数组问题

Question

Array
(
    [0] => Array
        (
            [name] => goods
            [data] => Array
                (
                    [access_time] => 1297836795000
                    [num] => 6
                )
 
        )
 
    [1] => Array
        (
            [name] => article
            [data] => Array
                (
                    [access_time] => 1297831430000
                    [num] => 4
                )
 
        )
 
    [2] => Array
        (
            [name] => goods
            [data] => Array
                (
                    [access_time] => 1297836785000
                    [num] => 2
                )
 
        )
    [3] => Array
        (
            [name] => member
            [data] => Array
                (
                    [access_time] => 1297836785000
                    [num] => 2
                )
 
        ))以上数组如何变成Array
(
    [0] => Array
        (
            [name] => goods
            [data] => Array
                (
                    [access_time] => 1297836795000
                    [num] => 8                
                )
 
        )
 
    [1] => Array
        (
            [name] => article
            [data] => Array
                (
                    [access_time] => 1297831430000
                    [num] => 4
                )
 
        )
    [2] => Array
        (
            [name] => member
            [data] => Array
                (
                    [access_time] => 1297836785000
                    [num] => 2
                )
 
        ))

Answer 1

数组中相同的 name 合并 然后再把 num 相加

Answer 2

$a = array(
  array('name'=>'goods','data'=>array('access_time'=>'1297836795000','num'=>'6')),
  array('name'=>'article','data'=>array('access_time'=>'1297831430000','num'=>'4')),
  array('name'=>'goods','data'=>array('access_time'=>'1297836785000','num'=>'2')),
  array('name'=>'member','data'=>array('access_time'=>'1297836785000','num'=>'2')),
  array('name'=>'liuyan','data'=>array('access_time'=>'1297836765000','num'=>'8')),
  array('name'=>'xiaohua','data'=>array('access_time'=>'1297836766000','num'=>'8')),
  array('name'=>'liuyan','data'=>array('access_time'=>'1297836765000','num'=>'8'))
);$c = array();
$out = array() ;
foreach($a as $k=>$v){
  $c[] = $a[$k]['name'] ;
}$b = array_unique ($c);foreach($b as $k=>$v){
  $sum = 0 ;
  foreach($a as $i=>$m){
    if($m['name']==$v){
      $sum += $m['data']['num'] ;
      
    }
  }
  
  $out[$k]['name'] = $v ;
  $out[$k]['data']['access_time'] = $a[$k]['data']['access_time'] ;
  $out[$k]['data']['num'] = $sum ;
  
}
$out = array_values($out);
print_r($out);输出：
Array
(
    [0] => Array
        (
            [name] => goods
            [data] => Array
                (
                    [access_time] => 1297836795000
                    [num] => 8
                )        )    [1] => Array
        (
            [name] => article
            [data] => Array
                (
                    [access_time] => 1297831430000
                    [num] => 4
                )        )    [3] => Array
        (
            [name] => member
            [data] => Array
                (
                    [access_time] => 1297836785000
                    [num] => 2
                )        )    [4] => Array
        (
            [name] => liuyan
            [data] => Array
                (
                    [access_time] => 1297836765000
                    [num] => 16
                )        )    [5] => Array
        (
            [name] => xiaohua
            [data] => Array
                (
                    [access_time] => 1297836766000
                    [num] => 8
                )        ))

Answer 3

这个可行，就是步骤多了一点。我记得应该有一个PHP函数可以直接处理NAME重复的问题，但是怎么也想不起来了。

Answer 4

楼主说的是这个函数：array_unique
显然解决你的问题肯定要用到这个函数，我也用了， 但是仅仅用这个函数是解决不了问题的，因为你的数组是多维的，且每一维的值都有区别。我的那个代码在数组很大而重复的却不多的情况下效率不高。可以进一步优化代码，
也就是 计算出b和c的差集，然后foreach这个差集 这样效率就高多了，不至于做无用的搜索。

Answer 5

这样效率更高些$a = array(
  array('name'=>'goods','data'=>array('access_time'=>'1297836795000','num'=>'6')),
  array('name'=>'article','data'=>array('access_time'=>'1297831430000','num'=>'4')),
  array('name'=>'goods','data'=>array('access_time'=>'1297836785000','num'=>'2')),
  array('name'=>'member','data'=>array('access_time'=>'1297836785000','num'=>'2')),
  array('name'=>'liuyan','data'=>array('access_time'=>'1297836765000','num'=>'8')),
  array('name'=>'xiaohua','data'=>array('access_time'=>'1297836766000','num'=>'8')),
  array('name'=>'liuyan','data'=>array('access_time'=>'1297836765000','num'=>'8'))
);$c = array();
$out = array() ;
foreach($a as $k=>$v){
  $c[] = $a[$k]['name'] ;
}$b = array_unique ($c);
$d = array_diff_key($c,$b) ;
array_values($d);
$e = array_intersect($b,$d);foreach($b as $k=>$v){
  $out[$k]['name'] = $a[$k]['name'] ;
  $out[$k]['data']['access_time'] = $a[$k]['data']['access_time'] ;
  $out[$k]['data']['num'] = $a[$k]['data']['num'] ;
}foreach($e as $k=>$v){
  $sum = 0 ;
  foreach($a as $i=>$m){
    if($m['name']==$v){
      $sum += $m['data']['num'] ;
      
    }
  }
  $out[$k]['name'] = $v ;
  $out[$k]['data']['access_time'] = $a[$k]['data']['access_time'] ;
  $out[$k]['data']['num'] = $sum ;
}
$out = array_values($out);
print_r($out);