在客户端加一段js脚本~~~服务器端的防止简直就是徒劳,人家存心要重复发贴,你是挡不住的~把这段代码放在页面最后: <script language="javascript" src="submitonlyonce.js"></script> 代码submitonlyonce.js的内容: function doSubmitOnce(currentForm) { for(i=0;i<currentForm.length;i++) { var currentElement = currentForm.elements[i]; if(currentElement.type.toLowerCase() == "submit") currentElement.disabled = true; } } if(document.all||document.getElementById) { // Run through all forms on page for(i=0;i<document.forms.length;i++) { var currentForm = document.forms[i]; var oldEventCode = (currentForm.onsubmit) ? currentForm.onsubmit : function () {}; currentForm.onsubmit = function () {oldEventCode(); doSubmitOnce(currentForm)}; } }
用cookie保存在客户端该怎么写?有没有例子?
我刚开始学web编程。请多指教。
if (isset($_POST['emp_id']))
{
$expire = time()+60; //客户端cookie数据保存60秒
setcookie("emp_id",$_POST['emp_id'],$expire);
setcookie("emp_email",$_POST['emp_email'],$expire);
Header("location:".$_SERVER['PHP_SELF']);
}
?>
<html>
<body>
<form method="post" action="<?php echo $_SERVER['PHP_SELF'];?>">
<table border="0">
<tr>
<th align="right">Employee ID</th>
<td><input name="emp_id" type="text" maxlength="8" size="24" value="<?php echo $_COOKIE['emp_id'];?>">
</tr>
<tr>
<th align="right">Employee Email</th>
<td><input name="emp_email" type="text" maxlength="40" size="24" value="<?php echo $_COOKIE['emp_email'];?>">
</tr>
<td>
<input type="submit" name="submit" value="Add New Employee" />
</td>
</table>
</form>
<?php
if (isset($_COOKIE['emp_id']))
{
echo "上次提交数据:".$_COOKIE['emp_id']." ".$_COOKIE['emp_email'];
echo "<br>";
}
else
echo "您还没提交数据!<br>";
?>
</body>
<html>
<form>标签上加上 target="hidden"
处理页里最后一句后面加上
echo("<script>top.location="表单页名称或者你想要转到的任何页面"</script>");
这样用户看不到处理页 随便他怎么前进后退刷新都不会增加记录
<script language="javascript" src="submitonlyonce.js"></script>
代码submitonlyonce.js的内容:
function doSubmitOnce(currentForm)
{
for(i=0;i<currentForm.length;i++)
{
var currentElement = currentForm.elements[i];
if(currentElement.type.toLowerCase() == "submit")
currentElement.disabled = true;
}
}
if(document.all||document.getElementById)
{
// Run through all forms on page
for(i=0;i<document.forms.length;i++)
{
var currentForm = document.forms[i];
var oldEventCode = (currentForm.onsubmit) ? currentForm.onsubmit : function () {};
currentForm.onsubmit = function () {oldEventCode(); doSubmitOnce(currentForm)};
}
}