function subfl($uid,$num1){
$result1=mysql_query("select * from user where lid='".$uid."'");
echo "select * from user where lid='".$uid."'";
$num2=mysql_num_rows($result1)+$num1;
$num=$num2;
if($myrow1=mysql_fetch_array($result1)){
do {
$this->subfl($myrow1["id"],$num2);
}
while ($myrow1=mysql_fetch_array($result1));
}else{
$num1=$num2;
$result1=mysql_query("select * from user where lid='".$uid."'");
echo "select * from user where lid='".$uid."'";
$num2=mysql_num_rows($result1)+$num1;
$num=$num2;
if($myrow1=mysql_fetch_array($result1)){
do {
$this->subfl($myrow1["id"],$num2);
}
while ($myrow1=mysql_fetch_array($result1));
}else{
$num1=$num2;
解决方案 »
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