array($men['higher']) : '';
}

$sign = $men['mid'];
}
print_r($menuArr);
#帮帮忙……

Answer 6

$menuArr[$men['mid']]['child'] = $men['higher'];
后，$menuArr[$men['mid']]['child'] 是字符串
你再当做数组操作
$menuArr[$men['mid']]['child'][$n] = $men['higher'];
当然要报错