代码如下:
26 $sql="SELECT * FROM `information` WHERE user = `$user`";
27 $resule=mysql_query($sql);
28 $row=mysql_fetch_array($resule);
29 if($row[anwser]!=$anwser)
30 echo "<script language=\"javascript\"> alert('提示答案错误,请重新填写!'); location.href='find.php';</script>";不知道哪错了,老是报错:
Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in E:\BBS\password.php on line 28求高手帮忙解决一下哇
26 $sql="SELECT * FROM `information` WHERE user = `$user`";
27 $resule=mysql_query($sql);
28 $row=mysql_fetch_array($resule);
29 if($row[anwser]!=$anwser)
30 echo "<script language=\"javascript\"> alert('提示答案错误,请重新填写!'); location.href='find.php';</script>";不知道哪错了,老是报错:
Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in E:\BBS\password.php on line 28求高手帮忙解决一下哇
if($row[anwser]!=$anwser) {
echo "<script language=\"javascript\"> alert('提示答案错误,请重新填写!'); location.href='find.php';</script>";
}