<script language=javascript>
function check() {
form1.referer.value = escape(document.referrer);
form1.screenwidth.value = screen.width;}
</script>
<body onload="javascript:check();>
<form action="" method="post" name="form1">
<input type=hidden name=referer value="{referer}">
<input type=hidden name=screenwidth value="{screenwidth}"> <?
$ref=$_post['referer'];
$width=$_post['screenwidth'];
echo "$ref";
echo "$width";
?>
</form>
</body>
</html>
function check() {
form1.referer.value = escape(document.referrer);
form1.screenwidth.value = screen.width;}
</script>
<body onload="javascript:check();>
<form action="" method="post" name="form1">
<input type=hidden name=referer value="{referer}">
<input type=hidden name=screenwidth value="{screenwidth}"> <?
$ref=$_post['referer'];
$width=$_post['screenwidth'];
echo "$ref";
echo "$width";
?>
</form>
</body>
</html>
<script language=javascript>
function check() {
form1.referer.value = escape(document.referrer);
form1.screenwidth.value = screen.width;
form1.submit();
}
</script>
<body onload="javascript:check();>
<form action="" method="post" name="form1">
<input type=hidden name=referer value="{referer}">
<input type=hidden name=screenwidth value="{screenwidth}"> <?
$ref=$_POST['referer'];
$width=$_POST['screenwidth'];
echo "$ref";
echo "$width";
?>
</form>
</body>
</html>
function check() {
form1.referer.value = escape(document.referrer);
form1.screenwidth.value = screen.width;
form1.submit();
}
</script>
<body onload="javascript:check();>
<form action="#" method="post" name="form1">
<input type=hidden name=referer value="{referer}">
<input type=hidden name=screenwidth value="{screenwidth}"> <?
$ref=$_POST['referer'];
$width=$_POST['screenwidth'];
echo "$ref";
echo "$width";
?>
</form>
</body>
</html>你上面的代码什么也不显示啊,我把他改成action="#" ,,也不显示啊
<head>
<title>My Variables PHP Script</title> <script language=javascript>
function check() {
form1.referer.value = escape(document.referrer);
form1.screenwidth.value = screen.width;
form1.submit();
}
</script>
</head><body onload="javascript:check();>
<form action="#" method="post" name="form1">
<input type=hidden name=referer value="{referer}">
<input type=hidden name=screenwidth value="{screenwidth}"> <?
$ref=$_POST['referer'];
$width=$_POST['screenwidth'];
echo "$ref";
echo "$width";
?>
</form>
</body>
</html>
提示网页上有错误,而且什么也不显示啊?
麻烦你能不能帮忙写一个可以通过编译的代码??