在PHP里面,有这样的代码
new FlashLibraryActivate( 'http://i.dell.com/images/global/banner_engine/bannerengine2.swf?xmlPath=images%2fglobal%2fbrand%2fbillboard%2fxml%2fjp%2fbanner_jajp.xml&bannerPath=images%2fglobal%2fbrand%2fbillboard%2f930%2fja%2f','930','380','#FFFFFF','8',alternateMarkup73c952c41cef4af2a31d9b7c3c34c253,'','flashID_43790a39d7b5497a81b4256bcc53730e','high','noscale','true','opaque','false','');我想用正则过滤掉所有
new ****(******);这种形式的代码,请问怎么做?请高人指导
new FlashLibraryActivate( 'http://i.dell.com/images/global/banner_engine/bannerengine2.swf?xmlPath=images%2fglobal%2fbrand%2fbillboard%2fxml%2fjp%2fbanner_jajp.xml&bannerPath=images%2fglobal%2fbrand%2fbillboard%2f930%2fja%2f','930','380','#FFFFFF','8',alternateMarkup73c952c41cef4af2a31d9b7c3c34c253,'','flashID_43790a39d7b5497a81b4256bcc53730e','high','noscale','true','opaque','false','');我想用正则过滤掉所有
new ****(******);这种形式的代码,请问怎么做?请高人指导
preg_replace('/new[^(]+\(.*?\);/is','',$s);
这样可以吗,new后面有个空格的,这应该怎么写?
return preg_replace('/new\s*[^(\s]+\(.*?\)/is','',$this->html);太谢谢了,分都给你,我真想给点给我自己,呵呵