Failed opening required './include/common.php' ,改成$_SERVER["DOCUMENT_ROOT"].'/include/common.php' 才行
两种方法
1.改成到include目录的相对路径
require("./include/common.php");
2.设置php.ini中添加include目录到点include_path中
1.改成到include目录的相对路径
require("./include/common.php");
2.设置php.ini中添加include目录到点include_path中
require("./include/common.php");hehe,他原来就是这么写的
检查php.ini中include_path的定义,确认有 .; 或 ./;
本来就是这么写的,
to 唠叨:php.ini:
include_path = "D:\web\mkfbbs;./;."也不正确Warning: main(./include/common.php) [function.main]: failed to open stream: No such file or directory in D:\web\mkfbbs\index.php on line 19Fatal error: main() [function.require]: Failed opening required './include/common.php' (include_path='D:\web\mkfbbs;./;.') in D:\web\mkfbbs\index.php on line 19
怎么写?
require("include/common.php");
有办法吗?
-----------
-----------
-----------
-----------
-----------
-----------
-----------
-----------
-----------
-----------
-----------
-----------
-----------
-----------
?
require("include/common.php");可以吗?-----------------------可以
require("include/common.php");
有办法吗?
-----------是不是要设置php.ini
require("include/common.php");
有办法吗?
-----------是不是要设置php.ini
程序中可以这么写include_once("common.php");2。如果没有包含,可以在包含文件中使用相对路径
程序中可以这么写:include_once("/include/common.php");