字符串解析json

Question

$str=({"success":true,"name":test,"email":"[email protected]","errCode":"0"});如何将errCode 直接提取输出???

Answer 1

在:php中:$m = json_decode($str);-->$m['errCode'];
在:js中:var m = eval(str);->m[0]['errCode '];

Answer 2

$str = '{"success":true,"name":"test","email":"[email protected]","errCode":"0"}';
echo json_decode($str)->errCode;

Answer 3

用str_replace()替换之。或者截取。

Answer 4

$str=({"success":true,"name":test,"email":"[email protected]","errCode":"0"});如果你这是 js 脚本，那么 alert($str.errCode) 就可以得到如果这是 php 代码，那么有语法错误如果这是传入的字符串，那么只能截取()中的内容，然后处理